RBSE Solutions for Class 5 Maths Chapter 10 Currency Additional Questions is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Additional Questions.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 10 |

Chapter Name |
Currency |

Exercise |
Additional Questions |

Number of Questions |
25 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Additional Questions

**Multiple Choice Questions**

Question 1.

If the rate of potato is 12 Rs. per kg. then cost of 15 kg potato is-

(a) 150 Rupees

(b) 180 Rupees

(c) 170 Rupees

(d) 190 Rupees

Question 2.

If the rate of tomato is 10 Rs. per kg. then what amount to be paid to vegetable seller on buying 10 kg. tomato :

(a) 250 Rupees

(b) 35 Rupees

(c) 200 Rupees

(d) 300 Rupees

Question 3.

A vegetable trader bought coriander at (RBSESolutions.com)rate of 28 Rs. per kg. How much amount he paid for 5 kg coriander ?

(a) 33 Rupees

(b) 150 Rupees

(c) 160 Rupees

(d) 140 Rupees

Question 4.

A trader bought 15 kg. cauliflower(RBSESolutions.com)at the rate of 18 Rs. per kg. How much he paid-

(a) 250 Rupees

(b) 260 Rupees

(c) 270 Rupees

(d) 280 Rupees

Question 5.

How much amount did trader paid when he bought 7 kg. Taro (Arabi) at the rate of 36 Rs. per kg.

(a) 240 Rupees

(b) 252 Rupees

(c) 250 Rupees

(d) 260 Rupees

Question 6.

To find price of item we perform ……. between quantity and rate.

(a) Addition

(b) Subtraction

(c) Multiplication

(d) Division

Question 7.

Price of 3 kg. of rice at(RBSESolutions.com)the rate of 45 Rs. per kg. is-

(a) 135 Rupees

(b) 50 Rupees

(c) 15 Rupees

(d) 1350 Rupees

Question 8.

Total price of the item listed in a bill is find out by-

(a) Adding

(b) Subtracting

(c) Multiplying

(d) Dividing

Question 9.

If the rate of oil is ७२ Rs. ५॰ paise per kg. then cost of % kg oil is-

(a) ७५२ Rs. ५॰ paise

(b) ६५२ Rs. ५॰ paise

(c) ६५२ Rs. ५॰ paise

(d) ८२५ Rs. ५॰ paise

Answers.

1. (b)

2. (a)

3. (d)

4. (c)

5. (b)

6. (c)

7. (a)

8. (a)

9. (c)

Question 10.

**In the following fill in the blanks-**

1. 100 paisa = ……. Rupee

2. More than one items purchased then ……. all the list price in bill.

3. २२५ Rs. x ३ = ……. Rs.

4. १॰८ Rs. ÷ ९ = ……. Rs.

5. The shopkeeper calculates(RBSESolutions.com)the price of the goods on the purchase of each- item and gives a slip called ……. .

Answers.

1. 1

2. Add

3. ६७५ Rs.

4. १२

5 . Invoice or Bill

**Very Short Answer Type Questions**

Question 1.

If the price of 1 kg. ghee is 380 Rs. and the price of 1 kg. oil is 95 Rs. then price of how much kg oil is equal to price of 1 kg ghee ?

Solution.

According to rate list price of 1 kg ghee = 380 Rs.

and price of 1 kg. oil = 95 Rs.

Therefore price of 4 kg. oil is equal to the price of 1 kg. ghee.

Question 2.

In the rate list of shop, price of 1 kg. Tuar dal is 70 Rs. and Price of 1 kg. ghee is 380 Rs. then find out one buying 10 kg. tuar dal or 2 kg. ghee, you will have to pay more money.

Solution.

According rate list

Price of 10 kg. Tuar Dal = 70 x 10 = 700 Rs.

and price of 2 kg. ghee = 380 x 2 = 760 Rs.

Therefore we see that we(RBSESolutions.com)will have to pay more money for ghee.

Question 3.

Sheela puts a dupatta shop in the hot market. This time she took 32 dupatta with her. The price of one was 60 Rs. Her 8 dupatta Solution. d out. Find out how many rupees she got ?

Solution.

Price of 8 dupatta at (RBSESolutions.com)rate of 60 Rs. per dupatta = 60 x 8 = 480 Rupees

Question 4.

Add 9 Rs. 50 paise and 12 Rs. 75 paise.

Solution.

Therefore, 9 Rs. 50 paise + 12 Rs. 75 paise = 22 Rs. 25 paise.

Question 5.

Subtract 9 Rs. 50 paise from 12 Rs. 40 paise.

Solution.

40 paise – 90 paise not possible

Therefore 12 Rs. – 1 Rs = 11 Rs.

and 1 Rs. = 100 paise.

⇒ 100 paise + 40 paise = 140 paise

140 Paise – 90 paise = 50 paise

Now, 11 Rs. – 9 Rs. = 2 Rs.

Therefore, 11 Rs. 140 paise – 9 Rs. 90 paise = 2 Rs. 50 paise

Therefore 12 Rs. 40 paise – 9 Rs. 90 paise = 2 Rs. 50 paise.

Question 6.

Solve : 7 Rs. 25 paise x 5.

Solution.

Therefore, 7 Rs. 25 paise x 5 = 36 Rs. 25 paise.

Question 7.

Solve : 47 Rs. 32 paise ÷ 7

Solution.

Therefore, 47 Rs. 32 paise ÷ 7 = 6 Rs. 76 paise.

Question 8.

A studnet bought (RBSESolutions.com)for १३४ rupees ६॰ paise and copies for २८॰ rupees ५॰ paise. What is his total expenditure ?

Solution.

**Short Answer Type and Essay Type Questions**

Question 1.

Ram went to market with ५३७ rupees ६॰ paise to buy vegetable. He bought potato for १५८ rupees ८॰ paise and tomato for २४६ rupees and ९॰ paise. How much money is left with him ?

Solution.

Question 2.

Price of a table is ८२६ rupees ४॰ paise and price of a(RBSESolutions.com)chair is ५४५ rupees ७॰ paise. Find out the total price of ५ tables and ६ chairs.

Solution.

Question 3.

If १४ packets of the pen is priced at ९८६ rupees २२ paise then, find out the price of a packet.

Solution.

Question 4.

Rupchand resident of Puskar bought following items from Rajasthan Stationers Krishan Ganj, Ajmer-

(1) 18 Practice notebook, at the rate of 4 rupees 75 paise per notebook.

(2) 1 geometry box, at the rate of 32 rupees.

(3) 10 pencils, at the rate of 1 rupee 25 paise per pencil.

(4) 5 pen, at the rate(RBSESolutions.com)of 18 rupees per pen.

(5) 1 liter gum, at the rate of 90 rupees 25 paise.

(6) 12 register, at the rate of 30 rupees per register.

(7) 5 diaries, at the rate of 60 rupees per diary.

Prepare a bill of the above purchased items.

Solution:

**Bill of all purchased items is as follows**

Question 5.

Smt. Kanta Wairagi went to Bharat general store, Dailwas of her locality to purchase things of need. Where she bought ५ kg. rice at the rate of ६५ Rs./Kg. ४ liter oil at the(RBSESolutions.com)rate of ८॰ Rs./Liter, ५॰॰ gram tea at the rate of २४॰ Rs./Kg., ६ kg. sugar at the rate of २८ Rs./kg. and ५॰॰ gram turmeric at the rate of १४॰ Rs./kg. Prepare a bill made by shopkeeper.

Solution.

**Shopkeeper made bill like as following-**

Smt. Kanta asked to shopkeeper which type of numbers are written on the bill. He told that, this is Devanagari Script digit of Hindi.

Question 6.

Ganesh purchased the following items from “Swadeshi General Store” Bharatpur.

(1) 3 kg rice at the rate of Rs. 40 and 25 paise per kg.

(2) 2 litres of oil at the(RBSESolutions.com)rate of Rs. 75 and 60 paise per kg.

(3) 4 kg of sugar at the rate of Rs. 41 per kg.

Find the total expenditure made by Ganesh by making the bill iti the following format.

Solution:

Question 7.

Madhu bought the following articles from a book store-

(1) 8 pencils at the rate of ₹ 4 per pencil.

(2) 5 exercise books at the rate of ₹ 5 per exercise book.

(3) 4 pens at the(RBSESolutions.com)rate of ₹ 10 per pen.

(4) 2 colour boxes at the rate of ₹ 9 per color box.

Prepare a bill for the above purchase in given bill performa and tell how much money Madhu spent ?

Solution:

We hope the RBSE Solutions for Class 5 Maths Chapter 10 Currency Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Additional Questions, drop a comment below and we will get back to you at the earliest.

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