RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression Additional Questions.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Algebraic Expression |

Exercise |
Additional Questions |

Number of Questions |
17 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression Additional Questions

**Multiple Choice Questions**

Question 1

Coefficient of x^{2} in 5x^{2} will be :

(A) 1

(B) 4

(C) 0

(D) 5

Question 2

Factors of 7y^{3} will be :

(A) 7, y, y, y

(B) 7,

(C) 7, y

(D) 0

Question 3

What will be the result (RBSESolutions.com) if we subtract 8xy from 10xy?

(A) 18xy

(B) 2xy

(C) xy

(D) 10xy

Question 4

If x = 4 then value of 2x + 8 will be :

(A) 16

(B) 8

(C) 10

(D) 18

Question 5

Number of (RBSESolutions.com) terms in 5xy + 5y + 2 will be :

(A) 2

(B) 4

(C) 3

(D) 1

Question 6

The value of 10xy + 5xy + y^{2}+ 4y^{2} will be :

(A) 15xy + 8y^{2}

(B) 15xy + 5y^{2}

(C) 10xy + y^{2}

(D) y^{2} + 8y

Answers:

1. (D), 2. (A), 3. (B), 4. (A), 5. (C), 6. (B)

**Fill in the Blanks :**

(i) The algebraic expression which (RBSESolutions.com) has three terms is known as ……….. expression.

(ii) In 9x^{3} + 8x + 5 the coefficient of x will be ……….. .

(iii) 8x^{3} + 9y^{2} + 5y^{2} + 4x^{3} = …………….

(iv) The value of algebraic expressions depends the value of ………….

Solution:

(i) trinomial

(ii) 8,

(iii) 12x^{3} + 14y^{2},

(iv) variable

**True/False**

(i) The algebaric expression on which (RBSESolutions.com) has only one term is known as monomial expression.

(ii) In 9x^{2}y coefficient of y is 9x^{2}.

(iii) 5xy + 8xy + 2xy = 15xy.

(iv) There are four terms in 3x^{2} + 9.

Solution:

(i) False

(ii) True

(iii) True

(iv) False

**Very Short Answer Type Questions**

Question 1

Subtract – 5xy from 9xy.

Solution:

9xy – (- 5xy) = 9xy + 5xy

= (9+ 5)xy = 14xy

Question 2

Find the (RBSESolutions.com) sum of 14xy + 9y and 6xy + 3y.

Solution:

(14xy + 9y) + (6xy + 3y)

= 14xy + 9 + 6xy + 3y

= 14xy + 6xy + 9 + 3y

= (14+ 6)xy + (9 +3)y

= 20xy + 12y

Question 3

If x = 4 and y = 2 then find the value of x^{2} – y^{2}.

Solution:

In (x^{2} – y^{2}) put x = 4 and y = 2

x^{2} – y^{2} = (4)^{2} – (2)^{2}

= 16 – 4 = 12

Question 4

How many terms are in (2x^{2} + 7x – 3)? Also (RBSESolutions.com) write the terms.

Solution:

(2x^{2} + 7x – 3)consists three terms, 2x^{2}, 7x and – 3.

Question 5

Write the coefficient of y in 6x^{2}y + 9x^{2}.

Solution:

In 6x^{2}y + 9x^{2} coefficient of y is 6x^{2}.

**Short Answer/Long Answer Type Questions**

Question 1

Draw the tree Sketch of (RBSESolutions.com) following algebraic expressions

(i) 2x^{2} – 3xy

(ii) 5xy + 10

Solution:

Question 2

Find out the (RBSESolutions.com) value of (i) 6x^{2} + 2x – 4 and (ii) x^{3}+ 6x – 2 if x = 2.

Solution:

(i) In 6x^{2} + 2x – 4 put x = 2

6x^{2} + 2x – 4 = 6(2)^{2} + 2(2) – 4

= 6 x 4 + 4 – 4

= 24 + 4 – 4

= 28 – 4 = 24

(ii) In x^{3} + 6x – 2 put x = 2

x^{3} + 6x – 2 = (2) + 6(2) – 2

= 8 + 12 – 2

= 20 – 2

= 18

Question 3

Simplify :

4x^{3} – [9x^{2} – { -5x^{3} – (2 – 7x^{2}) + 6x}]

Solution:

4x^{3} – [9x^{2} – { -5x^{3} – (7 + 7x^{2}) + 6x}}

= 4x^{2} – [9x^{2} – { -5 -2 + 7×2 + 6x}]

= 4x^{3} – [9x^{2} + 5x^{3} + 2 – 7x^{2} – 6x]

= 4x^{3} – 9x^{2} – 5x^{3} – 2 + 7x^{2} + 6x

= 4x^{3} – 5x^{3} – 9x^{2} + 7x^{2} + 6x – 2

= -x^{3} – 2x^{2} + 6x – 2

Question 4

Simplify the following algebraic (RBSESolutions.com) expression and find the value when x = 3, a = -1 and b = -2

(i) 3x – 5 – x +9

(ii) 2 – 8x + 4x +4

(iii) 3a + 5 – 8a +1

(iv) 10 – 3b – 4 – 5b

(v) 2a – 2b – 4 – 5 + a

Solution:

(i) 3x – 5 – x + 9 = 2x +4

Put x = 3

2x + 4 = 2(3) + 4 = 6 +4 = 10

(ii) 2 – 8x + 4x + 4 = 6 – 4x

Put x = 3

6 – 4x = 6 – 4(3) = 6 – 12 = -6

(iii) 3a +5 – 8a +1 = -5a + 6

Put a = -1

-5a + 6 = -5( -1) +6

= 5 + 6 = 11

(iv) 10 – 3b – 4 – 5b = 6 – 8b

Put b = -2

6 – 8b = 6 – 8(-2)

= 6 + 16 = 22

(v) 2a – 2b – 4 – 5 + a= 3a – 2b – 9

Put a = – 1 and b = -2

3a – 2b – 9 = 3(-1) – 2(- 2) – 9

= – 3 + 4 – 9 = -8

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