RBSE Class 5 Mathematics Board Paper 2017 English Medium are part of RBSE Class 5 Mathematics Board Model Papers. Here we have given Rajasthan RBSE Class 5 Mathematics Board Paper 2017 English Medium.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Mathematics |

Paper Set |
Board Paper 2017 |

Category |
RBSE Model Papers |

## Rajasthan RBSE Class 5 Mathematics Board Paper 2017 English Medium

**Time: 2.30 Hours**

**Maximum Marks: 80**

**General Instructions to the Students**

- All questions are compulsory.
- All questions are based on prescribed competencies/leaming area.
- Weightage of each question is written in front of it.
- Question paper is divided into 5 parts. Solve all questions.
- Answer must be written in the space provided below the questions.
- Do not tear, damage or separate any part of questions paper.

**1. Understanding of Shape and Position [8]**

Question 1.

Fill in the blanks: **[2]**

1. Angles which are less than right angle are called_______

2. Angle of 90° is called_______

Question 2.

Write the measures of following angles with the help of protractor: **[6]
**

1. _______

2. _______

3. _______

**2. Understanding Number of System [16]**

Question 3.

Write the fraction form of shaded part in given figure **[1]**

a. [latex s=2]\frac{2}{3}[/latex]

b. [latex s=2]\frac{1}{2}[/latex]

c. [latex s=2]\frac{1}{3}[/latex]

d. [latex s=2]\frac{2}{1}[/latex]

Question 4.

Seeing the number line tell that which number will be in box **[1]**

a. [latex s=1]4 \frac{1}{3}[/latex]

b. [latex s=1]3 \frac{1}{3}[/latex]

C. [latex s=1]1 \frac{3}{4}[/latex]

d. [latex s=1]3 \frac{1}{4}[/latex]

Question 5.

Write the ascending order of number **[4]**

45378, 43758, 47538 and 48735.

Question 6.

Write true or false in given statements. **[4]**

1. The greatest number formed from the digits 5, 0, 6, 2, 1 is 65201.

2. The place value of digit 2 in number 12756 is 2000.

3. 5320 > 5230

4. The digit 2 is in place of thousand in number of 23684

Question 7.

Show that the equal fractions by shading in given figure. **[6]**

**3. Understanding of basic Mathematical Operation [24]**

Question 8.

Add: **[2]**

[latex s=1]\begin{array}{r}{268} \\ {+\quad 473} \\ \hline\end{array}[/latex]

Question 9.

Write the missing digits **[2]**

[latex s=1]\begin{array}{r}{\square 8} \\ {-3 \square} \\ \hline 35\end{array}[/latex]

Question 10.

a. [latex s=1]\begin{array}{r}{3068} \\ {+4374} \\ \hline\end{array}[/latex] **[4]**

b. [latex s=1]\begin{array}{r}{8000} \\ {-2636} \\ \hline\end{array}[/latex]

Question 11.

Multiply 14 × 13 by sutra Nikhilam. **[4]**

Question 12.

Solve:

(i). If a flower beds have 144 plants then how many plants will be in 206 flower beds. **[6]**

(ii). How many garlands can be made from 880 flowers whenever one garland has sixteen flowers?

Question 13.

Find the greatest number, which divides completely 20, 40 and 60. **[6]**

**4. Understanding of Measurement [24]**

Question 14.

Fill in the blanks: **[4]**

a. 3 Kg. =_______ gm.

b. 1500 gm. =_______ Kg.

c. 8Km. =_______ metre

d. 500 Cm. =_______ metre

Question 15.

Write the tick mark to identify true or false: **[4]**

a. 3600 seconds in one hour (Ture / False)

b. Multiply by sixty to convert hour unit into minute unit (Ture / False)

c. 300 seconds in 3 minutes (Ture / False)

d. 200 minutes in 4 hours (Ture / False)

Question 16.

Ganesh purchased following materials from Swadeshi General STore, Bharatpur: **[4]**

(1) Rice 3 Kg., at the rate of 40 Rs 25 paisa

(2) Oil 2 Litre, at the rate of 75 Rs 60 paisa

(3) Sugar 4 Kg., at the rate of 41 Rs.

Prepare the bill of purchase materials in given format and how much money spent by Ganesh in total.

Question 17.

Give the answers to see the figures given on grid paper. **[6]**

(1) Area of rectangle ABCD =_______

(2) Area of rectangle PQRS =_______

(3) Area the area of both rectangles same ?_______

(4) Perimeter of rectangle ABCD =_______

(5) Perimeter of rectangle PQRS = _______

(6) Which rectangle has more perimeter. Write the name.

Question 18.

From a 100 liter oil drum 3 cans of 10 liters, 6 cans of 5 liters and 10 cans of 3 liters are filled then how many cans of 21itres will be filled by remaining oil? **[6]**

**5. Understanding of Data Handling and Pattern [8]**

Question 19.

Increase the given patterns: **[1]**

Question 20.

If 🏠 = 10 houses then **[1]**

How many houses are showing by 🏠🏠🏠

(a) 32

(b) 30

(c) 302

(d) 1011

Question 21.

Fill in the blanks identify the given patterns **[2]**

Question 22.

The number of accidents recorded in month of February in cross street by traffic police in Jaipur city are given below: **[4]**

Weeks |
I | II | III | IV |

Number of Accidents |
7 | 2 | 3 | 5 |

Draw the column chart in given graph of these data.

**Answers**

Answer 1:

- acute angle
- Right angle 11.

Answer 2:

- 70°
- 115°
- 90°

Answer 3:

c. [latex s=2]\frac{1}{3}[/latex]

Answer 4:

d. [latex s=1]3 \frac{1}{4}[/latex]

Answer 5:

43758, 45378, 47538, 48735

Answer 6:

- False
- True
- True
- False

Answer 7:

Answer 8:

Answer 9:

Answer 10:

Answer 11:

Answer 12:

Answer 13:

Factor of 20- 1, 2, 3, 4, 5, 10, 20

Factor of 40- 1, 2, 3, 4, 5, 8, 10, 20, 40

Factor of 60 – 1,2, 3, 4, 5, 6, 10, 12, 15,20, 30, 60

This equal factor of20, 40 and 60 are- 1, 2, 4, 5, 10, 20

Gratest factor of 20, 40 and 60 is 20 thus 20 is the greatest number which divides 20, 40 and 60 completely

Answer 14.

a. 3000

b. [latex s=1]1 \frac{1}{2}[/latex]

c. 8000

d. 5

Answer 15.

a. True

b. True

c. False

d. False

Answer 16:

Answer 17:

- Area of rectangle ABCD = 12cm²
- Area of rectangle PQRS =12 cm²
- Yes, area of both rectangles are same.
- Perimater of rectangle ABCD = 14 cm
- Perimeter of rectangle PQRS = 16 cm
- Perimeter of rectangle PQRS is greater.

Answer 18.

Total oil in drum =100 liters

Oil in three cans of 10 litres = 30 liters

Oil in 6 cans of 5 liters = 30 liters

Oil in 10 cans of 3 liters = 30 litres

Tus total oil filled in cans

= 30 liters + 30 liters + 30 liters

Remaining oil = 100 – 90 = 10 liters

this oil to be filled in the cans of 2 liters

hence number of cans of 2 liters. = 10 + 2 = 5 cans

Answer 19:

Answer 20:

(b) 30

Answer 21:

Answer 22:

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