RBSE Class 3 Maths Chapter 6 Solutions Decoration from Junk

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RBSE Class 3 Maths Chapter 6 Question Answer Decoration from Junk

Decoration from Junk Class 3 Questions and Answers

Decoration from Junk Class 3 Question Answer – InText

Page 54

Question 1.
Bhavya has made a hanging using bangles. Find out how many bangles are used in it?

Solution :
15 bangles are used in it.

Question 2.
Oh! Look at this hanging made of flowers and leaves?

How many flowers are there in one hanging? _____
How many flowers are there in two such hangings? _____
There are 3 green leaves with one flower. The entire hanging has _____ leaves and in two hangings _____ leaves are there.
Solution :
There are 18 flowers in one hanging. In two such hagings, total flowers are 2 × 18 = 36.
There are 3 green leaves with one flower. The entire hanging has 18 × 3 = 54 leaves and in two hangings, 54 × 2 = 108 leaves are there.

Page 55

Question 1.
Ravina, Sohan and Sejal also have to make this kind of a jeep. How many boxes will they need?
For three jeeps, we need _____ boxes.
Total how many lids will be needed?
Solution :
2 + 2 + 2 = 6 boxes. We can also say, that 2 boxes 3 times i.e. 2 × 3 = 6 boxes.
4 + 4 + 4 = 12 lids
4 lids 3 times = 4× 3 = 12 lids
So, 12 lids are needed to make 3 jeeps.

Question 2.
Tell, how many trees are there in this pomegranate garden?
4 + 4 + 4 + 4 + 4 + 4 = 24
_____ trees _____ times = _____ trees
_____ × _____ = _____ trees

Solution :

4 trees 6 times = 24 trees
4 × 6 = 24 trees

Page 56

Question 1.
Come lets us find out-
How many boxes of pomegranate are there?
_____ boxes _____ times = _____ boxes
_____ × _____ = _____ boxes

Solution :
5 boxes 5 times = 25 boxes
5 × 5 = 25 boxes

Question 2.
Raju has 3 leaves. Raju plucked 3 more leaves. Look, now how many leaves are there?
3 × 2 = 6 Leaves
Raju plucked few more leaves. Now total leaves-
_____ × _____ 12 leaves
Oh ! It is more the double of the previous one.
Solution :
6 × 2 = 12 leaves

Question 3.
Find out without counting-

One garland has 5 flowers. How many flowers will be there in 3 garlands?
_____ × 3 = _____
How many bananas are these in total?
4 × ____ = _____
Solution :
(i) Total flowers in 3 garlands
= 5 × 3 = 15 flowers

(ii) Total bananas = 4 × 4 = 16 bananas

Page 57

Question 1.
How many total beads will 2 garlands have?

Solution :
Total beads in 2 garlands
= 20 × 2 = 40 garlands

Question 2.
How many laddoos will fit in 7 boxes?

Solution :
Laddoos will fit in 7 boxes
= 4 × 7 = 28 laddoos

Question 3.
How many students will sit on 5 mats?

_____ × _____ = _____
Solution :
Students will sit on 5 mats
= 5 × 5 = 25

Page 58

Question 1.
Meena’s method- She keeps the match sticks horizontally and straight, and counts their crossing points.

Similarly make table of 6.
Solution :
Table of 6

Question 2.
Without multiplication, tell what will be the unit digit in these?
11 × 5, 12 × 5, 23 × 5, 14 × 5
Solution :
11 × 5 → Unit digit is 5
12 × 5 → Unit digit is 0
23 × 5 → Unit digit is 5
14 × 5 → Unit digit is 0

Question 3.
In the table of 9, add unit digit and tens digit and find out what do you get every time?
Solution :
Sum of unit and tens digits

Question 4.
Look at the table of 2, 3 and 5 given below. If we add the circled numbers, then which number will you get of table 5? Will it happen in the full table? Find out.

Solution :
2 + 3 = 5
4 + 6 = 10
6 + 9 = 15
8 + 12 = 20
Thus, we get the table of 5.

Question 5.
Observe the table of 10. Every time the unit digit is ‘0’. Multiply and tell—

Solution :
10 × 12 = 120
10 × 25 = 250
10 × 10 = 100
10 × 14 = 140
Every time the unit digit is 0.

Page 59

Question 1.
Come let us practice together-

(i) After jumping five times, on which number will you reach?
Solution :
After jumping five times we will reach on 20.

(ii) For reaching on 32, how many jumps will be needed?
Solution :
For reaching on 32, jumps will be needed = 8.

(iii) For reaching on 40, how many jumps will be needed?
Solution :
For reaching on 40, jumps will be needed = 10.

(iv) For reaching halfway on the Number Line, _____ jumps will be needed. The number will be _____
Solution :
For reaching halfway on the number line, 5 jumps will be needed. The number will be 20.

Question 2.
The cat still has to climb _____ more steps to reach the mouse.
Where will be the cat after 8 jumps?

Tell, will the cat be able to catch the mouse?
If the cat jumps up 3 stairs at a time, will it be able to catch the mouse?
Solution :
The cat still has to climb 12 more steps to reach the mouse.
After 8 jumps the cat will be :
2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16
8 × 2 = 16
Cat jumps up 2 stairs at a time, then it will not be able to catch the mouse.
If the cat jumps up 3 stairs at a time, it will be able to catch the mouse after 6 steps.

RBSE Class 3rd Maths Chapter 6 Question Answer – Exercise

Question 1.
If there are 8 biscuits in one packet, how many biscuits will be there in 4 such packets?
Solution :
Biscuits in one packet = 8
Biscuits in 4 such packets = 8 × 4
= 32 biscuits

Question 2.
One spider has 8 legs, then how many legs will 3 spiders have?
Solution :
One spider has legs = 8
∴ 3 spiders have legs = 8 × 3 = 24

Question 3.
How many wheels will 3 auto rickshaws have?
Solution :
Wheels in 1 auto rickshaw = 3
∴ Wheels in 3 auto rickshaws = 3 × 3
= 9

Question 4.
How many wheels are there in 5 bicycles?
Solution :
Wheels in 1 bicycle = 2
∴ Wheels in 5 bicycle = 2 × 5 = 10

Question 5.
How many legs will six cows have?
Solution :
1 cow has legs = 4
∴ 6 cows have legs = 4 × 6 = 24

Question 6.
How many bananas are there in 10 dozen?
Solution :
Bananas in 1 dozen = 12
∴ Bananas in 10 dozen = 10 × 12 = 120

Question 7.
Neha lit earthen lamps in her courtyardon Deepawali. Tell how many total lamps did she lit?

Solution :
Neha let total lamps 5 × 10 = 50 lamps.

Question 8.
Find out the total number of flowers?

Solution :
Total number of flowers = 3 × 6
= 18 flowers.

RBSE Class 3 Maths Chapter 6 Decoration from Junk Important Questions

Multiple Choice Questions-

Question 1.
4 × 3 can be written as-
(A) 4 × 4 × 4 × 4
(B) 4+3+4+3
(C) 4+4+4
(D) 4 × 3 × 4 × 3
Answer :
(C) 4 + 4 + 4

Question 2.
5 + 5 + 5 + 5 can be written as-
(A) 5 × 4
(B) 5 × 5
(C) 5 × 2
(D) 2 × 7
Answer :
(A) 5 × 4

Question 3.
The value of 2 × 7 is-
(A) 9
(B) 14
(C) 5
(D) 21
Answer :
(B) 14

Question 4.
Unit’s digit in 12 × 5 will be-
(A) 6
(B) 3
(C) 5
(D) 0
Answer :
(D) 0

Question 5.
Unit’s digit in 17 × 5 will be-
(A) 5
(B) 6
(C) 3
(D) 0
Answer :
(A) 5

Question 6.
Value of 4 × 9 is-
(A) 13
(B) 8
(C) 32
(D) 36
Answer :
(D) 36

Fill in the blanks-

1. 5 × _____ = 5 + 5 + 5
Answer: 3

2. The action of repeated addition, addition is called _____.
Answer: multiplication

3. Any number multiplied by _____ will give the same number.
Answer: 1

4. 7+7+7 can be written as 7 × _____.
Answer: 3

5. Unit’s digit in 10 × 5 will be _____.
Answer: 0

Write True/False for the following statements-

1. 5 + 5 + 5 can be written as 5 × 3.
Answer : True.

2. The unit’s place in 16 × 5 will be 5.
Answer : False

3. Multiplying any number by zero gives the same number.
Answer : False

4. 7 × 4 = 7 + 7 + 7 + 7
Answer : True.

Match the following-

Solution:

Very Short Answer Type Questions-

Question 1.
Write it in multiplication form and find its value-
(i) 4 times 3 = _____
(ii) 5 times 7 = _____
Solution :
(i) 4 times 3 = 4 × 3 = 12
(ii) 5 times 7 = 5 × 7 = 35

Question 2.
Fill in the box in the following questions-
(i) 4 + 4 + 4 = □
(ii) 3 times 5 = □
Solution :
(i) 4 + 4 + 4 = 12
(ii) 3 times 5 = 15

Question 3.
If there are 20 flowers in a garland then how many will be there in 2 such garlands?
Solution :
Flowers in 1 garland = 20
∴ Flowers in 2 garlands = 20 × 2
= 20 + 20 = 40

Question 4.
If there are 6 balls in a box, then what will be the total number of balls in the 4 boxes?
Solution :
Balls in 1 box = 6
∴ Balls in 4 boxes = 6 × 4 = 24

Question 5.
If there are 10 pencils in a packet, then how many pencils will be there in such 5 packets?
Solution :
Pencils in 1 packet = 10
Pencils in 5 packets = 10 × 5
= 10 + 10 + 10 + 10 + 10
= 50 pencils

Question 6.
If there are 4 plants in one bed, then how many plants will be there in 3 beds?
Solution :
Plants in 1 bed = 4
Plants in 3 beds = 4 × 3
= 4 + 4 + 4 = 12

Short Answer Type Questions-

Question 1.
If there are 3 flowers in one pot, then find the number of flowers in four pots.
Solution :
Flowers in each pot = [3]
Pots with 3 flowers = [4]
Therefore = 4 times 3
= 3 + 3 + 3 + 3
= 12 Flowers

Question 2.
Write tables-

Solution:

Question 3.
Solve the following-
(i) 4 times 7
Solution :
4 times 7 = 7+7+7+7

(ii) 8 times 5
Solution :
8 times 5 = 8 × 5 = 40

(iii) 3 + 3 + 3+ 3 + 3 + 3 = _____
6 times 3 = _____
6 × 3 = _____
Solution :
3 + 3 + 3 + 3 + 3 + 3 = 18
6 times 3 = 18
6 × 3 = 18

(iv) 9 + 9 + 9 = _____
3 times 9 =
3 × 9 =
Solution :
9 + 9 + 9 = 27
3 times 9 = 27
3 × 9 = 27