RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Exercise 6.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 6 |

Chapter Name |
Decimal Numbers |

Exercise |
Ex 6.1 |

Number of Questions |
10 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1

Question 1.

Write the numbers for the following (RBSESolutions.com) in the table given below :

(i) 1 tens 2 unit 3 one-tenths

(ii) 1 hundred 3 tens 7 one-tenths

(iii) 2 hundred 5 tens 1 unit 2 one-tenths

Solution.

On writting numbers in the table :

Question 2.

Write the place value of following (RBSESolutions.com) decimal numbers in a table.

(i) 19.4

(ii) 0.5

(iii) 10.9

(iv) 205.9

Solution.

On writing the place value of decimal numbers in a table :

Question 3.

Write each of the following (RBSESolutions.com) in the form of decimal :

(i) 7 one-tenths

(ii) 2 tens 4 one-tenths

(iii) Fourteen decimal nine

(iv) Six hundred point three

Solution.

On writing each in decimal form :

(i) 7 one-tenths = \(\frac { 7 }{ 10 } \) = 0.7

(ii) 2 tens 4 one-tenths 2 tens = 2 × 10 = 20

4 one-tenths = \(\frac { 4 }{ 10 } \) = 0.4

∴ 2 tens 4 one-tenths = 20.4

(iii) Fourteen point Nine = 14.9

(iv) Six hundred point three = 600.3

Question 4.

Represent the following in (RBSESolutions.com) form of decimal fractions :

(i) \(\frac { 3 }{ 10 } \)

(ii) 4 + \(\frac { 8 }{ 10 } \)

(iii) 300 + 50 + 8 + \(\frac { 1 }{ 10 } \)

(iv) 90 + \(\frac { 3 }{ 10 } \)

(v) \(\frac { 3 }{ 2 } \)

(vi) \(\frac { 2 }{ 5 } \)

(vii) 4 \(\frac { 1 }{ 2 } \)

(viii) 3 \(\frac { 3 }{ 5 } \)

Solution.

On representing each in form (RBSESolutions.com) of decimal fractions :

(i) \(\frac { 3 }{ 10 } \) = 0.3

(ii) 4 + \(\frac { 8 }{ 10 } \) = 4 + 0.8 = 4.8

(iii) 300 + 50 + 8 + \(\frac { 1 }{ 10 } \) = 358 + 0.1 = 358.1

(iv) 90 + \(\frac { 3 }{ 10 } \) = 90 + 0.3 = 90.3

(v) \(\frac { 3 }{ 2 } \) for making its denominator 10, multiply its numerator and denominator by 5 :

\(\frac { 3 }{ 2 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 15 }{ 10 } \) = 1.5

(vi) \(\frac { 2 }{ 5 } \) for making its denominator 10, multiply its numerator and denominator by 2 :

\(\frac { 2 }{ 5 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 4 }{ 10 } \) = 0.4

(vii) 4 \(\frac { 1 }{ 2 } \) = \(\frac { 9 }{ 2 } \)

for making its denominator 10, multiply its numerator and denominator by 5 :

\(\frac { 9 }{ 2 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 45 }{ 10 } \) = 4.5

(viii) 3 \(\frac { 3 }{ 5 } \) = \(\frac { 18 }{ 5 } \)

for making its denominator 10, multiply its numerator and denominator by 2 :

\(\frac { 18 }{ 5 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 36 }{ 10 } \) = 3.6

Question 5.

Write fractions for the following decimal (RBSESolutions.com) numbers and convert in the simplest form.

(i) 0.6

(ii) 2.5

(iii) 2.8

(iv) 13.7

(v) 21.2

(vi) 1.0

(vii) 6.4

Solution.

On writing decimal numbers as fractions and (RBSESolutions.com) converting them in simplest form :

Question 6.

Using centimeters convert the (RBSESolutions.com) following into decimal form :

(i) 2 mm

(ii) 30 mm

(iii) 116 mm

(iv) 5 cm 2 mm

(v) 95 mm

(vi) 19 cm 1 mm

Solution.

Question 7.

On the number line between which two whole (RBSESolutions.com) numbers, the following numbers are marked? Which whole number of these is closer to the decimal number?

(i) 0.5

(ii) 5.3

(iii) 9.0

(iv) 4.9

(v) 3.8

Solution.

On checking given each decimal number on number line :

∵ 0.5 is equally near from 0 and 1, but we let it closer to 1, because (RBSESolutions.com) when last point of number is 5 or more than 5, then it will be closer to next number.

Questions 8.

Show the following (RBSESolutions.com) on number line.

(i) 0.3

(ii) 1.7

(iii) 3.4

(iv) 2.5

Solution.

Question 9.

The length of Tulsi’s hand grip is 95 m.m. Write (RBSESolutions.com) it in cm form.

Solution.

The length of Tulsi’s hand grip = 95 mm

∵ 10 mm = 1 cm

∴ 95 mm = \(\frac { 1 }{ 10 } \) × 95 cm = \(\frac { 95 }{ 10 } \) = 9.5 cm

Thus, length of Tulsi’s hand grip is 9.5 cm

Question 10.

Deepu has a 6 cm. scale. It has been broken at 4.4 cm. What is the length of the left piece of scale?

Solution.

Total length of scale = 6 cm

Length of broken scale = 4.4 cm Thus, length (RBSESolutions.com) of remaining scale = (6 – 4.4) cm = (6.0 – 4.4) cm = 1.6 cm

We hope the RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Exercise 6.1, drop a comment below and we will get back to you at the earliest.

## Leave a Reply