Regular practice of RBSE Class 4 Maths Solutions and RBSE Class 4 Maths Chapter 19 Who Occupied How Much Space? Question Answer sharpens your problem-solving skills.
RBSE Class 4 Maths Chapter 19 Question Who Occupied How Much Space?
Who Occupied How Much Space? Class 4 Questions and Answers
Who Occupied How Much Space? Class 4 Question Answer – InText
Page 142
Let’s Solve
1. ______ matchboxes are required to cover the book completely.
Solution : 25
2. ______ matchboxes are required to cover the exercise book completely.
Solution : 16
3. How many less matchboxes are required to cover the notebook than the book?
Solution : 9
Pages 143-144
Let’s Solve Fill the table by counting boxes
Solution :
| S.No. | Figure | Occupied Block |
| 1. | Rectangle | 15 |
| 2. | Rectangle | 20 |
| 3. | Triangle | 15 |
| 4. | Rectangle | 28 |
The teacher told that each block is a square. Each block is 1 cm long and 1 cm wide, so the area of each block is equal to 1 square cm.
Fill in the blanks-
1. Figure 2 occupied ______ square cm of space.
Solution : 20
2. Figure 3 occupied ______ square cm of space.
Solution : 15
3. Figure 4 occupied ______ square cm of space.
Solution : 28
First Guess, Then Check-
1. How many books of the children of your class will cover the table?
Solution :
Do yourself.
2. How many bricks will be used to make a complete wall?
Solution :
8 × 10 = 80
Hence, 80 bricks will be used to make a complete wall.
Page 145
3. How many tiles are laid on the floor of the room?
Solution :
6 × 10 = 60
Hence, 60 tiles are used on the floor of the room.
Ant’s Race-
Raman : Hey! The ant could not find a way to get out of the leaf. I will take it off the leaf with the help of a straw.
Jyoti : The poor ant got tired of running but how much did the ant run in one go? Let’s measure.
How will you measure?
Other : Let’s measure with the help of thread and inch tape.
The ant ran 30 centimetres in one go.
Let’s Solve
1. How many centimetres did the ant run in 3 times? ______
Solution :
3 × 30 cm = 90 cm
2. How many centimetres did the ant run in 4 times? ______
Solution :
4 × 30 cm = 120 cm
3. How many rounds did the ant take in a race of 150 centimetres? ______
Solution :
150 cm ÷ 30 = 5 Rounds
4. How many rounds did the ant take in a 3 metre race? ______
Solution :
3 meter = 3 × 100 cm = 300 cm then 300 cm ÷ 30 cm = 10 Rounds.
Page 146
Let’s Discuss
Ravi has sown gram in his field. He has to guard his field every night from animals like Nilgai. He has built a hut from where he can see his field from all sides. He walks around his field three times at night. He makes sure that no animal enters his field.
1. What is the total length of the fence around Ravi’s field? ______
Solution :
150 meter + 56 meter + 56 meter + 150 meter + 180 meter = 592 meter
2. Ravi walks ______ than 1 kilometre every day to protect his crop. More/Less
Solution :
Ravi takes 3 rounds; so
3 × 592 meter = 1776 meter
Ravi walks 1776 meters which is more than 1000 meters or 1 km.
3. How many meters will Ravi walk in two days to protect his crop? ______
(Ravi’s Field)
Solution :
Ravi walks in 2 days
2 × 1776 meter = 3552 meter
Pages 146-148
Let’s Solve
Question 1.
Describe the total length of the fence of the figures given below-
Figure (1) – Total length of the fence = ______ meter
Figure (2) – Total length of the fence = ______ meter
Figure (3) – Total length of the fence = ______ meter
Solution :
(1) 450 cm = 4 meter 50 cm = 4.50 meter
(2) 1200 cm = 12 meter
(3) 910 cm = 9 meter 10 cm = 9.10 meter
Question 2.
Estimate the total area of the figures given on the grid-
Solution :
Figure (1)-Total area of circle = 6 square unit
Figure (2)-Total area of circle = 7 square unit
Figure (3)-Total area of circle = 7 square unit
Figure (4)-Total area of circle = 4 square unit
Question 3.
Raman is making different figures from 5 square-shaped tiles
(tiles are 1 × 1 meter)
Which figure has the highest perimeter? ______
Which figure has the lowest perimeter? ______
Solution :
| Figure | Perimeter |
| (i) | 12 meter |
| (ii) | 12 meter |
| (iii) | 12 meter |
| (iv) | 12 meter |
Perimeter of all figures are same.
Question 4.
Make different shapes with these square tiles with your friends-
How many different shapes have you made? ______
The highest perimeter is = ______ cm.
The lowest perimeter is = ______ cm.
Area of all shapes is ______ (equal/unequl)
Solution :
Do yourself.
Question 5.
Aarti’s mother wants to get lace stitched around her dupatta. The length of the dupatta is 2 meters and the width is 1 meter.
(i) How much lace will Aarti buy from the shopkeeper for the dupatta? ______
Solution :
Perimeter of dupatta
= 2(length + breadth)
= 2(2 meter +1 meter)
= 2 × 3 meter
= 6 meter
Hence, Aarti will buy 6 meter long lace for dupatta.
(ii) The shopkeeper said that the lace is 80 rupees per meter. Aarti buys half a meter extra. Tell how much money will she pay to the shopkeeper? ______
Solution :
Aarti will have to pay for 6 meter
= 80 × 6=₹ 480
For half meter more lace
= 80 × \(\frac{1}{2}\) = ₹ 40
Aarti will give a sum of = ₹ 480 + ₹ 40 = ₹ 520 to shopkeeper.
Question 6.
Anurag is preparing to join the army. Every morning he goes for a run in the garden near his house, which is 500 meters long and 300 meters wide.
(i) Anurag takes 5 rounds of the garden while running. He runs ______ kilometer every day.
Solution :
Anurag runs in a round
= 2(length + breadth)
= 2(500 + 300) meter
= 1600 meter
= 1 km 600 meter
on taking5 Rounds = 5 × 1600 meter
= 8000 meter
= 8 km
(∵ 1000 meter = 1 km)
(ii) Anurag runs ______ kilometer in 1 round.
Solution :
Anurag runs 1600 meter or 1 km 600 meter in one round.
(iii) Anurag took 2 rounds. Halfway through the third round, his father called him. Today he ran ______ meter.
Solution :
2 and half rounds
= 2 × 1600 meter + \(\frac{1}{2}\) × 1600 meter
= 3200 meter +800 meter
= 4000 meter
= 4 km
(iv) How many meter less did Anurag run today than he did every day? ______
Solution :
Today Anurag runs 8000 meter – 4000 meter = 4000 meter less.
Page 148
Let’s try
Look, Raman has drawn a figure on the dot paper given below.
You too draw two other figures whose perimeter is the same.
Make such figures whose area is equal to the given figure.
Solution :
Preimeter of given figure = 12 cm
Area of given figure = 5 square cm
(i) Perimeters of figure (i) and (ii) are (equal) same as perimeter of given figure 12 cm.
(ii) Areas of figure (iii) (iv) are equal as area of given figure 5 square cm.
RBSE Class 4th Maths Chapter 19 Question Answer – Exercise
Question 1.
An irregularly shaped leaf is placed on a square grid. If the number of boxes completely occupied by the leaf is 16 , the number of boxes occupied more than half is 4 and the number of boxes occupied less than half is also 4 , then the approximate area of the leaf is-
(a) 16 square units
(b) 18 square units
(c) 20 square units
(d) 28 square units
Solution :
(c) 20 square units
Question 2.
A rectangle is made up of square boxes. It has 5 boxes in a row and 2 boxes in a column. The area of the rectangle is-
(a) 7 square units
(b) 10 square units
(c) 12 square units
(d) 14 square units
Solution :
(b) 10 square units
Question 3.
Riya coloured some boxes of a square shaped paper to make a picture, if the coloured part is in the shape of a square and its area is 4 square units, then the side of this square is-
(a) 4 square units
(b) 16 square units
(c) 4 units
(d) 2 units
Solution :
(d) 2 units
Question 4.
Find the area of the shaded part of the figures given below by counting the square boxes-
(i) Area = ______ square unit
Solution :
25 square units
(ii) Area = ______ square unit
Solution :
18 square units
Question 5.
Estimate the area of the figures shown in the square grid-
Area = ______ square unit Area = ______ square unit
Solution :
(i) 18 square units
(ii) 13 square units
RBSE Class 4 Maths Chapter 19 Who Occupied How Much Space? Important Questions
Multiple Choice Questions
Question 1.
Amount of space occupied on a checkered paper by any figure is found out-
(A) by drawing a sketch of figure on checkered paper
(B) by cutting checkered paper similar to the shape of the object
(C) by counting the number of squares occupied by object
(D) all of the above
Answer:
(C) by counting the number of squares occupied by object
Question 2.
If spread on the ground, which of the following would occupy more space?
(A) Book
(B) Classroom floor
(C) Carpet
(D) Chalk box
Answer:
(B) Classroom floor
Question 3.
Which of the following occupies maximum space?
(A)
(B)
(C)
(D)
Answer:
(B)
Question 4.
Outer (External) measurement around a shape is called-
(A) Area
(B) Perimeter
(C) Volume
(D) None of the above
Answer:
(B) Perimeter
Question 5.
Perimeter of following shape 
of side 2 cm is-
(A) 4 cm
(B) 3 cm 2 cm
(C) 8 cm
(D) 5 cm
Answer:
(C) 8 cm
Fill in the blanks
1. In the method of finding the approximate area by counting the squares on the grid paper, which are ______ than half filled are left out.
Answer: less
2. The amount of space occupied by an object on a plane is termed as the ______ of that object.
Answer: area
3. The leangth of a rectangular field is 20 meters and width is 40 meters then perimeter of that field is ______.
Answer: 120 meter
4. The length of side of a square is 12 cm then its area is ______ square unit.
Answer: 144
Select True/False for the following statements-
(i) The measurement around any shape is called its measurement. (True/False)
Solution : True
(ii) The lengths of sides of a polygon are 10 cm, 15 cm, 12 cm and 14 cm, then perimeter of that polygon is 40 cm. (True/False)
Solution : False
(iii) The perimeter of a field is 500 meter. By taking six rounds of the field, a person covers a distance of 7 km. (True/False)
Solution : False
(iv) The length of wall around a pond is half Km. Shyam took four rounds of the pond. He covered 2 Km distance. (True/False)
Solution : True
Very Short Answer Type Questions
Question 1.
In a school programme, 35 children could sit on first floor and 28 children on second floor. Tell, which floor occupies more space?
Solution :
The floor, on which 35 children are sitting, occupies more space because that floor is bigger.
Question 2.
the length of a small book is 6 cm and breadth is 5 cm, so tell how many squars will book occupies when it is placed on a checkered paper of area 1 square cm?
Solution :
That book occupies 6 × 5 = 30 blocks on a checkered paper of 1 square cm.
Question 3.
Write the numbers of square blocks occupied by this figure.
Solution :
8 complete and 8 half blocks.
Question 4.
Calculate the perimeter of field given below.
Solution :
Perimeter of field
= 100 meter + 110 meter + 90 meter + 80 meter +30 meter
= 410 meter
Short Answer Type Questions
Question 1.
These are some different stickers, find out which sticker is occupying how many squares.
Make this table in your copy and fill it up
| Sticker | Occupied blocks |
| 1 | 21 |
| 2 | |
| 3 | |
| 4 | |
| 5 |
Solution :
| Sticker | Occupied blocks |
| 1 | 21 |
| 2 | 25 |
| 3 | 10 complete and 5 half |
| 4 | 24 complete and 8 half |
| 5 | 6 complete and 4 half |
Question 2.
(i) Make a same grid in your notebook or take a maths notebooks. Make different shapes on the grid by joining three one cm squares and find their perimeter.
Solution :
(ii) Do these shapes occupy equal space on the checkered paper?
Solution :
No, these figures don’t occupy equal.
(iii) Now do the same with the four squares.
Solution :
Long Answer Type and Essay Type Questions
Question 1.
Draw the following shapes on a checkered paper of your maths notebook with the help of scale and find out shapes enclosed by them-
(i) The length of a rectangle is 5 cm and width is 3 cm then the space enclosed by rectangle is equal to how many squares?
Solution :
(ii) Draw a square of side 3 cm and find the space occupied by it in the box.
Solution :
(i) The space enclosed by the rectangle will be equal to 15 squares.
(ii) The value of space occupied by the square on a square is equal to 9 squares.
Question 2.
Some shape are drawn on checkered paper given below. Calculate their areas-
Solution :
(i) Value of complete blocks = 4
Value of more than half blocks = 4
Total area = 4 + 4
= 8 blocks
(ii) Value of complete blocks = 7
Area = 7 blocks
(iii) Value of complete blocks = 5 blocks
(iv) Value of complete blocks = 6
Value of more than half blocks = 4
Total area = 6 + 4
= 10 blocks
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