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RBSE Class 4 Maths Chapter 9 Question Answer Vedic Mathematics
Vedic Mathematics Class 4 Questions and Answers
Vedic Mathematics Class 4 Question Answer – InText
Page 66
Write the Ekadhikena Purvena of the following numbers :
Solution :
Page 67
Now it’s your turn
(i)
Solution :
Steps :
1. Sum of unit digits : 8 + 6 = 14. The sum is greater than 10
2. Therefore, we write 4 in the sum and make the Ekadhikena purvena of digit 6 as \(\dot{5}\).
3. Sum of tens digits : 6 + \(\dot{5}\) = 6 + 6 = 12. Therefore, write 2 in the sum and make the Ekadhikena purvena of 5 as \(\dot{3}\).
4. Sum of hundreds digit : 2 + \(\dot{3}\) = 2 + 4 = 6. Write 6.
(ii)
Solution :
Steps :
1. Sum of unit digits : 5 + 4 + 8 = 17
2. Sum is greater than 10, therefore we write 7 in the sum and make the ekadhikena purvena of digit 8 as 5.
3. Sum of tens digit : 7 + 7 = 14 which is more than 10.
Therefore make the ekadhika purvena of 7 as \(\dot{2}\).
Now 4 + \(\dot{5}\) = 4 + 6 = 10.
So, write 0 in the sum and make ekadhikena purvena of 5 as \(\dot{3}\).
4. Sum of hundreds digits : 1 + \(\dot{2}\) + \(\dot{3}\) = 1 + 3 + 4 = 8. Write 8.
(iii)
Solution :
Steps :
1. Sum of unit digits : 7 + 4 + 8 = 19
2. Sum is greater than 10. Therefore write 9 in the sum and place the ekadhikena sign on the digit 2 (the digit before 8).
3. Sum of tens digits : 7 + 7 + \(\dot{2}\) = 17.
Therefore write 7 in the sum and place the ekadhikena sign on the digit 3 (the digit before 2)
4. Sum of hundreds digits : 4 + 2 + \(\dot{3}\) = 4 + 2 + 4 = 10. Write 10.
(iv)
Solution :
Steps :
1. Sum of unit digits : 5 + 5 + 8 = 18
2. The sum is greater than 10, therefore write 8 in the sum and place the ekadhikena sign on digit 5 (the digit before 8).
3. Sum of tens digits : 7 + 6 + \(\dot{5}\) = 19.
Therefore write 9 in the sum and place the ekadhikena sign on digit 3 (the digit before 5).
4. Sum of hundreds digits : 3 + 2 + \(\dot{3}\) = 3 + 2 + 4 = 9. Write 9.
Page 68
Write the Eka Nyuna Purvena of the following numbers :
Solution :
Page 69
Let’s Solve
Solution :
Steps :
1. 9 cannot be subtracted from 7, so add the Param Mitra Ank of 9 (which is 1) to 7. (7 + 1 = 8)
2. Make the Ekanyunena purvena of digit 7 as 1.
3. Similarly 6 cannot be subtracted from 1 (i.e. 0) so add the Param Mitra Ank of 6 (which is 4 ) is 0. (0 + 4 = 4)
4. Make the Ekanyunena purvena of 1 as 8.
5. Subtract 2 from 8 (i.e. 7) and write 5.
(ii)
Solution :
Steps :
1. 8 cannot be subtracted from 5, so add the Param Mitra Ank of 8 (which is 2) to 5. (5 + 2 = 7)
2. Make the Ekanyunena purvena of digit 5 as 3.
3. Similarly, 4 cannot be subtracted from 3. (i.e. 2) so add the Param Mitra Ank of 4 (which is 6) to 2. (2 + 6 = 8)
4. Make the Ekanyunena Purvena of 3 as ?
5. Subtract 4 from 7 (i.e. 6) and write 2.
(iii)
Solution :
Steps :
1. 7 cannot be subtracted from 5, so add the Param Mitra Ank of 7 (which is 3) to 5. (5 + 3 = 8)
2. Make Ekanyunena purvena of 5 as 4.
3. Similarly 5 cannot be subtracted from 4 (i.e. 3) so add Param Mitra Ank of 5 (which is 5) to 4. (3 + 5 = 8)
4. Make Ekanyunena purvena of 4 as 9.
5. Subtract 2 from 9 (i.e. 8) and write 6.
(iv)
Solution :
Steps :
1. 9 cannot be subtracted from 2, so add the Param Mitra Ank of 9 (which is 1) to 2. (2 + 1 = 3)
2. Make Ekanyunena purvena of 2 as 1.
3. Similarly 9 cannot be subtracted from 1 (i.e. 0), so add the Param Mitra Ank of 9 (which is 1) to 0. (0 + 1 = 1)
4. Make Ekanyunena purvena of 1 as 6.
5. Subtract 1 from 6 (i.e. 5) and write 4.
RBSE Class 4th Maths Chapter 9 Question Answer – Exercise
Question 1.
Fill in the blanks :
Solution:
Question 2.
Fill in the blanks :
Solution:
Question 3.
Fill in the blanks :
Solution:
(i) Param Mitra Ank of 2 = 8(2 + 8 = 10)
(ii) Param Mitra Ank of 9 = 1(9 + 1 = 10)
(iii) Param Mitra Ank of 5 = 5(5 + 5 = 10)
(iv) Param Mitra Ank of 6 = 4(6 + 4 = 10)
Question 4.
Find the sum using the Vedic Mathematical Method (Ekadhikena Purvena) :
(i)
Solution :
Steps :
1. Sum of unit digits : 6 + 7 = 13
2. Sum is greater than 10 , therefore write 3 in the sum and make Ekadhikena purvena of digit 7 as \(\dot{2}\).
3. Sum of tens digits : 2 + \(\dot{2}\) = 2 + 3 = 5. Write 5.
4. Sum of hundreds digits : 4 + 1 = 5. Write 5.
(ii)
Solution :
Steps :
1. Sum of unit digits : 3 + 7 = 10
2. Sum is 10, write 0 in sum and make Ekadhikena purvena of digit 7 as \(\dot{4}\).
3. Sum of hundreds digits : 6 + \(\dot{4}\) = 6 + 5 = 11, therefore write 1 in sum and make Ekadhikena purvena of 4 as \(\dot{4}\).
4. Sum of hundreds digit : 5 + \(\dot{4}\) = 5 + 5 = 10, write 10.
(iii)
Solution :
Steps :
1. Sum of unit digits : 8 + 3 = 11
2. Sum is greater than 10 , therefore write 1 in sum and make Ekadhikena purvena of digit 3 as \(\dot{6}\).
3. Sum of tens digits : 3 + \(\dot{6}\) = 3 + 7 = 10, therefore write 0 in sum and make Ekadhikena purvena of digit 6 as \(\dot{8}\).
4. Sum of hundrends digit : 5 + \(\dot{8}\) = 5 + 9 = 14, write 14.
(iv)
Solution :
Steps :
1. Sum of unit digits : 8 + 2 = 10
2. Sum is 10 , therefore write 0 in sum and make Ekadhikena purvena of 2 as i.
3. Sum of tens digits : 3 + i = 3 + 2 = 5, write 5.
4. Sum of hundreds digits : 2 + 7 = 9, write 9.
Question 5.
Perform subtraction using the Vedic Mathematical Method (Eka Nyunena Purvena) :
(i)
Solution :
Steps :
1. 8 cannot be subtracted from 7, so add the Param mitra digit of 8 (which is 2) to 7. (7 + 2 = 9)
2. Make the ekanyunena purvena of digit 7 as 8.
3. Similarly 9 cannot be subtracted from 8 (i.e. 7) so add the param mitra digit of 9 (which is 1 ) to 7. (7 + 1 = 8)
4. Make ekanyunena purvena of 8 is 6.
5. Subtract 4 from 6 (i.e. 5) and write 1.
(ii)
Solution :
Steps :
1. 9 cannot be subtracted from 4, so add param mitra of 9 (which is 1) to 4. (4 + 1 = 5)
2. Make ekanyunena purvena of digit 4 as 2.
3. Similarly 9 cannot be subtracted from 2 (i.e., 1) so add param mitra of 9 (which is 1) to 1. (1 + 1) = 2.
4. Make ekanyunena purvena of 2 as 3.
5. Subtract 1 from 3 (i.e., 2) and write 1.
(iii)
Solution :
Steps :
1. 6 cannot be subtracted from 3 so add the param mitra digit of 6 (which is 4) to 3. (3 + 4) = 7
2. Make the ekanyunena purvena of digit 3 as?
3. Subtract 5 from ? (i.e. 6) and write 1.
4. Subtract 1 from 2 and write 1.
(iv)
Solution :
Steps :
1. 7 cannot be subtracted from 6, so add param mitra digit of 7 (which is 3) to 6. (6 + 3 = 9)
2. Make ekanyunena purvena of digit 6 as 7.
3. Subtract 5 from ? (i.e. 6) and write 1.
4. Subtract 2 from 4 and write 2.
RBSE Class 4 Maths Chapter 9 Vedic Mathematics Important Questions
Multiple Choice Questions :
Question 1.
The Param Mitra Ank of 3 is :
(a) 6
(b) 5
(c) 8
(d) 7
Solution :
(d) 7
Question 2.
Ekadhikena Purvena of digit 4 in number 64 is :
(a) \(\dot{6}\) 4
(b) 6 \(\dot{4}\)
(c) 6 \(\dot{4}\)
(d) none of these
Solution :
(a) \(\dot{6}\) 4
Question 3.
The new number formed by making Ekadhikena Purvena of digit 7 in 47 will be :
(a) 37
(b) 57
(c) 27
(d) 46
Solution :
(b) 57
Question 4.
The number by making Ekanyunena Purvena of digit 3 in 753 will be :
(a) 743
(b) 763
(c) 653
(d) 863
Solution :
(a) 743
Question 5.
Param Mitra Ank of 5 is :
(a) 6
(b) 4
(c) 3
(d) 5
Solution :
(d) 5
Fill in the blanks :
1. Param Mitra Ank of 1 is _____.
Answer: 9
2. Ekadhikena Purvena of 0 is _____.
Answer: \(\dot{1}\)
3. Ekadhikena Purvena of digit 6 in 4567 is _____.
Answer: 4667
4. Ekadhikena Purvena of digit 5 in 985 is _____.
Answer: 995
5. Ekanyunena Purvena of digit 3 in 5432 is _____.
Answer: 5332
Select True/False for the following statements :
(i) Sum of Param Mitra digits is 10. (True/False)
Answer: True
(ii) Ekadhikena Purvena of digit 5 in 4598 is 5598. (True/False)
Answer: True
(iii) Ekanyunena Purvena of digit 2 in 7521 is 7621. (True/False)
Answer: False
(iv) Ekadhikena Purvena of digit 8 in 92578 is 92588. (True/False)
Answer: True
Very Short Answer Type Questions :
Question 1.
What is the Ekadhik of 96?
Solution :
Ekadhik of 96 = 9 \(\dot{6}\) = 96 + 1 = 97
Question 2.
What is the Ekanyunena of 75?
Solution :
Ekanyunena of 75 = 7 \(\dot{5}\) = 75 – 1 = 74
Question 3.
What is the new number formed from Ekadhikena Purvena of digit 0 in 3706?
Solution :
Ekadhikena Purvena of digit 0 in 3706
= 3 \(\dot{7}\) 06 = 3806
Question 4.
What is the new number formed from Ekadhikena Purvena of digit 0 in 505?
Solution :
Ekadhikena purvena of digit 0 in 505
= \(\dot{5}\) 05 = 605
Question 5.
What is the new number formed from Ekanyunena purvena of digit 3 in 6893?
Solution :
Ekanyunena purvena of digit 3 in 6893
= 6893 = 6883
Question 6.
Find the sum by using Ekadhikena purvena method :
Solution :
Steps :
1. Sum of digit : 7 + 4 = 11
2. Sum is greater than 10, therefore write 1 in sum and make ekadhikena purvena of digit 4 and \(\dot{4}\).
3. Sum of tens digits : 2 + \(\dot{4}\) = 2 + 5 = 7 write 7.
Short Answer Type Questions :
Question 1.
Find the sum by using Ekadhikena purvena method :
Solution :
Steps :
1. Sum of unit digits : 8 + 4 = 12
2. Sum is greater than 10, therefore write 2 in sum and make ekadhikena purvena of 4 as \(\dot{7}\).
3. Sum of tens digits : 4 + \(\dot{7}\) = 4 + 8 = 12, write 12.
Question 2.
Find the sum by using Ekadhikena Purvena method :
Solution :
1. Sum of unit digits : 4 + 7 = 11
2. Sum is greater than 10, therefore write 1 in sum.
3. Sum of tens digits : 1 + \(\dot{2}\) = 1 + 3 = 4 wirte 4.
4. Sum of hundreds digits 7 + 5 = 12, write 12.
Question 3.
Find the subtraction of the following by using Ekanyunena purvena method :
Solution :
Steps :
1. 4 cannot be subtracted from 3, so add the param mitra digit of 4 (which is 6) to 3. (3 + 6 = 9)
2. Make the Ekanyunena purvena of digit 5 as 8.
3. Subtract 5 from 8 (i.e. 7) and write 2.
Question 4.
Find the subtraction of the following by using Ekanyunena Purvena method :
Solution :
Steps :
1. 7 cannot be subtracted from 5, so add the param mitra digit of 7 (which is 3) to 5. (5 + 3 = 8)
2. Make ekanyunena purvena of digit 5 as 3.
3. Similarly, 5 cannot be subtracted from 3 (i.e. 2), so add the param mitra of 5 (which is 5) to 2. (2 + 5 = 7)
4. Subtract 2 from 4 (i.e. 3) and write 1.
Long Answer Type and Essay Type Questions :
Question 1.
Find the sum using Ekadhikena purvena methods :
(i) 
Solution :
(ii) 
Solution :
(iii) 
Solution :
Question 2.
Find the subtraction of the following using Ekanyunena purvena method :
(i) 
Solution :
(ii) 
Solution :
(iii) 
Solution :
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