Regular practice of RBSE Class 4 Maths Solutions We Learnt and Understood-4 Question Answer sharpens your problem-solving skills.
RBSE Class 4 Maths We Learnt and Understood-4 Question Answer
Question 1.
Draw the hour and minute hands of the given clocks according to the following time-
(i) 6 o’clock 00 minutes
Solution :
(ii) 3 o’clock 45 minutes
Solution :
(iii) 11 o’clock 35 minutes
Solution :
Question 2.
Write the names of Hindi and English months-
Solution :
| Hindi months | English months |
| 1. Poush | 1. January |
| 2. Magh | 2. February |
| 3. Falgun | 3. March |
| 4. Chaitra | 4. April |
| 5. Vaishakha | 5. May |
| 6. Jyeshtha | 6. June |
| 7. Ashadha | 7. July |
| 8. Shravana | 8. August |
| 9. Bhadrapad/Bhadra | 9. September |
| 10. Ashwin | 10. October |
| 11. Kartik | 11. November |
| 12. Margashirsha | 12. December |
Question 3.
Convert the following time-
(i) 5 hours into minutes
Solution :
5 hours = 5 × 60 minutes = 300 minutes
(ii) 2 hours 45 minutes into minutes
Solution :
2 hours 45 minutes
= 2 × 60 minutes + 45 minutes
= 120 + 45 = 165 minutes
(iii) 6 hours 20 minutes into minutes
Solution :
6 hours 20 minutes
= 6 × 60 minutes + 20 minutes
= 360 minutes + 20 minutes
= 380 minutes
(iv) 15 minutes into seconds
Solution :
15 minutes = 15 × 60 seconds
= 900 seconds
(v) 10 minutes 15 seconds into seconds
Solution :
10 minutes 15 seconds
= 10 × 60 seconds + 15 seconds
= 600 seconds + 15 seconds
= 615 seconds
(vi) 3 days 12 hours into hours
Solution :
3 days 12 hours = 3 × 24 hours +12 hours
= 72 hours + 12 hours = 84 hours
Question 4.
Find the total time-
(i) 4 hours 35 minutes and 2 hours 15 minutes
Solution :
(ii) 1 hour 45 minutes and 3 hours 30 minutes
Solution :
(iii) 20 minutes 40 seconds and 15 minutes
Solution :
(iv) 5 minutes 55 seconds and 2 minutes 15 seconds
Solution :
Question 5.
Find the difference in time-
(i) 9 hours 40 minutes and 5 hours 25 minutes
Solution :
(ii) 12 hours 10 minutes and 8 hours 50 minutes
Solution :
(iii) 30 minutes 15 seconds and 18 minutes
Solution :
(iv) 1 hour 20 minutes and 45 minutes
Solution :
Question 6.
Solve-
(i) If the price of samosa in the school canteen is ₹ 18 and the price of juice is ₹ 22, then what will be the total price of both?
Solution :
Total price = 18 + 22 = ₹ 40
(ii) You have ₹ 100, if you buy a book for ₹ 35 and a pencil box for ₹ 45, then how much money will be left?
Solution :
Total expenses on book and pencil
= ₹ 35 + ₹ 45
= ₹ 80
Remaining = ₹ 100 – ₹ 80 = ₹ 20
(iii) Tina bought a purse for ₹ 50 and slippers for ₹ 75. She paid ₹ 200. How much money did she get back?
Solution :
Total expenses on purse and slipper
= ₹ 50 + ₹ 75
= ₹ 125
Remaining = ₹ 200 – ₹ 125 = ₹ 75
Question 7.
Mutual conversion of Rupees and Paise-
(i) Convert 475 paise into rupees.
Solution :
475 paise = 400 paise + 75 paise
= ₹ 4+75 paise
(ii) Write ₹ 9.25 in paise.
Solution :
₹ 9.25 = ₹ 9+25 paise
= 9 × 100 paise + 25 paise
= (900+25) paise = 925 paise
(iii) How will you write 680 paise in rupees and paise?
Solution :
680 paise =600 paise +80 paise
= ₹ 6.80 or ₹ 680 paise
(iv) How many rupees will 1000 paise be?
Solution :
1000 paise = ₹ 10
Question 8.
Daily life problems related to Currency-
(i) Mother spent ₹ 35 on vegetables, ₹ 60 on fruits and ₹ 45 on milk. What was the total expenditures?
Solution :
Total expenditure
= ₹ 35 + ₹ 60 + ₹ 45
= ₹ 140.
(ii) Rahul has ₹ 500. He bought a pencil box for ₹ 120, a notebook for ₹ 180 and a water bottle for ₹ 75. How much money will he have left?
Solution :
Total expenditure
= ₹ 120 + ₹ 180 + ₹ 75 = ₹ 375
Remaining = ₹ 500 – ₹ 375 = ₹ 125
(iii) A girl bought a skirt for₹ 200 and a T-shirt for ₹ 150. If she gives ₹ 500 to the shopkeeper, how much money will she get back?
Solution :
Total expenditure on skirt and T-shirt
= ₹ 200 + ₹ 150 = ₹ 350
Remaining = ₹ 500 – ₹ 350 = ₹ 150
(iv) At a shop, the price of sweets is ₹ 300 , the price of namkeen is ₹ 250 and the price of chocolate is ₹ 100. If a customer buys sweets, namkeen and chocolate and gives ₹ 1000 to the shopkeeper, how much money will he get back?
Solution :
Total expenditure on Sweets and Namkeen
and Chocolate = ₹ 300 + ₹ 250 + ₹ 100
= ₹ 650
Money given to shopkeeper = ₹ 1000
Remaining = ₹ 1000 – ₹ 650 = ₹ 350
(v) Ravi gave 2 notes of ₹ 50, 3 notes of ₹ 20 and 5 coins of ₹ 10. How much money did he give in total?
Solution :
2 notes of ₹ 50 = ₹ 50 + ₹ 50 = ₹ 100
3 notes of ₹ 20 = ₹ 20 + ₹ 20 + ₹ 20 = ₹ 60
5 coins of ₹ 10 = ₹ 10 + ₹ 10 + ₹ 10 + ₹ 10 + ₹ 10 = ₹ 50
Total = ₹ 100 + ₹ 60 + ₹ 50 = ₹ 210
Question 9.
Find the Perimeter-
(i) The length of a courtyard is 25 meters and the width is 10 meters. What will be the perimeter of the courtyard?
Solution :
Perimeter of courtyard
= 2(length + breadth)
= 2(25+10) meter
= 2 × 35=70 meter
(ii) The length of a rectangular table is 6 meters and the width is 4 meters. Find its perimeter.
Solution :
Perimeter of table = 2(length + width)
= 2(6 meter +4 meter)
= 2(10 meter)
= 20 meter
(iii) The length of the door of a classroom is 7 meters and the width is 3 meters. What will be the perimeter of the door?
Solution :
Perimeter of the door
= 2(length + width)
= 2(7 meter + 3 meter)
= 2(10 meter) = 20 meter
(iv) The length of a garden is 30 m and width 20 m. How much length of wire is required to fence all four sides of the garden?
Solution :
Length of wire
= 2(length + width)
= 2(30 meter + 20 meter)
= 2(50 meter) = 100 meter
(v)
Figure (1) : Total length of the fence = _______
Solution :
Total length of the fence
= 2(length + width)
= 2(7 meter + 4 meter)
= 2 × 11 = 22 meter
Figure (2) : Total length of the fence = _______
Solution :
Total length of the fence
= 4 × side
= 4 × 4 meter = 16 meter
Question 10.
What is the difference between the numerical value of area and perimeter of the given figure?
(a) 23
(b) 5
(c) 14
(d) 9
Solution :
Area = 9 square unit
Perimeter = 14 unit
Difference in numerical value = 14 – 9 = 5
Answer:
(b) 5
Question 11.
Choose a pair from the given figures which has the same perimeter.
(a) L & M
(b) M & N
(c) L & N
(d) N & O ( )
Solution :
(i) Perimeter of L = 12 unit
(ii) Perimeter of M = 14 unit
(iii) Perimeter of N = 12 unit
(iv) Perimeter of O = 18 unit
Answer:
(c) L and N have same perimeter.
Question 12.
Which of the following figures has the largest area? = 1 ones
(a)
(b)
(c)
(d)
Solution :
(b) 7 square unit
Question 13.
Students of class 4 scored 2, 4, 3, 2, 4, 3, 2, 5, 1, 3, 1, 3, 2, 4 and 5 marks in a test of Mathematics subject. Fill in the table given below with these marks and write answers to the questions given below-
(i) How many number of students got 3 marks.
(ii) How many number of students are there in the class?
Solution :
(i) 4 (ii) 15
Question 14.
The number of students who were absent from school during the last week is given in the table. Represent it through a bar graph.
Solution :
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