RBSE Class 4 Maths Chapter 7 Solutions Car Parking

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RBSE Class 4 Maths Chapter 7 Question Answer Car Parking

Car Parking Class 4 Questions and Answers

Car Parking Class 4 Question Answer – InText

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Let’s Try

Multiply in the same way :
(i) 48 × 36
Solution:

(ii) 38 × 67
Solution:

(iii) 96 × 84
Solution:

(iv) 198 × 27
Solution:

RBSE Class 4th Maths Chapter 7 Question Answer – Exercise

Question 1.
Fill in the blanks :

Solution:
(i) 4 × 1 = [4]
(ii) 5 × 10 = [50]
(iii) 7 × 100 = [700]
(iv) 8 × 1000 = [8000]
(v) 180 × 0 = [0]
(vi) 10 × 100 = [1000]
(vii) 15 × [100] = 1500
(viii) 14 × [10] = 140
(ix) [18] × 100 = 1800
(x) [66] × 10 = 660

Question 2.
Multiply :
(i) 23 × 45 = _____.
(ii) 81 × 73 = _____.
(iii) 67 × 89 = _____.
(iv) 92 × 56 = _____.
(v) 38 × 112 = _____.
(vi) 23 × 299 = _____.
(vii) 49 × 76 = _____.
(viii) 44 × 102 = _____.
(ix) 25 × 248 = _____.
(x) 58 × 87 = _____.
Solution:
(i) 23 × 45 =
Solution:

(ii) 81 × 73 =
Solution:

(iii) 67 × 89 =
Solution:

(iv) 92 × 56 =
Solution:

(v) 38 × 112 =
Solution:

(vi) 23 × 299 =
Solution:

(vii) 49 × 76 =
Solution:

(viii) 44 × 102 =
Solution:

(ix) 25 × 248 =
Solution:

(x) 58 × 87 =
Solution:

Question 3.
The cost of one copy is ₹ 15. What will be the cost of 9 copies?
Solution :
Cost of one copy = ₹ 15
Cost of 9 copies = ₹ 15 × 9 = ₹ 135
Hence, cost of 9 copies is ₹ 135.

Question 4.
One packet contains 75 pencils.
How many pencils will there be in 19 such packets?
Solution :
Pencils in one packet = 75 pencils
Pencils in 19
packets = 75 × 19
= 1425 pencils
Hence, pencils in 19 packets is 1425.

Question 5.
There are 79 beads in a garland. How many beads will there be in 68 such garlands?
Solution :Beads in one garland = 79
Beads in 68 garlands = 79 × 68
= 5372 beads
hence, there will be 5372 beads in 68 garladns.

Question 6.
The cost of small bicycle is ₹ 1560.
What will be the cost of 6such bicycles?
Solution :
Cost of one bicycle = ₹ 1560
Cost of 6 bicycles = ₹ 1560 × 6
= ₹ 9360
hence, cost of 6 such bicycles is ₹ 9360.

Question 7.
If a cricket team has 11 players, how many players will there be in total in 12 teams?
Solution :
Players in one team = 11
Players in 12 teams = 11 × 12
= 132
hence, total 132 players will be there in 12 teams.

Question 8.
One box contains 1440 soap bars. How many soap bars will there be in 6 boxes?
Solution :
Number of soap bars in one box
= 1440
Number of soap bars in 6 boxes = 1440 × 6
= 8640 bars
hence, in 6 boxes, there are 8640 soap bars.

Question 9.
A family uses 12 kg of rice, 15 kg of flour, and 6 liters of oil every month. The price of rice is ₹ 45 per kg, flour is ₹ 30 per kg, and oil is ₹ 120 per litre. What is the family’s total monthly grocery expense?
Solution :
Cost of 1 kg Rice = ₹ 45
Cost of 12 kg Rice = 45 × 12 = ₹ 540
Cost of 1 kg flour = ₹ 30
Cost of 15 kg flour = 30 × 15 = ₹ 450
Cost of 1 litre Oil = ₹ 120
Cost of 6 litre Oil = 120 × 6 = ₹ 720
hence, family’s total monthly grocery expenses are ₹ 1710.

Question 10.
In a school in Barmer, each student is given 4 pens, 2 notebooks, and 1 eraser. The cost of a pen is ₹ 10, a notebook is ₹ 35, and an eraser is 5. If there are 25 students in the class, what will be the total cost of the material?
Solution :
Cost of 1 Pen= ₹ 10
Cost of 4 Pens = 10 × 4 = ₹ 40
Cost of 1 notebook = ₹ 35
Cost of 2 notebook = 35 × 2 = ₹ 70
Cost of an eraser = ₹ 5
Cost of 4 Pens, 2 notebooks and one eraser
= 40+70+5
= ₹ 115
Total students = 25
Total Expenses = 115 × 25 = ₹ 2875
hence, total cost of material = ₹ 2875

RBSE Class 4 Maths Chapter 7 Car Parking Important Questions

Multiple Choice Questions :

Question 1.
Value of 100 × 0 is :
(a) 100
(b) 1000
(c) 10
(d) 0
Answer:
(d) 0

Question 2.
If 6 children study sitting at a long table in a class, then the total number of children sitting at 9 such tables will be :
(a) 54
(b) 45
(c) 63
(d) 56
Answer:
(a) 54

Question 3.
There are 12 horizontal rows and 19 vertical rows of Rasmalai in a sweet box. Find the number of Rasmalai in the box.
(a) 128
(b) 228
(c) 328
(d) 238
Answer:
(b) 228

Question 4.
Solve 674 × 16 :
(a) 8784
(b) 9784
(c) 10784
(d) 11784
Answer:
(c) 10784

Question 5.
The value of 100 × 999 is :
(a) 0
(b) 999
(c) 9990
(d) 99900
Answer:
(d) 99900

Fill in the blanks :

1. If one spider has 8 legs then the number of legs of 22 spiders ______.
Answer: 176

2. If one bucket contains 25 litres of water, then 26 such buckets will contain ______ water.
Answer: 650 litres

3. 89 × 99 = ______.
Answer: 8811

4. 9999 × ______ = 9999
Answer: 1

5. 10000 × ______ = 0
Answer: 0

Select True/False for the following statements :

(i) 10 × 12 = 12 × 10 (True/False)
Answer: True

(ii) A person drives a car at a uniform speed of 50 km in 1 hour. Then in 5 hours he will cover a distance of 300 km at the same speed. (True/False)
Answer: False

(iii) Multiplying 1 (one) by any digit. The same number is obtained. (True/False)
Answer: True

(iv) On multiplying a number by 100, two zeroes are added at extreme right side of number. (True/False)
Answer: True

Very Short Answer Type Questions :

Question 1.
The cost of one chalk box is ₹ 15. Mahendra has to buy 45 boxes. How much money he should have?
Solution :
Price of one chalk box = ₹ 15
Price of 45 chalk boxes = 15 × 45 = ₹ 675 hence, Mahendra must have ₹ 675.

Question 2.
Yash want needs 751 lamps on Diwali. If the price of one lamp is ₹ 13. How much money does he need to buy the lamps?
Solution :
Price of one lamp = ₹ 13
Price of 751 lamps = 13 × 751 = ₹9763
hence, Yash want needs ₹ 9763 to buy lamps.

Question 3.
In a car factory, 395 cars are manufactured every month, then how many cars will be manufactured in a year?
Solution :
Cars manufactured in one month
= 395
Cars manufactured in one year = 395 × 12
= 4740 cars hence, 4740 cars will be manufactured in a year.

Question 4.
If price of one fridge is ₹ 3105. What will be price of 17 fridges?
Solution :
Price of one fridge = ₹ 3105
Price of 17 fridges = 3105 × 17
= ₹ 52,785
hence, cost of 17 fridges will be ₹ 52,785.

Question 5.
There are 45 bottles in a carton, then how many bottles will be there in 65 cartons?
Solution :
Bottles in one carton = 45
Bottles in 65 cartons = 45 × 65
= 2925 bottles
hence, there will be 2925 bottles in one carton.

Question 6.
Multiply 81 × 111.
Solution :

Short Answer Type Questions :

Question 1.
A person monthly saving is ₹ 1855.
Then find his yearly savings.
Solution :
Monthly savings = ₹ 1855
Yearly (12 months) savings = ₹ 1855 × 12
= ₹ 22,260
hence, his yearly saving is ₹ 22,260 .

Question 2.
The population of village is 998 . If the state government gives a subsidy of ₹ 55 per person for the development of village. Then find the total amount of subsidy.
Solution :
Subsidy for one person = ₹ 55
Subsidy for 998 person = ₹ 55 × 998
= ₹ 54,890
hence, the total amount of subsidy is ₹ 54,890.

Question 3.
Find the product of smallest two digit number by largest two digit number.
Solution :
Smallest two digit number = 10
Greatest two digit number = 99
Required product = 99 × 10
= 990

Question 4.
The price of one set of class IV books is ₹ 650. Then what will be the price of 32 sets?
Solution :
Cost of one set of book = ₹ 650
Cost of 32 sets = 650 × 32
= 20,800
hence, cost of 32 sets of books is ₹ 20800.

Long Answer Type and Essay Type Questions :

Question 1.
Mahesh bought 5 balls and 8 bats. If the price of one ball is ₹ 35 and the price of one bat is ₹ 375. Then how much money did Mahesh pay to the shopkeeper?
Solution :
Cost of 1 ball = ₹ 35
Cost of 5 balls = ₹ 35 × 5 = ₹ 175
Cost of 1 bat = ₹ 375
Cost of 8 bats = ₹ 375 × 8 = ₹ 3000
Cost of 5 balls and 8 bats = 175+3000
= ₹ 3175
Hence, Mahesh paid ₹ 3175 to the shopkeeper.

Question 2.
Find the values of the following :

(i) 81 × 74
Solution:

(ii) 111 × 21
Solution: