Regular practice of Class 5 Maths RBSE Solutions and RBSE Class 5 Maths Chapter 15 Solutions Neena’s Birthday Question Answer sharpens your problem-solving skills.
RBSE Class 5 Maths Chapter 15 Question Answer Neena’s Birthday
Neena’s Birthday Class 5 Questions and Answers
Neena’s Birthday Class 5 Question Answer – InText
Page-136
Question 1.
Let’s find out the perimeter of the rectangle :
Answer:
Page-137
Let’s practice :
Question 1.
Some rectangles are drawn on a grid paper below, If the side of the square on the grid paper is 1 centimetre, then find the perimeter of each rectangle :
Answer:
Page-139
Question 1.
Write the Area of the given shapes in square centimetres : _______.
Answer:
- 6 square centimeter
- 16 square centimeter
- 5 square centimeter
- 21 square centimeter
- 7 square centimeter
Page-140-141
Question 1.
Mahima has made some shapes by taking 9 square boxes of side 1 cm :
Observe the number of cells (area) and external measurement (perimeter) of these shapes and write it in the note book.
Solution :
- Area = 9 sq cm ; Perimeter = 20 cm
- Area = 9 sq cm ; Perimeter = 18 cm
- Area = 9 sq cm ; Perimeter = 20 cm
- Area = 9 sq cm ; Perimeter = 12 cm
Try it yourself :
(i) Draw a rectangle in your notebook of length 7 cm and width 5 cm and find its area and perimeter.
Solution :
Area of rectangle = length × width
= 7 cm × 5 cm
= 35 square cm
Perimeter of rectangle = 2 × (length + width)
= 2 × (7 + 5) cm
= 24 cm
Draw the picture yourself.
(ii) With the help of your classmate, draw a square of side 8 cm and find its area and perimeter.
Solution :
Draw the picture yourself.
Area of square = side × side
= 8 cm × 8 cm
= 64 square cm
Perimeter of square = 4 × side
= 4 × 8 cm
= 32 cm
(iii) Find the perimeter and area of a rectangle 12 cm long and 15 cm wide on a grid of 1 cm × 1 cm cells.
Solution :
Perimeter of rectangle = 2 × (length + width)
= 2 × (12 + 15) cm
= 2 × 27 cm
= 54 cm
Area of rectangle = length × width
= 12 cm × 15 cm
= 180 square cm
(iv) The width and length of a cloth is 12 cm . How much long lace border be required around it?
Solution :
The length and width of the cloth are 12 cm. The length of the lace border around it will be equal to its perimeter.
Perimeter = 4 × 12 = 48 cm
(v) The length of each side of a square plot is 9 m. Find its area.
Solution :
Area of the square plot = side × side
= 9 m × 9 m
= 81 square meters
(vi) The length of a garden is 12 m and width 10 m. Find its area.
Solution :
Area of the garden = length × width
= 12 m × 10 m
= 120 square meters
(vii) The length of one side of a square garden is 8 m. How much long wire will be required to fence the garden?
Solution :
Length of the square garden = 8 m Perimeter of the square garden
= 4 × 8 = 32 m
Therefore, 32 meters of wire will be needed to fence all four sides of the garden.
Page-144
Find out :
Question 1.
The perimeter of the given triangle is 30 cm. If a square of side 2 cm long is removed from it, then what will be the perimeter of the remaining part?
Solution :
Perimeter of the original triangle
= 30 centimeters
Perimeter of the remaining part after removing a 2 cm side square
= (30+4) = 34 cm
Question 2.
From the square shown in Figure1 below, 8 squares of 1 × 1 cm are cut out as shown in Figure-2. Then find the perimeter of the new figure.
Solution :
First, the perimeter of the square in figure-1
= 4 × side
= 4 × 5 cm
= 20 cm
When 8 square of 1 cm are cut from the square in figure-1 as per figure-2. The perimeter of the remaining shape, figure-2 is
= (20-1 × 8+3 × 8) cm
= (20-8+24) cm
= (20+16) cm
= 36 cm
RBSE Class 5th Maths Chapter 15 Question Answer – Practice Work
Question 1.
Write the formula to find the area and perimeter of the following figures :
(i) Rectangle
(ii) Square
Solution :
(i) Area of rectangle = length × width Perimeter of rectangle = 2 × (length + width)
(ii) Area of square = side × side
Perimeter of square = 4 × side
Question 2.
The length of a rectangle is 40 cm and width is 60 cm. Then find its area and perimeter.
Solution :
Area of rectangle = length × width
= 40 cm × 60 cm
= 2400 square cm
Perimeter of rectangle
= 2 × (length + width)
= 2 × (40 cm + 60 cm)
= 2 × 100 cm
= 200 cm
Question 3.
A boundary wall has to be built around a rectangular field. If the length of the field is 50 meters and the width is 40 meters, then how many meters of the boundary wall will have to be built?
Solution :
Length of the field = 50 m, width = 40 m
∴ Perimeter = 2 × (50m + 40m)
= 2 × 90 m
= 180 m
Therefore, a 180 m wall will need to be built.
Question 4.
What will be the perimeter of the remaining shape of the given square if a piece of 4 cm length and 6 cm width is removed from it?
Solution :
First, the perimeter of the square shape = 4 × 8 cm
= 32 cm
After cutting a piece of 4 cm length and 6 cm width, the perimeter of the remaining shape
= 32 cm – (6 cm + 4 cm) + (4 cm + 6 cm)
= 32 cm-10 cm+10 cm
= 32 cm
Question 5.
Find the area of the shaded region in the given figures :
Solution :
Area of the first shaded part
= \(\frac{1}{2}\) (length × width)
= \(\frac{1}{2}\) × 3 × 2
= 3 square cm
Area of the second shaded part
= 25 m × 25 m
= 625 square meters
RBSE Class 5 Maths Chapter 15 Neena’s Birthday Important Questions
Question 1.
Area means :
(A) An object occupying space in the air
(B) An object occupying space in water
(C) An object occupying space on a surface
(D) An object occupying space in a liquid
Answer:
(C) An object occupying space on a surface
Question 2.
The area enclosed by a figure on grid paper is calculated by :
(A) Drawing a sketch of the object
(B) Counting the number of squares covered by the object
(C) Cutting the graph paper in the shape of the object
(D) None of the above
Answer:
(B) Counting the number of squares covered by the object
Question 3.
A book has a length of 6 cm and width of 5 cm. How many squares will that book cover on graph paper?
(A) 30
(B) 40
(C) 50
(D) 60
Answer:
(A) 30
Question 4.
An envelope has a length of 15 cm and a width of 20 cm. What will be the outer measurement of the envelope?
(A) 60 cm
(B) 70 cm
(C) 80 cm
(D) 90 cm
Answer:
(B) 70 cm
Question 5.
The unit of area is in meters :
(A) square meter
(B) meter
(C) cube meter
(D) kilometer
Answer:
(A) square meter
Question 6.
The formula to find the perimeter of a square is :
(A) side × side
(B) length + width
(C) length ÷ width
(D) 4 × side
Answer:
(D) 4 × side
Question 7.
If the side of a square is 5 meters, then the area of this square will be among the following :
(A) 10 meters
(B) 25 meters
(C) 25 square meters
(D) 15 square meters
Answer:
(C) 25 square meters
Fill in the blanks :
(i) Area of a rectangle = _______ × width.
Answer:
length
(ii) The space enclosed by any object is called its _______ .
Answer:
Area
(iii) The _______ of open figures cannot be determined.
Answer:
perimeter
(iv) Perimeter of regular figures = _______ × measure of side.
Answer:
number of sides
(v) Perimeter of a rectangle = 2 × ( _______ + width).
Answer:
length
Write whether true or false :
(i) The perimeter of a square platform is 240 cm and each of its sides is 60 cm.
Answer: True
(ii) If all sides of a triangle are equal, its perimeter is 3 × side.
Answer: True
(iii) The perimeter of a square is side × side.
Answer: False
(iv) The area of a rectangle = 2 × (length + width)
Answer: False
Very Short Answer Type Questions :
Question 1.
The measures of the three sides of a triangle are 4 cm, 5 cm and 6 cm. Write the outer measure of this triangle.
Solution :
Outer measure of a triangle
= Sum of all three sides of the triangle
= 4 cm + 5 cm + 6 cm
= 15 cm
Question 2.
If a packet of biscuits has a length of 8 cm and a width of 4 cm, how many squares will it cover on a graph paper?
Solution :
32 squares
Question 3.
Find the outer measure of the figure given below :
Solution :
Outer measure = 16 + 2 + 10 + 3 + 2 + 3 + 2 + 3 + 2 + 5
= 48 cm
Question 4.
What is perimeter?
Solution :
If the outer measurement of any shape is measured and the total sum is calculated, that measurement is called perimeter.
Question 5.
If the length of a mat is 30 cm and the width is 25 cm , how much space will it cover on the floor?
Solution :
Length of the mat = 30 cm
Width of the mat = 25 cm
Therefore, total space covered = 30 × 25
= 750 square cm
Question 6.
The length of a rectangular fields is 25 m and the width is 30 m . Find the area of this field.
Solution :
Area of the rectangular field
= length × width
= 25 × 30
= 750 square meter
Question 7.
The length of a rectangular towel is 125 cm and the width is 60 cm. What will be the perimeter of this towel?
Solution :
Perimeter of a rectangular towel
= 2 × (length + width)
= 2 × (125 + 60)
= 2 × 185 = 370 cm
Short Answer Type Questions :
Question 1.
Dev had to walk 40 meters to complete two rounds of a square field. Find the side of the square field.
Solution :
Distance covered in two rounds = 40 meters
Distance covered in one round
= 40 ÷ 2 = 20 meters
The distance covered in one round is called the perimeter. Therefore, the perimeter of the square field = 20 meters
∵ 4 × side = Perimeter
Side = \(\frac{Perimeter }}{4}\) = \(\frac{20}{4}\) = 5 meters
Therefore, the side of the square field = 5 meters.
Question 2.
To fence a square field with barbed wire, 260 m of barbed wire were required. Find the side of this field.
Solution :
Perimeter of the square = 4 × side
Side of the square = \(\frac{Perimeter }}{4}\)
Here, Perimeter = 260 meters
Side of the square = \(\frac{260}{4}\) = 65 meters
Question 3.
The length of a room’s floor is 8 meters and the width is 7 meters. A carpet is laid in this room that completely covers the floor. Find the area of this carpet.
Solution :
Length of the floor = 8 meters
Width of the floor = 7 meters
Area of the floor = Area of the carpet
= length × width
= 8 × 7 = 56 square meters
Therefore, the area of the carpet = 56 square meters.
Question 4.
Find the perimeter of the figures given below.
Solution :
(i) Perimeter of figure (A)
= 10 + 7 + 10 + 8 + 7 + 7 + 9 + 7
= 65 cm
(ii) Perimeter of figure (B)
= 10 + 5 + 4 + 5 + 5 + 4 + 5
= 38 cm
Question 5.
The length of a mobile is 9 cm and its width is 4 cm. Calculate the area covered by the mobile. (use a grid with 1 cm × 1 cm squares)
Solution :
Length of mobile = 9 cm
Width of mobile = 4 cm
When the mobile is placed on grid paper, it will cover 36 squares.
Long Answer Type and Essay Type Questions :
Question 1.
Vijay has made a rectangle. Find its perimeter and area.
Can you increase its length and width in such a way that its perimeter and area become equal? (It’s not necessary to increase both length and width)
Solution :
Perimeter of the rectangle made by Vijay
= 2 × (length + width)
= 2 × (5 + 3)
= 2 × 8
= 16 cm
Area of the rectangle = length × width
= 5 × 3
= 15 square cm
If the length of this rectangle is reduced by 1 cm and the width is increased by 1 cm, its dimensions will become.
and
Length = 4 cm
Width = 4 cm
Then the perimeter and area of this square will both become equal.
Perimeter of the square = 4 × side
= 4 × 4
= 16 cm
Area of the square = (side)2
= 4 × 4
= 16 square cm
Question 2.
Some shapes are given on the grid paper below. Find their area.
Solution :
(i) The figure shows a rectangle. If each side of the square on the grid paper measures 1 cm, then the length of the rectangle = 5 cm and the width = 2 cm The number of squares enclosed by rectangle ABCD = 10
Therefore, the area of the rectangle
= 10 square cm.
Here, a rule is also visible between the length, width and area of the rectangle.
Length × Width = Area
= 5 cm × 2 cm
= 10 square cm.
(ii) Length of the square = 4 cm
Breadth of the square = 4 cm
Area of the square = (side)2
= (4)2
= 16 square cm
Number of squares enclosed within square ABCD = 16
Therefore, area of the square = 16 square cm
(iii) Length of the rectangle = 7 cm
Breadth of the rectangle = 3 cm
Area of the rectangle = length × breadth
= 7 cm × 3 cm
= 21 square cm
Number of squares enclosed within rectangle ABCD = 21
Therefore, area = 21 square cm
Leave a Reply