RBSE Solutions for Class 9 Maths Chapter 9 Quadrilaterals Ex 9.4 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 9 Quadrilaterals Ex 9.4.

Board |
RBSE |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 9 |

Chapter Name |
Quadrilaterals |

Exercise |
Ex 9.4 |

Number of Questions Solved |
6 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 9 Quadrilaterals Ex 9.4

Question 1.

Construct a parallelogram ABCD such (RBSESolutions.com) that AB = 4.7 cm, BC = 3.5 cm and AC = 7 cm.

Solution.

Steps of construction:

1. Draw AB = 4.7 cm.

2. With centre A, draw an arc of radius 3.5 cm and 7 cm respectively.

3. With centre B, draw an arc of 3.5 cm which will intersect the line segment at C.

4. Again by taking C as centre, draw an arc of 4.7 cm which intersects the previous arc at D.

5. Join A to C, A to D, B to C and C to D. Hence, ABCD is required parallelogram.

Question 2.

Construct parallelogram PQRS, when PQ = 5 cm, diagonal PR = 7.6 cm and (RBSESolutions.com) diagonal QS = 5.6 cm.

Solution.

Steps of construction:

1. Draw PQ = 5 cm.

2. With centre P, draw an arc of 3.8 cm and with centre Q draw an arc of 2.8 cm. These arcs intersect at point O (say).

3. Produce PO and QO. With centre P, draw an arc of 7.6 cm and with centre Q draw an arc of 5.6. These arcs cut each other point S and R.

4. Join QR, RS and PS.

Hence, PQRS is the required parallelogram.

Question 3.

Construct a parallelogram ABCD whose two sides are 4.6 cm and 3 cm long (RBSESolutions.com) and included angle is 60°.

Solution.

Steps of construction:

1. Draw AB = 4.6 cm as base line.

2. With centre A, draw an angle of 60°.

3. Take A as centre, draw an arc of 3 cm which cuts, the line segment at D.

4. By taking D and B as centres draw arcs of 4.6 cm and 3 cm which intersect each other at C.

Hence, ABCD is a required parallelogram.

Question 4.

Construct a rectangle ABCD in which AB = 6 cm (RBSESolutions.com) and diagonal AC =10 cm.

Solution.

Steps of construction:

1. Draw a line segment AB = 6 cm.

2. At B draw an angle 90°.

3. With centre A draw an arc of radius 10 cm which cuts the (RBSESolutions.com) previous line segment at C.

4. With centre C draw an arc of 6 cm.

5. Again with A as centre and radius equal to BC, draw arc which cuts previous arc at D.

6. Join BC, CD and AD.

Hence, ABCD is required rectangle.

Question 5.

Construct a rhombus ABCD, such that (RBSESolutions.com) diagonals AC = 7 cm and diagonal BD = 5 cm.

Solution.

Steps of construction:

1. Draw one of the diagonal AC = 7 cm as base.

2. Draw perpendicular bisector of AC which intersects at O.

3. Take O as centre and cut (RBSESolutions.com) an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.

4. Join AD, DC, AB and BC.

Hence, ABCD is the required rhombus.

Question 6.

Construct a square ABCD, the length of whose diagonal is 6 cm.

Solution.

Steps of construction:

1. Draw the diagonal BD of length 6 cm as base.

2. Draw perpendicular (RBSESolutions.com) bisector of DB which intersects DB at O.

3. Take O as centre and draw an arc of 3 cm above and below the line segment BD.

4. Join A, B, C and D.

5. Hence, ABCD is the required square.

We hope the given RBSE Solutions for Class 9 Maths Chapter 9 Quadrilaterals Ex 9.4 will help you. If you have any query regarding RBSE Rajasthan Board Solutions for Class 9 Maths Chapter 9 Quadrilaterals Ex 9.4, drop a comment below and we will get back to you at the earliest.

## Leave a Reply