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RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise

March 22, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise.

 

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 13
Chapter Name Comparison of Quantities
Exercise In Text Exercise
Number of Questions 8
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise

Page No: 147

Question 1.
Rashmi and Rehana picked flowers in basket from garden. In which there were 30% rose, 10% jasmine and rest were marigold. If there were 120 flowers in basket then
(i) What was the number of marigold flowers?
(ii) What was the number of jasmine flowers?
(iii) By what percentage were rose flowers less than jasmine flowers?
Solution:
(i) Percentage of marigold flowers
= 100% – (30% + 10%)
= 100% – 40%
= 60%
No. of marigold flowers = 120 x \(\frac { 60 }{ 100 }\) = 72
(ii) No. of jasmine flowers = 120 x \(\frac { 10 }{ 100 }\) = 12
(iii) Percentage of Rose flowers = 30%
Number of Rose(RBSESolutions.com)flowers = \(\frac { 30 }{ 100 }\) x 120 = 36
Number of Jasmine flowers = 12
Difference of number of rose and marigold flowers = 72 – 12 = 60
Hence, rose flowers were less than jasmine flowers by = \(\frac { 60 }{ 72 }\) x 100
= 83.33%

Page No: 150

RBSE Solutions

Question 2.
Reena obtained a bill of goods purchased from Khadi Bhandar. Looking at the bill answer the following questions.

Aazad Khadi Bhandar
Bill No. 1501
Sir………..
Date 5-10-2015
Goods/things Quantities Rate Amount
1. Bedsheets
2. kes
3. carpet
Total
4
4
2
.
80
120
200
.
320=00
480=00
400=00
1200=00
Subsidy 15% -180=00
1020=00
Vat 10% 102=00
One thousand one hundred and twenty two only 1122=00
Errors and omission expected                                              Signature

What is the mark up price of goods purchased?
—Subsidy is calculated on which price?
—VAT is calculated(RBSESolutions.com)on which price?
Solution:
The total marked price of purchased items = Rs 1200
—Subsidy is given at marked price.
—VAT is taken on the selling price.

RBSE Solutions

Question 3.
AS compared to Rs. 5000, Rs. 4000 are less by what percentage? Is that percentage similar to percentage by which Rs. 5000 are more than Rs. 4000?
Solution:
Let Rs 4,000 be the x% less than Rs 5,000. Then,
5,000 – (5,000 x \(\frac { x }{ 100 }\)) = 4,000
⇒ 5,000 x \(\frac { x }{ 100 }\) = 5,000 – 4,000
⇒ 50x = 1,000
⇒ \(x=\frac { 1000 }{ 50 }\)
⇒ x = 20
Hence Rs 4,000 is 20% less than the Rs 5,000.
Let Rs 5,000 be y% more as compared to 4,000. Then,
5,000 = 4,000 + 4,000 x \(\frac { y }{ 100 }\)
⇒ 5,000 – 4,000 = 40y
⇒ 1,000 = 40y
⇒ \(y=\frac { 1000 }{ 40 }\)
⇒ y = 25
Hence Rs 5,000 is 25% more as compared to Rs 4,000.

RBSE Solutions

Question 4.
Bank Pass Book

Date Particulars Credit Debit Balance
1.4.13 Cash 2000 – 2000
1.4.14 Interest 140 – 2140
1.4.15 Interest 149.80 – 2289.80

From entry of passbook tell—
—Interest is added after what period?
—How much interest is added for the first period?
—How much interest is added for the second period?
—Whether amount of interest is same for every year?
Solution:
Interest is credited after 1 year.
—Rs 140 is credited in first year.
—Rs 149.80 interest(RBSESolutions.com)is credited in 2nd year.
—No, interest is not same in each year.

Page No: 157

RBSE Solutions

Question 5.
Sandeep borrowed Rs. 3000 for 2 years at 8% annual compound interest rate from bank for establishing a biogas plant. If interest is accumulated annually then determine.
(i) What amount has to(RBSESolutions.com)be repaid with 8% annual compound interest rate?
(ii) How much Compound interest is there?
(iii) If this money was borrowed with simple interest then less or more interest was to be paid and how much?
Solution:
(i)
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise img-1
Hence, the amount to be paid is Rs 3,499.20.
(ii) Compound Interest = A – P
= 3,499.20 – 3,000
= Rs 499.20
(iii) Simple Interest
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise img-2
Therefore, if he borrowed money on simple interest, then he would pay Rs 19.20 less as compared to compound interest.

Page No: 158

RBSE Solutions

Question 6.
Complete the following blanks given in the table.

Condition of accumulation of interest Time in Years Annual Rate Transformation Period Transformed Rate
Annual 2 10% 2 10%
Half yearly 1½ 6% — 3%
Quarterly 1¼ 8% 5 —
Half yearly 2 14% 4 —
Annual 1 7% — —
Quarterly 6 months 16% — —

Solution:

Condition of accumulation of interest Time in Years Annual Rate Transformation Period Transformed Rate
Annual 2 10% 2 10%
Half yearly 1½ 6% 3 3%
Quarterly 1¼ 8% 5 2%
Half yearly 2 14% 4 7%
Annual 1 7% 1 7%
Quarterly 6 months 16% 2 4%

Page No: 163

Question 7.
Read following statements and find it is direct/inverse relation.

Statement Relation
1. A ladder is slipping by the side of wall height of top of ladder from bottom and distance from bottom to top of wall Inverse Relation
2. Between distance and time of car moving with uniform velocity.
3. Between number of persons and sufficiency of(RBSESolutions.com)food material in days (when quantity of food material is constant)
4. Between water and tank and population of village (when amount of water and its distribution is same)

Solution:

Statement Relation
1. A ladder is slipping by the side of wall height of top of ladder from bottom and distance from bottom to top of wall Inverse Relation
2. Between distance and time of car moving with uniform velocity. Direct Relation
3. Between number of persons and sufficiency of(RBSESolutions.com)food material in days (when quantity of food material is constant) Inverse Relation
4. Between water and tank and population of village (when amount of water and its distribution is same) Inverse Relation

RBSE Solutions

Question 8.
Think about such examples about direct and inverse relationship and discuss them with friends.
Solution:
Examples of direct relation –

  • Length of cloth and total price
  • No. of months and total salary
  • No. of hours of production and quantity of production.

Examples of Inverse Relation

  • No. of periods in a school and time of periods.
  • No. of workers and no. of hours to complete a work.
  • No. of production(RBSESolutions.com)machines and no. of necessary days to complete a production

We hope the given RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities In Text Exercise, drop a comment below and we will get back to you at the earliest.

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