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RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

March 18, 2026 by Prasanna Leave a Comment

Regular practice of RBSE Class 4 Maths Solutions and RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise Question Answer sharpens your problem-solving skills.

RBSE Class 4 Maths Chapter 17 Question Answer Rupees Paise

Rupees Paise Class 4 Questions and Answers

Rupees Paise Class 4 Question Answer – InText

Page 129

Question 1.
Look at the rupee and write its value-
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 1
Solution :
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 2

Let’s Try

Question 2.
Make change for 20 rupees in 5 other ways with the help of coins-
______
______
Solution:

  1. 20 = 1 + 2 + 2 + 5 + 10
  2. 20 = 10 + 5 + 5
  3. 20 = 10 + 10
  4. 20 = 2 + 2 + 2 + 2 + 2 + 5 + 5
  5. 20 = 10 + 2 + 2 + 2 + 2 + 1 + 1

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

Page 130

Question 3.
If we have to change ₹ 500 with the help of notes then-
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 3
Solution :
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 4

Page 132
Let’s Solve

Question 4.
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 5
Solution :
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 6

Question 5.
40 children participated in a programme. Look at the pie chart given below and answer-
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 7
1. How many children are participating in dance?
(a) Half
(b) One fourth
(c) Three fourth
Solution:
(a) Half

2. The number of children participating in singing is ______
Solution:
One fourth = 10

3. The number of children participating in drama is ______ .
Solution:
One fourth = 10

4. Most of the children are participating in ______ .
Solution:
Dance

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

5. How many children are participating in drama?
(a) Half
(b) One fourth
(c) Three fourth
Solution:
(b) One fourth = 10

RBSE Class 4th Maths Chapter 17 Question Answer – Exercise

Question 1.
Devraj’s and Subham’s father gave 300 rupees 85 paise to Devraj and 450 rupees 50 paise to Shubham. How much money did the father give to both of them in total?
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 8
(∵ 1 Rupee =100 paise) Hence, Father gave 751 Rs. 35 paise to them.

Question 2.
Aditya had 2200 rupees 75 paise in his bank account. Out of that, 856 rupees 90 paise were deducted as installment, so how much money is left in his account now?
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 9
Hence, amount left in Aditya’s account is 1343 Rs. 85 paise.

Question 3.
If the cost of a dozen footballs is 5760 rupees, then what will be the cost of one football?
Solution:
Cost of 12 pcs of football = Rs. 5760 hence cost of 1 football = Rs. 5760 ÷ 12
= Rs. 480
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 10

Question 4.
Fill in the blanks of the given magic square puzzle-
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 11
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 12

Question 5.
Solve-
(i)
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 13
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 18

(ii)
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 14
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 19

(iii)
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 15
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 20

(iv)
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 16
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 21

(v) 23 Rupees 45 Paise × 7
Solution:
23 Rupees 45 Paise × 7
= 23 × 7 Rupee 45 × 7 Paise
= 161 Rupee 315 Paise
= 161 Rupee 300 Paise 15 Paise
= 161 Rupee 3 Rs 15 Paise
= 164 Rupee 15 Paise

(vi) 120 Rupees 17 Paise × 5
Solution:
120 Rupees 17 Paise × 5
= 120 × 5 Rupees 17 × 5 Paise
= 600 Rupees 85 Paise

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

Question 6.
Khushi went to the market to buy household items. She bought items from the shop and also calculated her bill by looking at the price list. Her grandmother gave her 4 notes of ₹500. Find out whether Khushi’s items will cost ₹ 2000 or not?
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 17
Solution:
RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise 22

(i) How much did Khushi buy and how much money did she have left?
Solution:
Khushi purchased items of 1080 Rs. her grandmother gave her 4 notes of ₹ 500 it means she was given 500 × 4 = ₹ 2000
The amount left with Khushi
= 2000-1080 = ₹ 920

(ii) Find out if Khushi is right? Write true or false and answer-
Solution:

(i) The combined price of ghee and flour is more than ₹ 500.
Solution: True

(ii) 1 kg ghee is ₹ 60 more expensive than 1 kg tea leaves.
Solution: False

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

(iii) The price of 3 kg sugar and 1 kg turmeric is the same.
Solution: True

(iv) The price of arhar dal is less than the price of urad dal.
Solution: True

(v) The price of sugar is less than turmeric.
Solution: True

RBSE Class 4 Maths Chapter 17 Rupees Paise Important Questions

Multiple Choice Questions-

Question 1.
The cost of 1 kg rice is ₹ 30, then cost of 5 kg will be-
(A) ₹ 180
(B) ₹ 200
(C) ₹ 150
(D) ₹ 100
Answer:
(C) ₹ 150

Question 2.
The cost of 1 litre oil is ₹ 140, the cost of 3 litre is-
(A) ₹ 300
(B) ₹ 280
(C) ₹ 360
(D) ₹ 420
Answer:
(D) ₹ 420

Question 3.
500 gram of turmeric cost ₹ 20, so 1 kg of turmeric cost is-
(A) ₹ 80
(B) ₹ 40
(C) ₹ 60
(D) ₹ 50
Answer:
(B) ₹ 40

Question 4.
Out of ₹ 500, ₹ 400 are spent, the remaining-
(A) ₹ 70
(B) ₹ 80
(C) ₹ 90
(D) ₹ 100
Answer:
(D) ₹ 100

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

Question 5.
Out of ₹ 600, ₹ 300 are spent, the remaining-
(A) ₹ 400
(B) ₹ 300
(C) ₹ 200
(D) ₹ 100
Answer:
(B) ₹ 300

Question 6.
1 kg flour cost ₹ 35, 4 kg cost-
(A) ₹ 130
(B) ₹ 160
(C) ₹ 140
(D) ₹ 120
Answer:
(C) ₹ 140

Question 7.
100 grams of coriander is available for ₹ 8, the price of 1 kg –
(A) ₹ 70
(B) ₹ 90
(C) ₹ 80
(D) ₹ 60
Answer:
(C) ₹ 80

Fill in the blanks-

1. The cost of 1 kg rice is ₹ 30, then the cost of 3 kg = ______
Answer: ₹ 90

2. The cost of 1 litre oil is ₹ 150, then the cost of 2 litre = ₹ ______
Answer: ₹ 300

3. 1 kg of turmeric cost ₹ 40, the cost of 5 kg turmeric = ₹ ______
Answer: ₹ 200

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

4. The cost of 2 kg of pulse at the rate of ₹ 80 / kg = ₹ ______
Answer: ₹ 160

5. Out of ₹ 400, ₹ 180 are spent, saving = ₹ ______
Answer: ₹ 220

Select True/False for the following statements-

(i) 100 paise = 1 Rs (True/False)
Answer: True

(ii) By spending ₹ 330 out of ₹ 500, a total is ₹ 270 is saved. (True/False)
Answer: False

(iii) The sum of ₹ 3465 Paise and ₹ 6515 Paise is ₹ 9980 Paise. (True/False)
Answer: True

(iv) Mohan had 1000 Rs. He bought goods worth Rs. 540, now he is left with Rs. 560 (True/False)
Answer: False

Very Short Answer Type Questions

Question 1.
Yasha bought 4 kg rice at the rate of 30 Rs / Kg; tell the total cost.
Solution:
₹ 30 × 4 = ₹ 120

Question 2.
250 gram of coriander is available for ₹ 10, what is the cost of 1 kg?
Solution:
₹ 10 × 4 = ₹ 40

Question 3.
1 litre oil is available for ₹ 150, how much will it cost for 3 litre?
Solution:
₹ 150 × 3 = ₹ 450

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

Question 4.
1 kg salt cost ₹ 20, what is the cost of 6 kg salt?
Solution:
₹ 20 × 6=₹ 120

Question 5.
500 gram turmeric is available for ₹ 18, what is the cost of 2 kg?
Solution:
₹ 18 × 4=₹ 72

Question 6.
1 kg of sugar cost ₹ 40, how much will I have to pay for 7 kg sugar?
Solution:
₹ 40 × 7 = ₹ 280

Short Answer Type Questions-

Question 1.
Sonu went to the market with ₹ 600.
He bought oil for ₹ 150; pulses for ₹ 100 and rice for ₹ 200. What is remaining amount?
Solution:
Total expenses = ₹ 150 + ₹ 100 + ₹ 200 = ₹ 450
Remaining amount = ₹ 600 – ₹ 450 = ₹ 150

Question 2.
250 gram of ginger is available for ₹12. Ravi has to buy 1 kg ginger. What is the total cost?
Solution:
1 kg = 4 × 250 gram
Cost = 4 × ₹ 12 = ₹ 48

Question 3.
1 kg of sugar is available for ₹ 45. What is the cost of 10 kg of sugar? Will 400 enough?
Solution:
₹ 45 × 10 = ₹ 450
No, ₹ 400 is not enough; ₹ 50 more is needed.

Question 4.
The cost of Rava is ₹ 40 per kg and the cost of sugar is ₹ 35 per kg. Kiran bought 3 kg of Rava (Samolina) and 2 kg of sugar. What is the total cost?
Solution:
Rava = ₹ 40 × 3 = ₹ 120
Sugar = ₹ 35 × 2 = ₹ 70
Total = ₹ 190

Long Answer Type and Essay Type Questions-

Question 1.
Meena went to a grocery shop and she bought following items :

Item Quantity
Wheat 2 Kg
Moong dal 1 Kg
Mustard oil 1 Litre
Turmeric 100 gram
Salt 1 Kg
Jaggery 500 gram

Rate List :
Wheat : ₹ 28 per kg
Moong dal : ₹ 90 per kg
Mustard oil : ₹ 140 per litre
Turmeric : ₹ 100 per kg
Salt : ₹ 20 per kg
Jaggery : ₹ 40 per kg

RBSE Class 4 Maths Chapter 17 Solutions Rupees Paise

If Meena has ₹ 300; will she be able to buy whole stuff? If yes, what will the remaining amount?
Solution:
Wheat = 2 × ₹ 28 = ₹ 56
Moong dal = ₹ 90
Mustard oil = ₹ 140
Turmeric = 100 gram =₹ 10
Salt = ₹ 20
Jaggery = 500 gram = 1 / 2 kg = ₹ 20
Total expenses = ₹ 56 + ₹ 90 + ₹ 140 + ₹ 10
+ ₹ 20+ ₹ 20= ₹ 336
No, Meena can not buy (purchase) whole stuff for ₹ 300. She needs ₹ 336-₹ 300 = ₹ 36 more.

Question 2.
Seema’s mother gave her ₹ 500 and asked to buy following stuff-
immmmmmmmmmm
Price List :
Rice : ₹ 32 per kg
Gram flour: ₹ 70 per kg
Rava : ₹ 40 per kg
Sugar : ₹ 38 per kg
Refined oil : ₹ 130 per litre
Coriander powder: ₹ 80 per kg
Will Seema be able to buy all stuff in ₹ 500 ?
Solution:
Rice = 3 × ₹ 32 = ₹ 96
Gram flour = ₹ 70
Rava = ₹ 40
Sugar = 2 × ₹ 38 = ₹ 76
Refined oil = ₹ 130
Coriander powder = 100 gram = 1 / 10 kg = ₹ 8
Total expenses = ₹ 96 + ₹ 70 + ₹ 40 + ₹ 76 + ₹ 130 + ₹ 8 = ₹ 420
Yes, Seema can buy whole stuff in ₹ 500 she will be left with ₹ 500-₹ 420 = ₹ 80.

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