RBSE Solutions for Class 5 Maths Chapter 3 Multiplication and Division Additional Questions is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 3 Multiplication and Division Additional Questions.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 3 |

Chapter Name |
Multiplication and Division |

Exercise |
Additional Questions |

Number of Questions |
21 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 3 Multiplication and Division Additional Questions

**Multiple Choice Questions**

Question 1.

Number comes on multiplying 220 by 50-

(a) 27000

(b) 225

(c) 11000

(d) 1100

Question 2.

Product on multiplying 456 by 0-

(a) 4560

(b) 0

(c) 450

(d) 405

Question 3.

If there is 12 biscuits in a Parle G biscuit packet, then(RBSESolutions.com)number of biscuits in 250 packets-

(a) 238

(b) 262

(c) 412

(d) 3000

Question 4.

Number obtained on multiplying ९९ by १-

(a) ९९

(b) १00

(c) ९९१

(d) १९९

Question 5.

If the cost of 12 pencils is ₹ 24, then cost of one pencil is-

(a) 10 Rupees

(b) 5 Rupees

(c) 2 Rupees

(d) 1 Rupee

Question 6.

If 300 match sticks put in 10 match boxes then(RBSESolutions.com)number of match sticks in each box is –

(a) 3000

(b) 320

(c) 30

(d) 10

Question 7.

Value of 352 ÷ 16

(a) 176

(b) 0

(c) 22

(d) 48

Question 8.

Value of ११११ ÷ ११

(a) ११

(b) १0१

(c) १११

(d) १00

Answers

1. (c)

2. (b)

3. (d)

4. (a)

5. (c)

6. (c)

7. (c)

8. (b)

**Fill in the blanks in following questions**

1. 225 × 3 = ……………..

2. If 100 is(RBSESolutions.com)multiplied by zero then product is ……………..

3. Value of 125 × 26 is ……………..

4. Value of ५६ × ४0 is ……………..

5. Quotient of ४00 ÷ ४0 is ……………..

Answers

1. 675

2.0

3. 3250

4. २२४0

5. २0

**Very Short Answer Type Questions**

Question 1.

Write the product of 684 multiplied by 112.

Solution.

76608

Question 2.

Write the value of ५१६ × २२0

Solution.

११३५२0

Question 3.

Write the Quotient when 990 divided by 11.

Solution.

990 ÷ 9= 110

Question 4.

Solve 432 ÷ 12

Solution.

432 ÷ 12 = 36

Question 5.

If the cost of 7 pots is ₹ 350 then find the cost of 1 pot.

Solution.

350 ÷ 7 = 50

Question 6.

Value of ५५५ ÷ ५

Solution.

५५५ ÷ ५ = १११

**Short Answer and Essay Type Questions**

Question 1.

How many plants(RBSESolutions.com)will be there in 206 flowerbeds if each flowerbed has 144 plants.

Solution.

Total number of flowerbeds = 206

Number of plants in one flowerbed = 144

∴ Total number of plants in 206 flowerbeds

Therefore, 29664 plants are there in 206 flowerbeds.

Question 2.

How many garlands can be(RBSESolutions.com)made from 880 flowers if each garland is made up of 16 flowers.

Solution.

Number of flowers in 1 garland = 16

Total number of flowers = 880

∴ Number of garlands can be made

Therefore, 55 garlands can be made.

Question 3.

Mahesh has 345 toffees. He wants to distribute then(RBSESolutions.com)among his 16 friends equally. Find out how many toffees each one will get and how much toffee will remain with him.

Solution.

Total toffees Mahesh has = 345

No. of friends = 16

Share of each friend = 345 ÷ 16

Therefore, share of(RBSESolutions.com)each friend is 21 toffees and 9 toffees left un shared.

Question 4.

Solve 887 ÷ 19

Solution.

Here Quotient = 46 and Remainder = 13

Question 5.

८६ books can be put in a box. Then how many books can stored in १८ boxes?

Solution.

Number of books(RBSESolutions.com)put in 1box = ८६

Therefore, number of books stored in १८ boxes = ८६ × १८

Question 6.

९४४ Laddoos can be put in a group of ४ – ४ in boxes, then what is the number of boxes needed ?

Solution.

**b**

We hope the RBSE Solutions for Class 5 Maths Chapter 3 Multiplication and Division Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 3 Multiplication and Division Additional Questions, drop a comment below and we will get back to you at the earliest.

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