RBSE Solutions for Class 7 Maths Chapter 14 Simple Equation Ex 14.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 14 Simple Equation Exercise 14.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Simple Equation |

Exercise |
Ex 14.1 |

Number of Questions |
1 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 14 Simple Equation Ex 14.1

Question

Solve the given below (RBSESolutions.com) equations and also verify the answer.

1. 2x + 1 = 9

2. 5x – 4 = 26

3. 5x – 2x + 7 = 31

4. 5x + 8 = 12 + 6

5. 12x + 3x = 60

6. \(\frac { 7x }{ 9 }\) = 21

7. \(\frac { 2x }{ 3 }\) – \(\frac { x }{ 2 }\) = 3

8. \(\frac { 3x }{ 4 }\) – \(\frac { 2x }{ 5 }\) = 7

9. \(\frac { 7x+1 }{ 2 }\) +1=11

10. \(\frac { 3l }{ 2 }\) = \(\frac { 2 }{ 3 }\)

11. 7m + \(\frac { 19 }{ 2 }\) = 13

12. 6z + 10 = -2

13. \(\frac { q }{ 4 }\) + 7 = 5

14. 4(2 – x) = 8

15. 3(n – 5) = 21

16. 4 = 5(t – 2)

17. 0 = 16+4(m – 6)

Solution:

**1. 2x + 1 = 9**

⇒ 2x = 9 – 1 = 8 (Shifting 1 to other side)

⇒ \(\frac { 2x }{ 2 }\) = \(\frac { 8 }{ 2 }\) ⇒ x = 4

Verifaction of answer LHS = 2x +1

= 2 x 4 + 1

= 8 + 1

= 9 = RHS

So, x = 4 is correct answer.

**2. 5x – 4 = 26**

⇒ 5x = 26 + 4 (Transferring side)

⇒ 5x = 30

⇒ \(\frac { 5x }{ 5 }\) = \(\frac { 30 }{ 5 }\) (दोनों पक्षों में 5 का भाग दने पर)

⇒ x = 6

Verifaction (RBSESolutions.com) of answer

LHS = 5x – 4

= 5 x 6 – 4 = 30 – 4

= 26 = RHS

so x = 6 is correct answer.

**3. 5x – 2x + 7 = 31**

3x + 7 = 31

⇒ 3x = 31 – 7 (Transferring side)

3x = 24

⇒ \(\frac { 3x }{ 3 }\) = \(\frac { 24 }{ 3 }\) (Dividing both sides by 3)

x = 8

Verifaction (RBSESolutions.com) of answer

LHS = 5x – 2x + 7

= 5 x 8 – 2 x 8 + 7

= 40 – 16 +7 = 31 = RHS

So x = 8 is correct answer.

**4. 5x + 8 = 12 + 6**

⇒ 5x = 18 – 8 = 10 (shifting 8 to other side)

⇒ \(\frac { 5x }{ 5 }\) = \(\frac { 10 }{ 5 }\)

(Dividing both sides by 5)

⇒ x = 2

Verifaction (RBSESolutions.com) of answer

LHS = 5x + 8

= 5 x 2 + 8 = 18

RHS = 12 + 6 = 18

So x = 2 is correct answer.

**5. 12x + 3x = 60**

⇒ 15 = 60

⇒ \(\frac { 15x }{ 15 }\) = \(\frac { 60 }{ 15 }\) = 4 (Dividing by 15 both sides)

⇒ x = 4

Verifaction (RBSESolutions.com) of answer

LHS = 12x + 3x = 15x

= 15 x 4 = 60 = RHS

So x = 4 is correct answer.

**12. 6z + 10 = -2**

⇒ 6z = -2 – 10

⇒ 6z = -12

z = – \(\frac { 12 }{ 6 }\) = -2

Verifaction of answer

LHS = 6z + 10

= 6 x (-2) + 10

= -12 + 10

= -2 = RHS

So z = -2 is correct (RBSESolutions.com) answer.

**13. \(\frac { q }{ 4 }\) + 7 = 5**

⇒ \(\frac { q }{ 4 }\) = 5 – 7 = -2

q = -2 x 4 = -8

Verifaction of answer

LHS = \(\frac { q }{ 4 }\) + 7 = \(\frac { -8 }{ 4 }\) + 7

= -2 +7 = 5 = RHS

So q = -8 is correct answer.

**14. 4(2 – x) = 8**

⇒ 2 – x = \(\frac { 8 }{ 4 }\)

⇒ 2 – x = 2

⇒ x = 2 – 2 = 0

Verifaction of answer

LHS = 4(2 – x)

= 4(2 – 0) = 8 = RHS

So x = 0 is correct answer.

**15. 3(n -5) = 21**

⇒ n – 5 = \(\frac { 21 }{ 3 }\) = 7

⇒ n = 7 + 5 = 12

Verifaction (RBSESolutions.com) of answer

LHS = 3(n – 5)

= 3(12 – 5) = 3(7)

= 21 = RHS

So n = 12 is correct answer.

**16. 4 = 5(t – 2)**

**17. 0 = 16 + 4(m – 6)**

⇒ 16 + 4(m – 6) = 0

⇒ 4(m – 6) = -16

⇒ m – 6 = \(\frac { -16 }{ 4 }\) = -4

⇒ m = -4 + 6 = 2

Verifaction (RBSESolutions.com) of answer

RHS = 16 + 4(m – 6)

= 16 + 4(2 – 6)

= 16 + 4(-4)

= 16 – 16 = 0 = LHS

So m = 2 is correct answer.

We hope the RBSE Solutions for Class 7 Maths Chapter 14 Simple Equation Ex 14.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 14 Simple Equation Exercise 14.1, drop a comment below and we will get back to you at the earliest.

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