RBSE Class 3 Maths Chapter 5 Solutions Sweet Berries

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RBSE Class 3 Maths Chapter 5 Question Answer Sweet Berries

Sweet Berries Class 3 Questions and Answers

Sweet Berries Class 3 Question Answer – InText

Page 40

Question 1.
Will you tell, how much more is 53 than 17?
17 is ……. more than 10, first substract 10 from 53. Then how many left? Then substract 7 more, then _______ is left. Therefore 53 – 17 is _______.
Solution :
17 is 7 more than 10 , first substract 10 from 53. Then how many left? 43. Then substract 7 more, then 36 is left. Therefore 53-17 is 36.
Therefore, 53 is 36 more than 17.

Page 41

Question 1.
Solve the following questions using Lokesh’s method-
(i) 30 + 48

Solution :

(ii) 43 + 47

Solution :

(iii) 50 + 23

Solution :

Page 42

Question 1.
With the help of Beads chain, you also find out.

Solution :
First we will go till 52 on beads chain. Now 2 steps backward from 52, we will reach 50. Now we will go 10 steps backward from 50, We will reach 40. Then 3 steps backward from 40, we will reach 37. Therefore, 52 – 15 = 37

Page 42

Question 1.
Solve these on Number Line-
(i) 67 + 13
(ii) 44 – 26
(iii) 35 + 42
(iv) 72 – 3
Solution :
(i) 67 + 13
First we will go to 67 on the number line. Now to add 3 to 67 we will go 3 steps forward from 67 and reach 70. Now we will go 10 more steps forward from 70 and reach 80.
Hence, 67+13=80

(ii) 44 – 26
First we will reach 44 on number line. Now we will go back 6 steps and reach 38. Then we will go back the remaining 20 steps and reach 18.
Therefore, 44 – 26 = 18

(iii) 35 + 42
First we will go to 35 on the number line. Now we will go 40 steps forward to add 35 to 40 and reach 75. Now we will go forward for the remaining 2 steps and reach 77.
Hence, 35 + 42 = 77

(iv) 72-3
First we will go to 72 on the number line and then move back 3 steps to subtract 3. In this way we will reach 69.
Hence, 72 – 3 = 69

Page 48

Question 1.
Solve-

Solution :

Page 49

Question 1.
You also Add and Subtract on Number Line-

Solution :
(i) 465 + 266
First we will go to 465 on number line. Now to add 100, we will go 100 steps ahead and reach 565. Again to add 100, we will go 100 steps forward and reach 665. Now to add 66 we will go 66 steps forward and reach 731.
Thus, 465 + 266 = 731

(ii) 428-137
First we will go to 428 on number line. Now to subtract 100, we will go back 100 steps and reach 328. Now to subtract 37 we will go back 37 steps and reach 291.
Hence, 428 – 137 = 291

(iii) 247 + 441
247 + 441 = 688

(iv) 260 – 132
260 – 132 = 128

Question 2.
First make an estimate and then find the correct answer-

Solution :

	My estimate	Correct answer
272 + 146 =	More than 400	418
408 – 90 =	More than 300	318
505 – 324 =	Less than 200	181
604 + 199 =	More than 800	803

Page 51

Question 1.
Fill in the blank-

Solution :

Page 52

Question 1.
Match the Devanagari digits with International digits-

Solution :

Question 2.
1. Tick (✓) on the plate with zero laddoos.

Solution :

2. Satish had 4 toffees. He gave 2 toffees to Sonu and 2 toffees to Monu. Tell how many toffees are left with him?
Solution :
Satish had 4 toffees. If he gave 2 toffees to Sonu, then he was left with 2 toffees and now after giving 2 toffees to Monu, he was left with no toffees. That means zero was left.

3.
Solution :
Zero (0)

4. Udai had Rs. 10 He bought kulfi of Rs. 10 Now tell how much amount is left with him?
Solution :
Udai had 10 rupees, If he buys kulfi for 10 rupees then he will be left with nothing i.e. zero rupees.

RBSE Class 3rd Maths Chapter 5 Question Answer – Exercise

Question 1.
Write the number that comes just before –

Solution :

Question 2.
Write the number that comes just after—

Solution :

Question 3.
Arrange the given numbers in ascending order-

Solution :

Question 4.
Arrange the given numbers in descending order-

Solution :

Question 5.
Compare the given numbers and put appropriate sign <, >, =

Solution :

Question 6.
Solve

Solution :

Question 7.
Write the missing numbers

Solution :

RBSE Class 3 Maths Chapter 5 Sweet Berries Important Questions

Multiple Choice Questions-

Question 1.
The sum of 23 + 17 is-
(A) 42
(B) 40
(C) 44
(D) 38
Answer :
(B) 40

Question 2.
The value of 68-18 will be-
(A) 50
(B) 52
(C) 56
(D) 58
Answer :
(A) 50

Question 3.
The value of 272+188 is-
(A) 360
(B) 560
(C) 460
(D) 660 ( )
Answer :
(C) 460

Question 4.
How much should be added to 337 to get the answer 360?
(A) 23
(B) 27
(C) 29
(D) 32
Answer :
(A) 23

Question 5.
The difference between 56 and 33 will be-
(A) 27
(B) 26
(C) 22
(D) 23
Answer :
(D) 23

Question 6.
The value of 267 + 327 will be-
(A) 594
(B) 494
(C) 574
(D) 528
Answer :
(A) 594

Fill in the blanks-

1. The value of 19 + 31 will be _______.
Answer : 50

2. The value of 73 – 37 will be _______.
Answer : 36

3. Value of tens place in 539 = _______.
Answer : 3

4. The value of 239 – 79 = _______.
Answer : 160

5. The value of 135 + 275 = _______
Answer : 410

Write True/False for the following statements-

1. The units, tens and hundreds digits in 289 are 9,8 and 2 respectively.
Answer : True

2. To subtract 100 from 300, we have to move 100 steps forward on number line.
Answer : False

3. 45 is 19 more than 26.
Answer : True

4. 245 + 565 = 810
Answer : True

Very Short Answer Type Questions-

Question 1.
Solve the following by breaking numbers.
53 + 27
Solution :
53 + 27 = 50 + 3 + 20 + 7
= 70 + 7 + 3
= 70 + 10 = 80

Question 2.
Solve on number line-
67 – 17
Solution :
67 – 17 = 50

Question 3.
Solve on number line-
30 + 18
Solution :
30 + 18 = 48

Question 4.
There are 142 pomegranate trees and 235 mango trees in an orchard. How many trees are there in the orchard?
Solution :

Question 5.
86 runs are needed to win the match. Rohit scored 53 runs. How many more runs are needed to win the match?
Solution :
86-53

Question 6.
The price of an item is ₹ 78. You have ₹ 56. How much more money is needed to buy the item?
Solution :
78-56

So, To buy the item ₹ 22 more is needed.

Short Answer Type Questions-

Question 1.
Solve the following-
(i) 427 + 320
Solution :
(i)

(ii) 215 + 337
Solution :
(ii)

Question 2.
Solve the following
(a) 357 – 248
Solution :

(b) 605-108
Solution :

Question 3.
The population of a village in year 2025 is 850. If the population of the village in 2022 was 620. How much did the population increase in the last three years?
Solution :
Population in the year 2025 = 850
Population in the year 2022 = -620
Population increased = 230
Hence, the population of the village increased by 230 in the last three years.

Question 4.
Solve the following-
(i) 935 – 284
Solution :

(ii) 566 – 376
Solution :