RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Negative Numbers and Integers |

Exercise |
Ex 4.3 |

Number of Questions |
4 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3

Question 1.

Subtract the (RBSESolutions.com) following.

(i) + 32 – (+12)

(ii) + 7 – (+15)

(iii) (-14) – (-20)

(iv) (-30) – (-15)

(v) 23 – (-10)

(vi) (-27) – 22

Solution.

(i) + 32 – (+12) = 32 – 12 = 20

(ii) + 7 – (+15) = 7 – 15 = – 8

(iii) (-14) – (-20) = – 14 + 20 = 20 – 14 = 6

(iv) (-30) – (-15) = – 30 + 15 = 15 – 30 = – 15

(v) 23 – (-10) = 23 + 10 = 33

(vi) (-27) – 22 = – 27 – 22 = – 49

Question 2.

Fill in the (RBSESolutions.com) blanks.

(i) – 5 + ………………… = 0

(ii) 7 + ………………… = 0

(iii) 11 + (-11) = …………………

(iv) (- 3) + ………………… = – 7

(v) 14 – ………………… = 16

(vi) (- 4) + ………………… = – 8

Solution.

(i) -5 + 5 = 0

(ii) 7 + (-7) = 0

(iii) 11 + (-11) = 0

(iv) (-3) + (-4) = – 7

(v) 14 – (- 2) = 16

(vi) (-4) +(-4) = – 8

Question 3.

Fill in the blanks (RBSESolutions.com) with the sign > , < or =

(i) (-2) + (-9) …………….. (-2) + (-4)

(-21) + (-10) …………….. (-10) + (-21)

(iii) 45 – (-12) …………….. (-12) + 45

(iv) (- 14) + (14) …………….. (-7) + (1)

Solution.

Filling the blanks with sign

(i)( -2) + (-9) = -2 -9 = – 11

and (-2) + (-4) = -2 -4 = – 6

∴(-2) + (-9) < (-2) + (-4)

(ii) (- 21) + (- 10) ……….. (- 10) + (- 21)

(-21) + (-10) = – 21 – 10 = – 31

and (-10) + (-21) = -10 -21 = -31

∴ (-21) + (-10) = (-10) + (-21)

(iii)45- (-12) (- 12) + 45

45 – (-12) = 45 + 12 = 57

and (-12) + 45 = -12 + 45 = 33

∴ 45- (-12) > (-12) + 45

(iv) (-14) + (14) ……………….. (-7) + (1)

(-14) + (14) = -14 + 14 = 0

and (-7) + (1) = 7 + 1 = -6

∴ (-14) + (14) > (-7) + (1)

Question 4.

Find the value (RBSESolutions.com) of the following.

(i) (-7) + (-4) + 11

(ii) (-12) + (-3) – (-4)

(iii) 14 – 8 – (-2)

(iv) (- 24) + (-12) – (-8)

Solution.

(i) (-7) + (-4) + 11

= -7 -4 +11 = -11 + 11 = 0

(ii) (-12) + (-3) – (-4)

= -12 -3 + 4 = -15 + 4 = -11

(iii) 14 – 8 – (-2) = 14 – 8 + 2

= 14 + 2- 8= 16 – 8 = 8

(iv) (-24) + (-12) – (-8)

= -24 -12 + 8 = -36 + 8 = -28

We hope the RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.3, drop a comment below and we will get back to you at the earliest.

## Leave a Reply