RBSE Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Ex 3.3

Rajasthan Board RBSE Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Ex 3.3 Textbook Exercise Questions and Answers.

RBSE Class 9 Maths Solutions Chapter 3 Coordinate Geometry Exercise 3.3

Question 1.
In which quadrant or on which axis do each of the points (- 2, 4), (3, – 1), (- 1, 0), (1, 2) and (- 3, – 5) lie? Verify your answer by locating them on the Cartesian plane.
Answer:
(i) In the point (- 2, 4), abscissa is negative and ordinate is positive. So, it lies in the second quadrant.
(ii) In the point (3, – 1), abscissa is positive and ordinate is negative. So, it lies in the fourth quadrant.
(iii) The point (- 1, 0) lies on the negative x-axis.
(iv) In the point (1, 2), abscissa and ordinate are both positive. So, it lies in the first quadrant.
(v) In the point (- 3, – 5), abscissa and ordinate are both negative. Therefore, it lies in the third quadrant.
Locations of the points are shown in the figure given below:

These points are respectively represented by A, B, C, D and E which clearly verify their locations in the pointed quadrant and axis.

Question 2.
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.

Answer:
Draw X’OX and YOY’ as the coordinate axes and mark their point of intersection O as the origin (0, 0).
To plot the point (- 2, 8), we take 2 units on OX’ and then 8 units parallel to OY to obtain the point A(- 2, 8).
Similarly, we plot the point B(- 1, 7).
To plot (0, – 1.25), we take 1.25 units below x-axis on the y-axis to obtain
To plot (1, 3), we take 1 unit on OX and then 3 units parallel to OY to obtain the point D(1, 3).
To plot (3, – 1), we take 3 units on OX and then move 1 unit parallel to OY’ to obtain the point E(3, – 1).