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RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3

February 8, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.3.

Board RBSE
Class Class 9
Subject Maths
Chapter Chapter 8
Chapter Name Construction of Triangles
Exercise Ex 8.3
Number of Questions Solved 3
Category RBSE Solutions

Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.3

Case III: To construct a triangle when a side and two angles are given.

Question 1.
Construct a triangle PQR when QR = 8 cm, ∠Q = 120° and ∠R = 30°
Solution.
Steps of construction:

  1. Draw line segment QR = 8 cm.
    RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3
  2. With Q as centre, draw an angle of 120°.
  3. Again with centre, draw an angle of 30° which intersects (RBSESolutions.com)the arms of angle 120° at P.
    Hence, ∆PQR is the required triangle.

RBSE Solutions

Question 2.
Construct a triangle ABC when b = 7 cm, ∠A = 90° and ∠C = 60°.
Solution.
Steps of construction:

  1. Draw line segment b = 7 cm as base.
    RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3
  2. Take A as centre, draw an angle of 90° by ruler and compass.
  3. Take C as centre and draw an angle of 60° by (RBSESolutions.com)ruler and compass which will meet the angle line at B.
  4. Join B to C.
    Hence, ∆ABC is the right-angled triangle.

Question 3.
Construct an isosceles triangle whose base is of length 4 cm and the vertex angle is equal to 30°. Draw a perpendicular from the vertex to the base.
Solution.
∵ Vertex angle = 30°
RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3
Steps of construction:

  1. Draw a line segment BC = 4 cm as base.
  2. With B as centre, draw an angle of 75°.
  3. With C as centre, also draw (RBSESolutions.com)an angle of 75° which intersects at A.
  4. Draw a perpendicular from the vertex A to the base BC.

Hence, ∆ABC is the required isosceles triangle whose base is 4 cm and vertex angle = 30°.

RBSE Solutions

We hope the given RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3 will help you. If you have any query regarding RBSE Rajasthan Board Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.3, drop a comment below and we will get back to you at the earliest.

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