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RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

April 6, 2026 by Prasanna Leave a Comment

Regular practice of RBSE Class 3 Maths Solutions and RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics Question Answer sharpens your problem-solving skills.

RBSE Class 3 Maths Chapter 15 Question Answer Operation of Vedic Mathematics

Operation of Vedic Mathematics Class 3 Questions and Answers

Operation of Vedic Mathematics Class 3 Question Answer – InText

Page 134
Let’s Practice-

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 1
Solution :
RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 2

Page 135

Let’s do-
RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 3
Solution :
RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 4

Page 136
Let’s do-

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 5
Solution :
RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 6

Page 137
Let us do-

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 7
Solution :
RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics 8

RBSE Class 3rd Maths Chapter 15 Question Answer – Exercise

Question 1.
Fill in the blanks with Ekadhiken numbers-
(i) 5 = 5 + 1 = 6
(ii) \(\dot{8}\) = _____
(iii) \(\dot{6}\) = _____
(iv) \(\dot{9}\) = _____
(v) \(\dot{2}\) = _____
Solution :
(ii) \(\dot{8}\) = 8 + 1 = 9
(iii) \(\dot{6}\) = 6 + 1 = 7
(iv) \(\dot{9}\) = 9 + 1 = 10
(v) \(\dot{2}\) = 2 + 1 = 3

Question 2.
Write the value of Ekadhiken Purvena number-
(i) 9 in 69 = 69 + 10 = 79
(ii) 8 in 78 = ______
(iii) 2 in 52 = ______
(iv) 4 in 34 = ______
(v) 8 in 183 = ______
Solution :
(ii) \(\dot{78}\) = 78 + 10 = 88
(iii) \(\dot{52}\) = 52 + 10 = 62
(iv) \(\dot{3}\) 4 = 34 + 10 = 44
(v) \(\dot{183}\) = 183 + 100 = 283

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

Question 3.
Fill in the blanks with Eknunen number-
(i) \(\stackrel{9}{\text {. }}\) = 9 – 1 = 8
(ii) \(\stackrel{6}{\text {. }}\) = ______
(iii) \(\stackrel{2}{\text {. }}\) = ______
(iv) \(\stackrel{8}{\text {. }}\) = ______
(v) \(\stackrel{7}{\text {. }}\) = ______
Solution :
(ii) \(\stackrel{6}{\text {. }}\) = 6 – 1 = 5
(iii) \(\stackrel{2}{\text {. }}\) = 2 – 1 = 1
(iv) \(\stackrel{8}{\text {. }}\) = 8 – 1 = 7
(v) \(\stackrel{7}{\text {. }}\) = 7 – 1 = 6

Question 4.
Write the value of Eknunen Purvena number-
(i) Digit 1 in \(\stackrel{81}{\text {. }}\) – 10 = 71
(ii) Digit 2 in \(\stackrel{32}{\text {. }}\) = ______
(iii) Digit 6 in \(\stackrel{96}{\text {. }}\) = ______
(iv) Digit 5 in \(\stackrel{75}{\text {. }}\) = ______
(v) Digit 0 in \(\stackrel{40}{\text {. }}\) = ______
Solution :
(ii) \(\stackrel{32}{\text {. }}\) = 32 – 10 = 22
(iii) \(\stackrel{96}{\text {. }}\) = 96 – 10 = 86
(iv) \(\stackrel{75}{\text {. }}\) = 75 – 10 = 65
(v) \(\stackrel{40}{\text {. }}\) = 40 – 10 = 30

RBSE Class 3 Maths Chapter 15 Operation of Vedic Mathematics Important Questions

Multiple Choice Questions-

Question 1.
What will be the Ekadhik number of 6?
(A) 5
(B) 7
(C) 9
(D) 4
Answer:
(B) 7

Question 2.
What will be the Eknunen number of 8?
(A) 7
(B) 9
(C) 5
(D) 2
Answer:
(A) 7

Question 3.
The number obtained from \(\dot{34}\) is-
(A) 24
(B) 35
(C) 33
(D) 44
Answer:
(D) 44

Question 4.
The number obtained from \(\stackrel{15}{\text {. }}\) is-
(A) 25
(B) 05
(C) 35
(D) 16
Answer:
(B) 05

Question 5.
The value of \(\dot{32}\) among the following will be-
(A) 33
(B) 31
(C) 23
(D) 42
Answer:
(A) 33

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

Question 6.
What will be the Eknunen number of 5?
(A) 6
(B) 7
(C) 15
(D) 4
Answer:
(D) 4

Fill in the blanks-

1. ______ is the root source of all knowledge.
Answer : Veda

2. A dot placed above a digit is called ______
Answer : Ekadhik

3. The dot placed below a digit is called ______
Answer : Eknunen

4. If one wants to perform Ekadhik of a digit in a number, a new number can be found by placing the ______ sign on that digit.
Answer : Ekadhik

5. If one wants to perform Eknunen of a digit in a number, a new number can be found by placing the ______ sign on that digit.
Answer : Eknunen

Write True/False for the following statements-

1. The dot placed above a digit is called the sign of Eknunen.
Answer : False

2. The dot placed below a digit is called the sign of Ekadhik.
Answer : False

3. Ekadhiken of 8 is 9.
Answer : True

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

4. Eknunen of 7 is 6.
Answer : True

Very Short Answer Type Questions

Question 1.
Find the Ekadhiken of the following numbers-
(i) \(\dot{5}\)
(ii) 1 \(\dot{6}\)
Solution :
(i) \(\dot{5}\) = 5 + 1 = 6
(ii) 16 = 16 + 1 = 17

Question 2.
Find the Ekanunen of the following numbers-
(i) \(\stackrel{8}{\text {. }}\)
(ii) \(\stackrel{6}{\text {. }}\)
Solution :
(i) 8 = 8 – 1 = 7
(ii) \(\stackrel{6}{\text {. }}\) = 6 – 1 = 5

Question 3.
Find the Ekadhiken Purven of the following numbers-
(i) 5 in 15
(ii) 4 in 64
Solution :
(i) 5 in 15 = \(\dot{15}\) = 25
(ii) 4 in 64 = \(\stackrel{64}{\text {. }}\) = 74

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

Question 4.
Find the Ekanunen Purven of the following numbers-
(i) 6 in 56
(ii) 3 in 63
Solution :
(i) 6 in 56 = \(\stackrel{56}{\text {. }}\) = 46
(ii) 3 in 63 = 63 = 53

Short Answer Type Questions-

Question 1.
Perform Ekadhiken on the following-
(i) \(\dot{1}\)
(ii) \(\dot{4}\)
(iii) \(\dot{7}\)
(iv) \(\dot{9}\)
(v) 1 \(\dot{2}\)
(vi) \(\dot{16}\)
(vii) \(\dot{59}\)
(viii) \(\dot{73}\)
Solution :
(i) \(\dot{1}\) = 1 + 1 = 2
(ii) \(\dot{4}\) = 4 + 1 = 5
(iii) \(\dot{7}\) = 7 + 1 = 8
(iv) \(\dot{9}\) = 9 + 1 = 10
(v) 1 \(\dot{2}\) = 13
(vi) \(\dot{16}\) = 26
(vii) \(\dot{59}\) = 69
(viii) \(\dot{73}\) = 83

Question 2.
Perform Ekanunen on the following-
(i) \(\stackrel{2}{\text {. }}\)
(ii) \(\stackrel{3}{\text {. }}\)
(iii) \(\stackrel{7}{\text {. }}\)
(iv) \(\stackrel{5}{\text {. }}\)
(v) \(\stackrel{11}{\text {. }}\)
(vi) \(\stackrel{17}{\text {. }}\)
(vii) \(\stackrel{24}{\text {. }}\)
(viii) \(\stackrel{51}{\text {. }}\)
Solution :
(i) \(\stackrel{2}{\text {. }}\) = 2 – 1 = 1
(ii) \(\stackrel{3}{\text {. }}\) = 3 – 1 = 2
(iii) \(\stackrel{7}{\text {. }}\) = 7 – 1 = 6
(iv) \(\stackrel{5}{\text {. }}\) = 5 – 1 = 4
(v) \(\stackrel{11}{\text {. }}\) = 10
(vi) \(\stackrel{17}{\text {. }}\) = 16
(vii) \(\stackrel{24}{\text {. }}\) = 14
(viii) \(\stackrel{51}{\text {. }}\) = 41

RBSE Class 3 Maths Chapter 15 Solutions Operation of Vedic Mathematics

Question 3.
Find the Ekadhiken Purven of the following numbers-
(i) 8 in 348
(ii) 6 in 986
(iii) 7 in 127
(iv) 5 in 725
Solution :
(i) \(\dot{348}\) = 358
(ii) \(\dot{986}\) = 996
(iii) \(\dot{127}\) = 137
(iv) \(\dot{725}\) = 735

Question 4.
Find the Ekanunen Purven of the following numbers-
(i) 3 in 93
(ii) 6 in 526
(iii) 9 in 296
(iv) 1 in 817
Solution :
(i) \(\stackrel{93}{\text {. }}\) = 83
(ii) \(\stackrel{526}{\text {. }}\) = 516
(iii) \(\stackrel{296}{\text {. }}\) = 196
(iv) \(\stackrel{817}{\text {. }}\) = 717

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