Rajasthan Board RBSE Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbook Exercise Questions and Answers.

## RBSE Class 9 Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.1

Question 1.

The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.

(Take the cost of a notebook to be ₹ x and that of a pen to be ₹ y.)

Answer:

Let the cost of a notebook be ₹ x and that of a pen be ₹ y.

Since the cost of a notebook is twice the cost of a pen, so the required linear equation in two variables to represent the above statement is given by x = 2y.

Question 2.

Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case :

(i) 2x + 3y = 9.35̄

Answer:

2x + 3y = 9.35̄ can be written as 2x + 3y – 9.35̄ = 0.

On comparing it with ax + by + c = 0,

a = 2, b = 3 and c = – 9.35̄.

(ii) x – \(\frac{y}{5}\) – 10 = 0

Answer:

On comparing x – – 10 = 0 with ax + by + c = 0,

a = 1, b = –\(\frac{1}{5}\) and c = – 10.

(iii) – 2x + 3y = 6

Answer:

– 2x + 3y = 6 can be written as – 2x + 3y – 6 = 0.

On comparing it with ax + by + c = 0,

a = – 2, b = 3 and c = – 6.

(iv) x = 3y

Answer:

x = 3y can be written as x – 3y = 0.

On comparing it with ax + by + c = 0,

a = 1, b = – 3 and c = 0.

(v) 2x = – 5y

Answer:

2x = – 5y can be written as 2x + 5y = 0.

On comparing it with ax + by + c = 0,

a – 2, b = 5 and c = 0.

(vi) 3x + 2 = 0

Answer:

On comparing 3x + 2 = 0 with ax + by + c = 0,

a = 3, b = 0 and c = 2.

(vii) y – 2 = 0

Answer:

On comparing y – 2-0 with ax + by + c = 0,

a = 0, b = 1 and c = – 2.

(viii) 5 = 2x

Answer:

5 = 2x can be written as 2x – 5 = 0.

On comparing it with ax + by + c = 0,

a = 2, b = 0 and c = – 5.

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