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Class 7

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise

June 3, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 2
Chapter Name Fractions and Decimal Numbers
Exercise In Text Exercise
Number of Questions 23
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise

Download and install Partial Fraction Calculator on Windows or MAC and enjoy Partial Fraction Calculator on big screen computers for free.

(Page 16)
Question
(i) You know that area of (RBSESolutions.com) a rectangle = length x breadth. But if length and breadth is given in fraction, then how will you find the area of rectangle?
(ii) Are you agree with that to find the area of a rectangle, we must know how to multiply two or more than fractional numbers?
Solution:
(i) If length and breadth are given in fractional numbers then the numerators are multiplied with numerators and denominators with denominators to find a fraction that is the area of a rectangle:
For example:
length = 4/5 unit and breadth = \(\frac { 3 }{ 7 }\)unit
Then area of rectangle = length x breadth
= \(\frac { 4 }{ 5 }\) x \(\frac { 3 }{ 7 }\) = \(\frac { 4\times 3 }{ 30 }\) = \(\frac { 5 }{ 7 }\)
= \(\frac { 12 }{ 35 }\) sq unit.
(ii) Yes. we are agree with that we must know, how to multiply two or more fractional numbers.

RBSE Solutions

(Page 19)
Question
Complete (RBSESolutions.com) the table:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 19
After completing the table, do you agree (RBSESolutions.com) that value of product of two proper fraction is less than the value of each fraction?
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 19a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 19b
yes, we are agree with that the product of two proper fraction is always less than the each fraction.

(Page 20)
Question
Complete (RBSESolutions.com) the table:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 20
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 20a
On completing the table we can say that the product of two improper fractions is greater than each fraction.

(Page 24)
Question
Interchange the numerator (RBSESolutions.com) and denominotor with each of the function \(\frac { 1 }{ 5 }\) and \(\frac { 2 }{ 3 }\).

(ii) Fill in the blanks :
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 24
Solution:
(i) After changing the numerator and denominator of \(\frac { 1 }{ 5 }\) required fraction = \(\frac { 5 }{ 1 }\) and after changing the numerator and denominator of \(\frac { 2 }{ 3 }\) required fraction = \(\frac { 3 }{ 2 }\)
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 24a

(Page 25)
Question
How can you (RBSESolutions.com) read those number
(1) 24.2 = Twenty four decimal two
(ii) 2.04 = Two decimal zero four
(iii) 325.52 = …………..
(iv) 56.32 = ……………
Solution:
(iii) 325.52 = Three hundred twenty five decimal five two.
(iv) 56.32 = Fifty six decimal three two.

How do we write 1/8 as a decimal? To convert 1/8 to a decimal, divide the denominator into the numerator.

RBSE Solutions

(Page 26)
Question
See the following (RBSESolutions.com) table and fill up the blanks:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 26
(ii) We can also write these numbers in their extended form
421.258 = 4 x 100 + 2 x 10 + 1 x 1 + 2 x \(\frac { 1 }{ 10 }\) + 5 x \(\frac { 1 }{ 100 }\) + 8 x \(\frac { 1 }{ 1000 }\)
Similarly write the (RBSESolutions.com) remaining numbers from above table.
120
(iii) Fill in the blanks : 120 m = \(\frac { 120 }{ 1000 }\)km = …… km.
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 26a
(ii) Extended form (RBSESolutions.com) of remaining numbers
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 26b

(Page 30)
Put decimal in –
Question
1.52 x 1000 = ….
Solution:
1.52 x 1000 = 1520.00

(Page 34)
Question
(i) There are 8 black and 7 white (RBSESolutions.com) strips in a zebra crossing. So tell what part of total strips is the number of white strips?
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 34
(ii) On a day 100 people crossed the road by zebra crossing out of which 20 are men, 30 women, 10 children and 40 students. Show all these data’s In decimal.
Solution:
(i) Total strips 8 + 7 = 15
Part of white strips (RBSESolutions.com) related with total strips.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 34a
∴ White strips are \(\frac { 7 }{ 5 }\) part of the total strips.

(ii) Total number of people = 100
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise 34b

RBSE Solutions

Do and Learn

(Page 14)

Let us write 5/8 as a decimal using the division method.

Question 1
Find five equivalent (RBSESolutions.com) fractions of \(\frac { 4 }{ 7 }\)
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K1
∴ Equivalent fractions of \(\frac { 4 }{ 7 }\) are = \(\frac { 8 }{ 14 }\), \(\frac { 12 }{ 21 }\), \(\frac { 16 }{ 28 }\), \(\frac { 20 }{ 35 }\), and \(\frac { 24 }{ 42 }\)

Question 2
Compare and (RBSESolutions.com) write (<,= ,>)
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K2
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K2a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K2b

(Page 18)
Question
Solve
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K3
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K3a

(Page 18)
Question
Solve
(i) 5 x \(\frac { 1 }{ 2 }\) = ?
(ii) 1\(\frac { 4 }{ 9 }\) x 6 = ?
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K4

RBSE Solutions

(Page 18)
Question
Solve
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K5
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K5a

(Page 19)
Question
Find
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K6
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K6a
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K6b

(Page 20)
Question
Find the product of one (RBSESolutions.com) proper and one improper fraction and prepare the table showing theresoult.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K7
Product is greater than proper and smaller then improper fraction.
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K7a
Product is greater than proper and smaller than improper fraction.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K7b
Product is greater than proper and smaller than improper fraction.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise K7c
Product is greater than (RBSESolutions.com) proper and smaller than improper fraction.

Product is greater than proper and smaller than improper fraction.

RBSE Solutions

(Page 24)
Question
Solve

Solution:

(Page 24)
Question
Fill in the blanks

Solution:

(Page 25)
Question
Solve

Solution:

(Page 26)
Question
Which (RBSESolutions.com) number is smaller?
(i) 35.37 and 35.07
(ii) 262.327 and 262.372
Solution:
(j) 35.07
(ii) 262.327

RBSE Solutions

(Page 29)
Question
Find the (RBSESolutions.com) value of
(1) 2.3 x 3.5
(ii) 37 x 5
(iii) 2.4 x 7.35
Solution:

(Page 32)
Question
Divide the given decimal (RBSESolutions.com) numbers by 10,100 and 1000?
(i) 132.4
(ii) 1.03
(iii) 40.033
(iv) 4.321
Solution:

(Page 32)
Question
(i) 6 ÷ 1.2
(ii) 9 ÷ 4.5
(iii) 48 ÷ 0.8
Solution:

RBSE Solutions

(Page 33)
Question
Solve
(i) 7.75 ÷ 0.25
(ii) 5.6 ÷ 1.4
(iii) 42.8 ÷ 0.02
Solution:

We hope the RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers In Text Exercise, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise

May 30, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 15
Chapter Name Comparison of Quantities
Exercise In Text Exercise
Number of Questions 16
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise

Do and Learn

(Page 159)
Question 1
Find the ratio of actual length and breadth (RBSESolutions.com) of mathematics book of class VII.
Solution:
Length of book = 27 cm.
Breadth = 15 cm
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 1

RBSE Solutions

Question 2
Find the ratio of length and breadth of national flag by taking help from your teacher.
Solution:
Different size of national flag (RBSESolutions.com) length and breadth ratio as follows :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 2

Question 3
Find the ratio of length and breadth (RBSESolutions.com) of your classroom by measuring it
Solution:
Let the length and breadth of room is 30 feet and 20 feet.
Ratio = 30 : 20 = \(\frac { 30 }{ 20 }\) = \(\frac { 3 }{ 2 }\) = 3 : 2

Question 4
Measure your height and measure the length by expanding both the hand completely. Now find out the ratio between these two quantities.
Solution:
Length of both hands = 60 cm
Self height = 120 cm
Ratio = 120 : 60
\(\frac { 120 }{ 60 }\) = \(\frac { 2 }{ 1 }\) = 2 : 1

(Page 162)

Percentage Difference calculator is a free online tool to find the percent difference between two numbers.

Question 1
25 students of class tell their (RBSESolutions.com) interests about games.
Kabbadi – 4 students
Cricket – 11 students
Chess – 6 students
Tennis – 3 students
Other games – 1 students
Express the number of students in percentage according to the interest in each game.
Solution:
Total students = 25
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 3

Percentage Difference calculator – online basic math function tool to calculate how much percent difference between two quantities or observations.

Question 2
Following results are obtained on taking (RBSESolutions.com) advice of 250 students of preference of menu of mid day meal is selected school of Jalore Panchayat.
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 4
Express the percentage of preference of each type of menu from the above results.
Solution:
Total number (RBSESolutions.com) of students = 250
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 5

RBSE Solutions

(Page 163)
Question 1
Convert the following (RBSESolutions.com) fractions into per-centage.
(i) \(\frac { 5 }{ 8 }\)
(ii) \(\frac { 5 }{ 3 }\)
Solution:
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 6

Question 2
Convert the decimal(RBSESolutions.com) fractions into percentage.
(i) 0.5
(ii) 0.08
(iii) 0.225
(iv) 6.5
Solution:
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 7
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 8

Question 3
Convert the percentage (RBSESolutions.com) into simple fraction and decimal fraction
(i) 36%
(ii) 12\(\frac { 1 }{ 2 }\)%
(iii) 3.6%
Solution:
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 9

(Page 166)

convert CGPA into percentage? Read this blog to understand an easy process to calculate percentage from CGPA.

Question 1
The population of a village is increased (RBSESolutions.com) to 15000 from 12000 in last 10 years. Then what is the percentage growth of population ?
Solution:
Population of village = 12000
Increased population of village in last 10 year = 15000
Increase in population = (15000 – 12000) = 3000
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 10

Question 2
Express rate of growth or loss in the (RBSESolutions.com) form of percentage in the following :
(1) The cost of electricity per unit has increased to ₹6.00 from ₹3.50
(2) The cost of 100 envelopes has decreased to ₹80 from ₹100.
Solution:
(1) Original rate per unit = ₹3.50
Increased rate per unit = ₹6
increase = 6 – 3.50 = ₹2.50
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise - 11
(2)100 envelopes cost = ₹100
New price = ₹80
Decrease in price = 100 – 80 = ₹20
Decrease % = \(\frac { 20 }{ 100 }\) x 100% = 20%

RBSE Solutions

(Page 168)
Question 1
Mahaveer bought 5 bags of sugar for ₹16000. He (RBSESolutions.com) spent ₹200 for taxi fare, ₹120 for labour charges and ₹200 for transporttation charges. Find the selling price of per kg of sugar so as to earn a profit of ₹3 on each kg.
Solution:
Cost of 5 bags of sugar = ₹16000
Other expenses = ₹200 + ₹120 + ₹200
= ₹520
∴ Total C.P. of 5 bags of sugar
= ₹16000 + ₹520 = ₹16520
∵ Profit on 1 kg = ₹3
Profit on 5 bags or 500 kg sugar
= 500 x 3 = ₹1500
So, Profit = S.P – C.P
or S.P = C.P + Profit
= 16520+ 1500 = ₹18020
So, S.P. of 5 bags = ₹18020
S.P. of 1 bag = \(\frac { 1820 }{ 5 }\) = ₹3604

Question 2
Manoj bought a second hand car for ₹1,50,000. He spent ₹60,000 on Its (RBSESolutions.com) engine repair and ₹15000 on replacing the tyre tubes. Manoj sold this car to Jitendra for ₹2,10,000 Calculate loss or gain in this business.
Solution:
Cost of car = ₹1,50,000
Expense on engine = ₹60,000
Expense on tyre & tube = ₹15,000
Total cost price = ₹2,25,000
Selling price = ₹2,10,000
Manoj has a loss
So, Loss = C.P – S.P
= 2,25,000 – 2,10,000
Loss = ₹15,000
Manoj has a loss of ₹ 15,000

Percentage Difference calculator – online basic math function tool to calculate how much percent difference between two quantities or observations.

(Page 170)
Ashok has borrowed ₹50000/- for the construction (RBSESolutions.com) of his house. This borrowed amount is known as Principal. He repays ₹55000 to that institute after one year.
Ashok paid ₹5,000/- extra on ₹50,000. This extra amount is known as interest.
The amount of interest depends on following things:
1. Borrowed money (Principal)
2. Time (Period for which the amount is borrowed).
3. Rate (The extra amount paid on per hundred) which is determined on the basis of per mounth/per annum.
You can find the amount you have to pay at the end of the year by adding sum borrowed and the interest
i.e., Amount = Principal + Interest

Question 1
How much interest would Ashok have pay after 2 years if he (RBSESolutions.com) was not able to return the money to the instutute after 1 year ?
Solution:
Because after one year he pays ₹5000/-
as interest so in 2 years he has to pay ₹10000/- as interest.

Question 2
How much money in (RBSESolutions.com) total has to be paid including interest?
Solution:
Amount = Principal + Interest
= 50,000 + 10,000
= ₹60,000/-

RBSE Solutions

We hope the RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities In Text Exercise, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions

May 30, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Exercise Additional Questions.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 15
Chapter Name Comparison of Quantities
Exercise Ex 15.4
Number of Questions 25
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions

Multiple Choice Questions

Question 1
Value of 5% is :
(A) 0.05
(B) 0.5
(C) 5
(D) 0.005

the percentage difference calculated dividing the absolute values.

Question 2
Value of \(\frac { 1 }{ 2 }\) in (RBSESolutions.com) percentage is :
(A) 80 %
(B) 50 %
(C) 25 %
(D) 15 %

RBSE Solutions

Question 3
Express \(\frac { 4 }{ 5 }\) in ratio is :
(A) 4 : 5
(B) 5 : 4
(C) 1 : 2
(D) 2 : 3

Question 4
\(\frac { 2 }{ 3 }\) is (RBSESolutions.com) equivalent to
(A) 66\(\frac { 2 }{ 3 }\)
(B) 65\(\frac { 2 }{ 3 }\)
(C) 62\(\frac { 2 }{ 3 }\)
(D) 60\(\frac { 2 }{ 3 }\)

Our percentage off calculator helps to calculate percent off by given number.

Question 5
Formula to find out profit percentage is :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 1

Question 6
Formula to (RBSESolutions.com) find out % increase
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 2.

Question 7
10 % of 50 will be :
(A)10
(B) 50
(C) 40
(D) 5

Question 8
What will be value of 75% in (RBSESolutions.com) decimal fractions?
(A) 73
(B) 7.3
(C) 0.73
(D) 0.073

Question 9
Mohan purchase a pen ₹10 and sold it in ₹12. Then profit will be :
(A) ₹2
(B) ₹3
(C) ₹4
(D) ₹6

RBSE Solutions

Question 10
Suresh purchased a book in ₹120 and (RBSESolutions.com) sold it on 10% loss then its selling price is :
(A) ₹100
(B) ₹110
(C) ₹108
(D) ₹115

Answer:
(1) (A), (2) (B), (3) (A), (4) (A), (5) (B), (6) (A), (7) (D), (8) (C), (9) (A), (10) (C)

You can convert CGPA to percentage with the simple formula of mutiplying CGPA with 9.5.

Fill in the blanks
(i) 10% of 100 will be …………..
(ii) Ratio of 2 km to 400 km will be ……………
(iii) Fraction \(\frac { 12 }{ 16 }\) is in percentage (RBSESolutions.com) form will be …………
Answer:
(i) 10,
(ii) 1 : 200,
(iii) 75%

True/False
(i) The ratio of ₹5 and 50 paise is 10 : 1.
(ii) 75% of 12 is 12\(\frac { 3 }{ 4 }\)
(iii) 35 % + 65 % = 100 %.
(iv) Fraction \(\frac { 1 }{ 8 }\) is (RBSESolutions.com) equivalent 12.5%.
Answer:
(i) True
(ii) False
(iii) True
(iv) True

Very Short Answer Type Questions

Question 1
Collection of 10 chips of various (RBSESolutions.com) colours is as follows :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 3
Fill the table and find out the percentage of every colour chips?
Solution:
The required percentage (RBSESolutions.com) of every colour chips is as follows :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 4

RBSE Solutions

Question 2
Find out following :
(a) 50% of 164
(b) 75% of 12
(c) 12\(\frac { 1 }{ 2 }\)% of 64
Solution:
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 5

Question 3
In the class of 25 children 8% children (RBSESolutions.com) like to wet in rain. Find out the number of children who like to wet in rain.
Solution:
Number of children who like to wet in rain = 8% of 25
= \(\frac { 8 }{ 100 }\) x 25 = 2

Question 4
9 is which number’s 25%?
Solution:
Let the number is x
25% of x = 9
⇒ \(\frac { 25 }{ 100 }\) × x = 9 ⇒\(\frac { 1 }{ 4 }\) × x = 9
⇒ x = 9 x 4 = 36
∴ Required number is 36.

Question 5
15 is which (RBSESolutions.com) number’s 75%?
Solution:
Let the number is x
75% of x = 15
⇒ \(\frac { 75 }{ 100 }\) x 1 = 15
\(\frac { 3 }{ 4 }\) x a = 15
⇒ 44 = 15 x \(\frac { 4 }{ 3 }\)
= 5 x 4 = 20
∴ Required number is 20.

Short Answer Type Questions

Question 1
In a computer lab 3 computers are required for 6 students. Find out (RBSESolutions.com) how many computers are required for 24 students?
Solution:
In a computer lab,
∵ 6 students required computers = 3
∴1 student required computers = \(\frac { 3 }{ 6 }\)
∴ 24 students required computers = \(\frac { 3 }{ 6 }\) x 24 = 3 x 4 = 12

RBSE Solutions

Question 2
Population of Rajasthan is 570 lac and population (RBSESolutions.com) of Uttar Pradesh is 1660 lac. Area of Rajasthan is 3 Lac square km and area of Uttar Pradesh is 2 lac square km.
(i) In both states how many people are per square km.
(ii) Which state is having less population density?
Solution:
(i) Population of Rajasthan = 570 lac
Area of Rajasthan = 3 lac sq. km
∴ Number of people per square km = \(\frac { 570 }{ 3 }\) = 190
And population (RBSESolutions.com) of Uttar Pradesh = 1660 lac
Area of Uttar Pradesh = 2 lac sq. km
∴ Number of people per square km
= \(\frac { 1660 }{ 2 }\)
= 830
(ii) Because per square km less people are living in Rajasthan. So, Rajasthan is having less population density.

Question 3
Find out
(a) 15% of 250
(b) 1% of an hour
(c) 20% of 2500
(d) 75% of 1kg
Solution:
(a) 15% of 250 = \(\frac { 15 }{ 100 }\) x 250
= 15 x 2.5 = 37.5

(b) 1% of 1 hour = 1% of 60 minutes
= \(\frac { 1 }{ 100 }\) x 60 = \(\frac { 6 }{ 100 }\) minutes
= \(\frac { 6 }{ 10 }\) x 60 second = 36 second

(c) 20% of 2500 = \(\frac { 20 }{ 100 }\) x 2500
= 20 x 25 = 500

(d) 75% of 1 kg = 75% of 1000 gm
= \(\frac { 75 }{ 100 }\) x 1000 = 750 gm = 0.75 kg.

Long Answer Type Questions

Question 1
In chalk powder calcium, carbon and oxygen (RBSESolutions.com) ratio are 10 : 3 : 12. Find out the carbon percentage.
Solution:
Calcium : Carbon : Oxygen
10 : 3 : 12
Total of ratio = 10 + 3 + 12 = 25
Parts of carbon in chalk = \(\frac { 3 }{ 25 }\)
∴ Percentage of carbon in chalk = ( \(\frac { 3 }{ 25 }\) x 100)%
= (3 x 40)%
= 12%

Question 2
Amina purchase a book in ₹275 and sold it on 15 percent loss, then (RBSESolutions.com) find out the selling price of the book.
Solution:
C.P. of book = ₹275
Loss = 15%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 6

Question 3
In every condition after 3 years how much amount (RBSESolutions.com) has to be paid if principal = ₹1200, rate = 12% P.A.
Solution:
Principal = ₹1200, Rate = 12%. Time = 3 years
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 7

Question 4
Arun purchased a car in ₹3,50,000 and next year its price (RBSESolutions.com) has increased up to ₹3,70,000. Find the percentage increase in the price of car.
Solution:
Original Price = ₹3,50,000
Increased Price = ₹3,70,000
Increment in Price = ₹(3,70,000 – 3,50,000)
= ₹20,000
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 8

RBSE Solutions

Question 5
I have purchased a T.V. in ₹10,000 and taking 20% profit it has (RBSESolutions.com) been sold out. How much money I received on selling of this ?
Solution:
C.P. = ₹10,000, Profit = 20%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 9

Question 6
On selling a washing machine in ₹13500, Juhi bears a loss of 20%. What was (RBSESolutions.com) the cost price of washing machine?
Solution:
S.P. = ₹13,500, loss = 20%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 10
∴ C.P. of washing machine = ₹16,875

We hope the RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1

May 28, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Exercise 4.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 4
Chapter Name Rational Numbers
Exercise Ex 4.1
Number of Questions 10
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Ex 4.1

Welcome to our step-by-step math rational expressions calculator.

Question 1
Write five rational numbers equivalent to (RBSESolutions.com) the following ratinal numbers
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 1
Solution:
(i) Five equivalent rational numbers of –\(\frac { 2 }{ 3 }\) are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 2

(ii) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { 1 }{ 5 }\) are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 3

(iii) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { -5 }{ 3 }\) are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 4

(iv) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { 4 }{ -9 }\) are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 5

.RBSE Solutions

Question 2
Write three such (RBSESolutions.com) rational numbers equivalent to \(\frac { -5 }{ 12 }\) in which the denominator is 60, – 96 and 108.
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 6

Question 3
Write three such rational (RBSESolutions.com) numbers equivalent to \(\frac { -3 }{ 7 }\) in which the numerator is 24, – 60 and 75.
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 7

Question 4
Write the following rational numbers in the (RBSESolutions.com) simplest from (standard forms) :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 8
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 9

Question 5
Represent the following rational numbers (RBSESolutions.com) on number line :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 10
Solution:
(i) We know that \(\frac { 3 }{ 5 }\) is greater than 0, so \(\frac { 3 }{ 5 }\) will be in between 0 and 1.
Now to represent \(\frac { 3 }{ 5 }\) on number line, the distance between 0 and S is divided in 5 equal parts and take three parts from it to mark point P. This way point P represents point \(\frac { 3 }{ 5 }\) .
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 45

(ii) We know (RBSESolutions.com) that \(\frac { 7 }{ 8 }\) is greater than 0 and less than 1.
∴ \(\frac { 7 }{ 8 }\) will be in between 0 and 1.
Now to represent \(\frac { 7 }{ 8 }\) on number line, distance between 0 and 1 is divided in 8 equal parts and take 7 parts from it to mark point P. Thus point P represent point \(\frac { 7 }{ 8 }\).
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 12

(iii) We know that \(\frac { -8 }{ 3 }\) or -2\(\frac { 2 }{ 3 }\), is greater than -3 and less than – 2 so \(\frac { -8 }{ 3 }\), will be in between -2 and – 3.
Now on number line, the (RBSESolutions.com) distance between – 2 and – 3 divided in 3 equal parts and take 2 parts from it to mark point P. This way point P represents point \(\frac { -8 }{ 3 }\).

(iv) We know that -2\(\frac { 1 }{ 2 }\) or \(\frac { -5 }{ 2 }\), is greater from – 3 and less than – 2 so \(\frac { -5 }{ 2 }\) will be in between – 2 and -3.
Now to represent \(\frac { -5 }{ 2 }\) on number line, the distance between -2 and -3 is divided in 2 equal parts and take one part from it to mark point P.
This way point P represent (RBSESolutions.com) the point –\(\frac { 5 }{ 2 }\) ( -2\(\frac { 1 }{ 2 }\)) or number line.

(v) We know that \(\frac { 5 }{ 7 }\) is greater than 0 and less than 1.
\(\frac { 5 }{ 7 }\), will be in between 1 and 1.
Now to represent \(\frac { 5 }{ 7 }\) on number line, the distance between 0 and 1 is divided in 7 equal parts and take 5 parts to make point P. This way point P

represents \(\frac { 5 }{ 7 }\) on number line.

RBSE Solutions

Question 6
Choose the correct (RBSESolutions.com) sign from <, >, = and fill in the blanks :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 44
Solution:
(i) We know that positive rational numbers are greater than negative rational numbers
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 img 43

(ii) L.C.M. of (RBSESolutions.com) denominator 4 and 3 is 12
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 6

RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 6a

(iii) L.C.M. of (RBSESolutions.com) denominator – 5 and 3 is 15
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 6b

(iv) L.C.M. of 7 and 2 is 14
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 6c
(vi) We know that negative rational (RBSESolutions.com) numbers are smaller than positive rational number.

RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 6d

Question 7
Write five rational numbers between fol-lowing rational numbers :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7a
We know that integers (RBSESolutions.com) between -9 and -3 are
⇒ -8 < -7 < -6 < -5 < -4
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7b
∴ Five rational numbers between – 9 and – 3 will be:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7c
We know that integers (RBSESolutions.com) between 0 and -6 are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7d
∴ Five rational numbers between 0 and -1
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7e
∴ Five rational numbers (RBSESolutions.com) between -56 and – 50 are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7f
We know that integers between 12 and 6 are :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7g
∴ Five rational (RBSESolutions.com) numbers between \(\frac { 1 }{ 2 }\) and \(\frac { 1 }{ 4 }\) are
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7h

(v) We know that integers between 2 and -4 are:
-4 < -3 < -2 < -1 < 0 < 1 < 2
∴ Five rational numbers between \(\frac { 2 }{ 5 }\) and \(\frac { -4 }{ 5 }\) will be
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 7i

RBSE Solutions

Question 8
Write three more rational (RBSESolutions.com) numbers in each of the following :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 8
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 8a
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 8b

Question 9
Write the (RBSESolutions.com) following rational number in increasing order :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9
Solution:
(i) ∵ Denominators of given rational numbers are positive.
∴ L.C.M of 2, 2, 4 and 4 = 4 on making denominator of each = 4
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9a
∵ Denominators of (RBSESolutions.com) rational numbers are positive
∴ L.C.M. of 2, 4 and 7 = 28 on making the denominator of each = 28
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9b
∴ Increasing order is
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9c
∵ Denominator of rational (RBSESolutions.com) numbers are positive.
∴ L.C.M of 11, 15, 1, 1 and 15 = 165
on making denominator of each = 165
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9d
∵ Denominator of rational number are positive
∴ L.C.M of 5, 7, 6, 9 = 630 on making (RBSESolutions.com) denominator of each = 165
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 9e

RBSE Solutions

Question 10
Write the following rational (RBSESolutions.com) numbers is decreasing order :
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10
Solution:
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10a
on making (RBSESolutions.com) the denominator 48 of each
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10b
∵ Denominator of rational number (RBSESolutions.com) are positive
∴ L.C.M of 6, 6, 9, 12 = 36
on making denominator 36 of each
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10c
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10d
on making (RBSESolutions.com) denominator 6 of each
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10e
on making (RBSESolutions.com) denominator 30 of each
RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 10f

RBSE Solutions

We hope the RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Exercise 4.1, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution

May 27, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 1

RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution are part of RBSE Solutions for Class 7 Science. Here we have given Rajasthan Board RBSE Class 7 Science Chapter 7 Organic Evolution.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Science
Chapter Chapter 7
Chapter Name Organic Evolution
Number of Questions Solved 49
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Science Chapter 7 Organic Evolution

MCQ CBSE Class 6 Science MCQ CBSE Class 7 Science MCQ CBSE Class 8 Science MCQ CBSE Class 9 Science MCQ CBSE Class 10 Science.

Textbook Exercise

Multiple Choice Questions

Choose the correct option
Question 1.
Heart of fish has
(a) One auricle one ventricle
(b) One auricle two ventricles
(c) Two auricles one ventricle
(d) Two auricles two ventricle
Answer:
(a) One auricle one ventricle

Question 2.
Archaeopteryx is a connecting link between
(a) Pisces and amphibian
(b) Reptiles and Aves
(c) Aves and mammals
(d) Amphibians and reptiles
Answer:
(b) Reptiles and Aves

Question 3.
Which Scientist gave a theory of mutation
(a) Lamarck
(b) Darwin
(c) Hugo de Vries
(d) Mendel
Answer:
(c) Hugo de Vries

Question 4.
Forelimb of whale is called as
(a) Flipper
(b) arm
(c) wing
(d) leg
Answer:
(a) Flipper

Fill in the blanks
1. Wings of bird and bat are …………. organ.
2. Vertebral Column is consists of small …………..
3. Every organisms, in its development, repeat its ……………. history.
4. Organic evolution is a ……………… and process.
5. Darwin gave Theory of ……………
Answer:
1. Analogous
2. Vertebrae
3. Organic
4. slow, gradual
5. Natural selection

Short Answer Type Questions
Question 1.
Write differences between homologous and analogous organs.
Answer:

Homologous organs Analogous organs
Organs of different animals which have similar basic structure and origin. Organs which have different basic structure and origin.
They have different functions. They have same functions.

Question 2.
Write the process of fossils formation.
Answer:
The dead body of organisms were buried under rocks especially sedimentary rocks. As the time passes, their remains are left in these rocks. These are known as fossils. Some times, whole body of organisms changes into fossils.

Question 3.
Draw a structure of hearts of different animals to show sequence of organic evolution.
Answer:
RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 1
Question 4.
Define Lamarck’s Theory of evolution with examples.
Answer:
According to Lamarck, the organs which are frequently used were developed more whereas the organs which were used less frequently perish. For example, as a result of more use of neck and fore limbs of African giraffe, these organs increase in size.

Question 5.
What is mutation?
Answer:
In some organisms, suddenly some changes take place. These changes transfer from one generation to another. These sudden changes in an organism which transfer from one generation to another are called mutations.

Long Answer Type Questions
Question 1.
Explain evolution on the basis of evidences of embryology.
Answer:
Evidences from Embryology: In multicellular organisms, zygote is formed as a result of sexual reproduction.RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 2
When we see fish, turtle,chicken, human’s embryo, early stages of them appears almost identical. This proves that the ancestors of all vertebrates resemble with fish and their development is certainly in order. Every organisms in its development repeats its organic history called as Theory of Recapitulation. This theory was proposed by German Scientist Haeckel.

Question 2.
Clarify different steps of Darwin’s Theory.
Answer:
Charles Robert Darwin’s gave a theory of natural selection for organic evolution. Different phases of Darwin’s theory are as under:
1. Production of off spring in living organisms: Each organism does production of off springs to maintain their race. Example, elephant produces 8 off springs in her life span. It is a slow breeder. A pair of elephant began to breed regularly and engender that all off springs are regularly breeding in the 750 years a pair will generate approximately 1.9 million elephants and number of elephants will be very high. But this does not happen.

2. The struggle for survival: Due to over production of off springs, the struggle for space and food for the growing number of offspring takes place. It is the struggle of survival. This struggle occurs in between animals of own species; and with other species also which is capable of the same shall live. Destruction due to struggle, the number of organisms will remains balanced and consistence in nature.

3. Natural Selection: In struggle of survival only those animals live who adapt them according to nature. If they are not able to do it, then they are destroyed.

4. Origin of new species: Inheritance of useful traits will continue from generation to generation and harmful traits gradually become extinct or remains as Vestigial organ. Sometimes, variations increase so that after new generation is more different from older generation and development of a new race goes. For example, at the beginning dog, jackal and wolves, three were members of the same race but due to change in atmosphere to adapt themselves accordingly, changes in their size and physical characteristics occurred, After thousands of years dog, fox and wolf, three new species were developed.

Question 3.
Explain a process of formation of fossils.
Answer:
Process of formation of fossils: Fossils are formed in a number of different ways, but most are formed when a plant or animal dies in a watery environment and is buried in mud and silt. Soft tissues quickly decompose leaving the hard bones or shells behind. Over time sediment builds over the top and hardens into rock. Not all animals are converted into fossils, only those can be converted which died at a place where they can be preserved.
RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 3

Intext Questions

Question 1.
When and how did life begin? (Page 63)
Answer:
Life originated on Earth about 3.5 billion years ago. Life originated as a result of very slow and gradual process. Initially, the atmosphere of earth was reducing. The conditions favorable for life were there at that time which are not present now. Some amino acids were formed as a result of some chemical reactions. Primary simple cell is formed by some combination of amino acids which gave rise to different individuals.

Question 2.
What were all the creatures from beginning same as they are today? (Page 63)
Answer:
No, all organisms were not the same as they are today. A lot of variations takes place from the very past till now and this gave rise to new species

Activity

Question 1.
Make a chart of organic evolution and fix in a class room.
Answer:
RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 4
Question 2.
Make a collage of vestigial organs.
Answer:
RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 5

Other Important Questions

Multiple Choice Questions
Question 1.
Most developed group is
(a) Pisces
(b) Aves
(c) Reptiles
(d) Mammals
Answer:
(d) Mammals

Question 2.
Which of the following is a pair of homologous organs?
(a) wings of bird – hands of man.
(b) wings of bat – wings of insects
(c) Wings of birds – wings of insects
(d) Flippers of whales – fins of fish
Answer:
(a) wings of bird – hands of man.

Question 3.
Which ofthe following is a pair of analogous organs?
(a) Wings of birds – wings of insects
(b) Hands of man – forelimb of horse
(c) Flippers of whales – wings of bat
(d) Wings of birds – flippers of whales
Answer:
(a) Wings of birds – wings of insects

Question 4.
The solid evidence of evolution is
(a) Vestigial organs
(b) Fossils
(c) Organic evolution
(d) Embryology
Answer:
(b) Fossils

Question 5.
Theory of Mutation was given by:
(a) Lamarck
(b) Darwin
(c) Hugo de Vries
(d) Heckle
Answer:
(c) Hugo de Vries

Question 6.
The principle oflnheritance of Acquired traits was given by:
(a) Darwin
(b) Lamarck
(c) Birbal Sahni
(d) Hugo de Vries
Answer:
(b) Lamarck

Fill in the Blanks
1. Pisces gave rise to ………………. group.
2. The remains of dead organisms found on rocks are called …………………
3. Generally, ……………….. is found in Vertebrates.
4. Giraffe is found only in …………….
5. ……………. gave Theory of Mutation.
Answer:
1. Reptiles
2. Fossils
3. Skeleton
4. Africa
5. Hugo de Vries

Very Short Answer Type Questions
Question 1.
How primitive protein formation took place on earth?
Answer:
The formation ofprimitive protein occurred as a result of chemical reaction between amino acids and carboxylic acid.

Question 2.
Explain Organic Evolution.
Answer:
Organic evolution refers to the slow and gradual process by which living organisms have changed from the simplest unicellular form to the most complex multi-cellular forms that are existing today.

Question 3.
Which type of organisms develop first on earth?
Answer:
Initially, unicellular organisms developed on Earth.

Question 4.
Write the name of one extinct animal.
Answer:
Dinosaur.

Question 5.
Write the name of two vestigial organs.
Answer:

  1. Tonsils
  2. Appendix.

Question 6.
What is the similarity between fish and a man on the basis of skeleton.
Answer:
In both of them, skeleton is made up of vertebrae.

Question 7.
What is the difference between fish and frog?
Answer:
Heart of a fish has two valves where as heart of a frog has three valves.

Question 8.
What is the basis of classification?
Answer:
In classification, the organisms having same characteristics are put in same group.

Question 9.
Write the name of one fossil.
Answer:
Archaeopteryx.

Question 10.
Write the name of an Indian PaleoBotanist?
Answer:
Professor Birbal Sahni.

Short Answer Type questions
Question 1 .
Write a short note on Organic evolution.
Answer:
On earth, firstly single celled organisms were formed. Then multicellular organisms were originated from them. Earlier, these were simple, but in gradual development became complicated. All animals were initially without a back bone. Fishes grew from them, by which amphibians were developed. From these evolved reptiles who ruled on the earth millions of years. Thereafter, some reptiles developed into birds and other in mammals. Animals from one class to another takes thousands of years to develop. Similarly, the evolution in plants also take place.

Question 2.
What are homologous organs? How do they prove organic evolution?
Answer:
Homologous organs maybe defined as the organs of different animals which have similar basic structure but different functions. For example, hands of man and wings of birds have different functions but their basic structure and origin is same. There are different organisms at different levejs which shows similarity in their structures. These also gives evidence for organic evolution.

Question 3.
Tabulate the function of forelimbs of some animals and their transformation.
Answer:

S.No. Name of animal Function of forelimbs Transformation into
1 Whale Swimming flippers
2 Birds Flying wings
3 Bat Flying wings
4 Man Holding things hands

Question 4.
What are Analogous organs? Which fact is proved by these organs?
Answer:
The wings of insects, bird.bat etc., help them in flying. There are differences in structure and origin of their wings. The origin of insect wings protrudes from the walls of the body while the origin of bird and bat’s wing is the modification of the forelimb. They have bones. Though the functions are similar, the origin and structure are different. Such organs are called Analogous organs. Animals with analogous organs developed in different classes in a different way.

Question 5.
What evidence is obtained about organic evolution by digestive systems of different animals?
Answer:
We can see that digestive tract of frog, birds, man etc., have a pharynx, stomach, small intestine. It includes liver, pancreas, digestive glands etc. Secretion of digestive juices and their function is also same. So this proves that these animals have evolved in a certain order.

Question 6.
How are skeleton of animals helpful in understanding organic evolution?
Answer:
Generally, skeleton is found in no to chord animals. They have back bone which is made up of small bones called vertebrae. The similarity in their bones of hands and leg and skeletal systems, shows that their ancestors would have been similar. Over the time, some differences appear due to change in conditions.

Question 7.
How does structure of heart represent order of evolution?
Answer:
Comparative study of hearts of fish, frog, snake and man shows that structure of fish is simplest of all and structure of human heart is more complex. This shows a certain order of evolution. The table represents the same as:

s.No. Animal Name Structure of heart
1. Fish Two chambers (One auricle and one ventricle)
2. Frog Three chambers (Two auricles and on ventricle)
3. Snake Two auricles and two incomplete ventricles
4. Human Four chambers (Two auricles and two ventricles)

Question 8.
How does study of embryo prove organic evolution? State Hackle’s principle on the basis of this.
Answer:
When we see fish, turtle, chicken, human embryo’s, early stages in them appears almost identical. This proves that the ancestors of all the vertebrates were almost identical. This proves that ancestors of all vertebrates resemble with fish and their development is certainly in order. Haeckel Theory: According to this theory, ” Every organism, in its development, repeats its organic history”. This theory is known as Theory of Recapitulation.

Question 9.
What do you understand by connecting link? Explain giving example.
Answer:
Those organisms which shows characteristics of two groups are called connecting links. For example, Archaeopteryx serves as a connecting link between reptiles and birds. This animal had some features like beak, wings, structure of legs etc similar to aves (bird) and some characteristics beak, tail, scales on body etc similar to reptiles.

Question 10.
What do you understand by Neo – Darwinism?
Answer:
Darwin added new approaches to his old doctrine and gave a new doctrine of neo – Darwinism. According to this, new species are originated due to gene variation into the members of the particular species. Only genetic variations are inherited and environmental characteristics ends when animal die.

Long Answer Type Questions
Question 1.
How does classification support organic evolution? Draw evolution tree for evidences from classification.
Answer:
Evidences from classification: All organisms have been classified on the basis of characteristics. These are arranged in a certain order. For example, protozoa is first and Chordates are last. Classification of animals from protozoa to Echinodermata is the gradual evolution of all animals. Similarly, Pisces, Amphibians, Reptiles, Aves and Mammals of chordate have many similarities such as in these vertebral column are hollow, Animals of class Pisces developed by non-chordates. The evolution takes place from simple to complex. It proves that all organisms evolved from a common ancestor like many branches originated from main stem of tree.
RBSE Solutions for Class 7 Science Chapter 7 Organic Evolution 6
Question 2.
What are Vestigial organs? Write the name of some vestigial organs. What evidence does vestigial organs show about evolution?
Answer:
Some organs are found in animals today which are present in the form of remains. But they were highly developed and functional in their ancestors. Examples are as follows:

S.No. Animals Vestigial organs
1. Human Muscles ear, nictating membrane, coudal vertebrae, Vermiform oppendix
2. Marine bottom fish less developed eyes
3. pythons (snake) Vestiges of the hind limbs
4. Kiwi and Ostrich Wings

Question 3.
How geographical distribution of organisms support organic evolution?
Answer:
Evidences from Geographical distribution: Now a days, variations are found in the geographical distribution of plants and animals. For example, Platypus. Kangaroo and Eucalyptus plant is found in Australia only. Similarly, Giraffe is found only in Africa. According to scientists at a time, the continents were connected to each other. Later on they were separated by the sea. That’s why animals and plants found in one continent could not reach to another continent Due to different circumstances structures of them are changed according to different places. The geographical distribution is therefore also certifies organic evolution.

Question 4.
Describe Theory of inheritance of acquired traits of Lamarck. Also explain limitations of this theory.
Answer:
This theory was given by Jean Baptiste Lamarck in 1809. His theory is known as Theory of Acquired traits. According to Lamarck due to changes in environment, more frequently used organ strengthened and organ that was less frequently used disappeared. Giraffes are found in Africa. It has long legs and neck. It lives by eating the leaves of tall trees. According to Lamarck ancestors of giraffe were not so tall. They could easily eat weeds. Gradually, due to changes in the environment, desert extended and grassland perished.

To get the leaves of the tress which were at height, legs and neck had to use more frequently. That’s why its legs and neck become too long. These traits are inherited from generation and generation. Snakes live in holes. Due to inconvenience legs were use less and gradually disappeared. Drawbacks of Lamarck: Some scientists denied the theory of Lamarck. They said,”if the tail of a mouse is cut generation to generation, there is no chance of birth of a mouse with out tail. In the same manner, girls do not take with a prick in their earlobe even after girls are having it from generations.

Question 5.
What is the theory of Mutation? Explain reasons and means of Mutation.
Answer:
Theory of Mutation: Hugo de Vries gave the theory of mutation. When he tested some plant, he found that some of the plants produced are quite different from their species. These traits are inherited from generation to generation. These sudden variations in inherited characters are called Mutation. Mutation in animals can be caused by the following:

  1. Change in number of genes
  2. Change in gene arrangement
  3. Change in gene structure.

Means of mutation: Mustard gas, Nitrous acid, Phenol, X – rays, Beta rays etc.

Question 6.
Write a short note on Birbal Sahni with explaining his contribution?
Answer:
Palaeobotanist who enchanted the world with interesting tidbits, Birbal Sahni was bom on November 14, 1891 at Bhera village, in the Shahpur District. He is the founder of Palaeobotanical research in India. Among st a large number of fossil plants described by him from Rajmahal Hills of Bihar, was his most remarkable discovery of a new group of fossils Gymnosperms, to which he gave the name ” Pentoxylae”. Sahni was greatly interested in archaeology and he published a number of papers in this filed. His work “on the Technique of Casting coins in the ancient India” set a new standard in archaeological research in India. He founded the institute of Paleobotany at Lucknow, which was later renamed as Birbal Sahni Institute of Paleobotany after his death.

We hope the RBSE Solutions for Class 8 Science Chapter 7 Organic Evolution will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Science Chapter 7 Organic Evolution, drop a comment below and we will get back to you at the earliest

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