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RBSE Class 5 Maths We Learnt and Understood-II Solutions

February 28, 2026 by Prasanna Leave a Comment

Regular practice of Class 5 Maths RBSE Solutions We Learnt and Understood-II Question Answer sharpens your problem-solving skills.

RBSE Class 5 Maths We Learnt and Understood-II Question Answer

Question 1.
Multiply :
(i) 2453 × 624
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 1

(ii) 3891 × 237
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 2

(iii) 1765 × 418
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 3

(iv) 3127 × 295
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 4

(v) 1301 × 751
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 5

(vi) 6213 × 981
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 6

Question 2.
Solve and check your answer :
(i) 1440 ÷ 18
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 7
Here 18 × 80 + 0 = 1440
Therefore, Divisor × Quotient + Remainder = Dividend

(ii) 2352 ÷ 24
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 8
Here 24 × 98 + 0 = 2352
Therefore, Divisor × Quotient + Remainder = Dividend

(iii) 1680 ÷ 20
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 9
Here 20 × 84 + 0 = 1680
Therefore, Divisor × Quotient + Remainder = Dividend

(iv) 972 ÷ 12
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 10
Here 12 × 81 + 0 = 972
Therefore, Divisor × Quotient + Remainder = Dividend

(v) 315 ÷ 9
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 11
Here 9 × 35 + 0 = 315
Therefore, Divisor × Quotient + Remainder = Dividend

(vi) 1872 ÷ 26
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 12
Here 26 × 72 + 0 = 187
Therefore, Divisor × Quotient + Remainder = Dividend

(vii) 1600 ÷ 25
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 13
Here 25 × 64 + 0 = 1600
Therefore, Divisor × Quotient + Remainder = Dividend

(viii) 1045 ÷ 19
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 14
Here 19 × 55 + 0 = 1045
Therefore, Divisor × Quotient + Remainder = Dividend

(ix) 2465 ÷ 17
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 15
Here 17 × 145 + 0 = 2465
Therefore, Divisor × Quotient + Remainder = Dividend

Question 3.
Answer :
(i) Radhika bought 15 copies for Rs 1230. What is the cost of one copy?
Solution :
(i) The cost of 15 notebooks
= Rs. 1230
Therefore, the cost of 1 notebook
= Rs. (1230 ÷ 15)
= Rs. 82
RBSE Class 5 Maths We Learnt and Understood-II Solutions 16

(ii) A farmer has 984 oranges. How many dozen oranges will he have?
Solution:
The farmer has a total of oranges = 984 Therefore, dozens of oranges
= 984 ÷ 12 = 82 dozens
∵ 1 Dozen =12 Oranges
RBSE Class 5 Maths We Learnt and Understood-II Solutions 17
Thus, the farmer has 82 dozen of oranges.

(iii) A student studied for a total of 1460 minutes in 20 days. How many minutes did he study every day?
Solution:
The student studied a total of minutes in 20 days = 1460 minutes
Therefore, daily study = 1460 ÷ 20 minutes = 73 minutes

RBSE Class 5 Maths We Learnt and Understood-II Solutions 18

(iv) Saurabh walked for a total of 9360 steps in 12 days. How many steps did he walk on an average every day?
Solution:
Saurabh walks a total of steps in 12 days = 9360
Therefore, the average steps walked per day
= 9360 ÷ 12 = 780 steps
RBSE Class 5 Maths We Learnt and Understood-II Solutions 19

(v) 875 toffees are to be packed in small packets. If one packet contains 25 toffees, how many packets will be made?
Solution:

RBSE Class 5 Maths We Learnt and Understood-II Solutions 20

(vi) Ekanyunena Purvena of the digit 4 in 184 :
Solution:
Ekanunen Purven of digit 4 in 184
= 184 = 174

(vii) Ekanyunena Purvena of digit 3 in 539 :
Solution:
Ekanunen Purven of digit 3 in 539
= 539 = 439

(viii) Ekanyunena Purvena of number 6 in 762 :
Solution:
Ekanunen Purven of digit 6 in 762
= 762 = 662

RBSE Class 5 Maths We Learnt and Understood-II Solutions

(ix) Ekanyunena Purvena of number 9 in 891 :
Solution:
Ekanunen Purven of digit 9 in 891
= 891 = 791

Question 4.
Show the following fractions on the number line :
(i) 2 \(\frac{1}{4}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 29

(ii) 1 \(\frac{1}{2}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 30

(iii) 2 \(\frac{3}{4}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 31

(iv) \(\frac{7}{2}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 32

(v) \(\frac{2}{3}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 33

(vi) \(\frac{8}{4}\)
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 34

Question 5.
Seema had 20 mangoes. She gave \(\frac{1}{5}\) mangoes to her friends. How many mangoes did Seema give to her friends?
Solution :
Seema had a total of mangoes =20
Gave to friends = \(\frac{1}{5}\) mangoes
= \(\frac{1}{5}\) × 20 = 4 mangoes
Therefore, Seema gave 4 mangoes to her friends.

Question 6.
Ramesh bought 2 dozen apples. \(\frac{1}{3}\) of these apples got rotten. How many apples got rotten?
Solution :
Ramesh bought apples = 2 dozen
= 2 × 12 = 24 apples
Apples rotted = \(\frac{1}{3}\)
= 24 × \(\frac{1}{3}\) = 8 apples
Therefore, 8 apples rotted out of 2 dozen apples.

Question 7.
Arya had 36 biscuits. She gave \(\frac{1}{6}\) biscuits to her brother. How many biscuits did Arya gave to her brother?
Solution :
Arya had a total of biscuits = 36
Given to brother = \(\frac{1}{6}\)
= 36 × \(\frac{1}{6}\)
= 6 Biscuits

RBSE Class 5 Maths We Learnt and Understood-II Solutions

Question 8.
There are 24 oranges in a bag. Rekha ate half of them. How many oranges are left now?
Solution :
Total oranges in the bag = 24
Rekha ate =24 × \(\frac{1}{2}\)
= 12 oranges
Remaining oranges = 24 – 12
= 12 oranges
Therefore, 12 oranges are left now.

Question 9.
Put the correct symbol of <, >, = between the fractions given below :
RBSE Class 5 Maths We Learnt and Understood-II Solutions 22 RBSE Class 5 Maths We Learnt and Understood-II Solutions 24
Solution:
RBSE Class 5 Maths We Learnt and Understood-II Solutions 23 RBSE Class 5 Maths We Learnt and Understood-II Solutions 25

Question 10.
Convert decimal to fraction :
(i) 0.5 = _______.
(ii) 0.75 = _______.
(iii) 1.2 = _______.
(iv) 0.10 = _______.
Solution :
(i) 0.5 = \(\frac{5}{10}\)
(ii) 0.75 = \(\frac{75}{100}\)
(iii) 1.2 = \(\frac{12}{10}\)
(iv) 0.10 = \(\frac{1}{10}\)

Question 11.
Write in decimal :
(i) 4 kilo 250 gram = _______. kilo
(ii) 1 meter 75 centimeter = _______. meter
Solution :
(i) 4 kilo 250 gram = 4.25 kilo
(ii) 1 meter 75 centimeter = 1.75 meter

RBSE Class 5 Maths We Learnt and Understood-II Solutions

Question 12.
Put the correct sign of >, < or = in the following blanks :
(i) 4.25 _______. 4.5
(ii) 6.75 _______. 6.7
(iii) 3.3 _______. 3.35
(iv) 7.85 _______. 7.58
(v) 9.09 _______. 9.90
(vi) 0.50 _______. 0.05
(vii) 2.45 _______. 2.54
(viii) 8.8 _______. 8.80
(ix) 57.5 _______. 5.75
Solution :
(i) 4.25 < 4.5
(ii) 6.75 > 6.7
(iii) 3.3 < 3.35
(iv) 7.85 > 7.58
(v) 9.09 < 9.90
(vi) 0.50 > 0.05
(vii) 2.45 < 2.54
(viii) 8.8 = 8.80
(ix) 57.5 > 5.75

Question 13.
Complete the pattern :
(i) 3,6,12,24, _______.
(A) 36
(B) 40
(C) 48
(D) 50
Answer:
(C) 48

(ii) 1024,512,256,128, _______.
(A) 64
(B) 96
(C) 100
(D) 32
Answer:
(A) 64

(iii) 5,15,45,135, _______.
(A) 270
(B) 405
(C) 325
(D) 37
Answer:
(B) 405

(iv) 1000,900,800,700, _______.
(A) 500
(B) 550
(C) 600
(D) 650
Answer:
(C) 600

RBSE Class 5 Maths We Learnt and Understood-II Solutions

Question 14.
The marks obtained by the students of Class 5 in the first test are 8, 8, 7, 5, 8, 7, 4, 5, 6, 9, 4, 5, 7, 8, 8, 7, 6, 5, 4, 8. Complete the following table by matching the marks.
RBSE Class 5 Maths We Learnt and Understood-II Solutions 26
Also draw a Bar graph or grid on the checkered sheet.
Solution :
RBSE Class 5 Maths We Learnt and Understood-II Solutions 27
Bar Graph :
RBSE Class 5 Maths We Learnt and Understood-II Solutions 28

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