RBSE Solutions for Class 8 Maths Chapter 15 Surface Area and Volume In Text Exercise is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 15 Surface Area and Volume In Text Exercise.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 8 |
| Subject | Maths |
| Chapter | Chapter 15 |
| Chapter Name | Surface Area and Volume |
| Exercise | In Text Exercise |
| Number of Questions | 9 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 8 Maths Chapter 15 Surface Area and Volume In Text Exercise
Page No: 180
Question 1.
If a cuboid is formed by sticking three cubes of side x then what will be the dimensions of cuboid.
Solution:
Position I
Length = 3x
Breadth = x
Height = x
Position II
Length = x
Breadth = x
Height = 3x
Page No: 181
Question 2.
Find out surface area of a cube having side 3 cm. What will be the(RBSESolutions.com)surface area of 5 such cubes?
Solution:
Surface area of cube of side 3 cm.
= 6 a²
= 6(3)²
= 54 cm.²
Surface area of 5 cubes
= 54 x 5
= 270 cm.²
Question 3.
What will be the total surface area of 5 cubes having side 3 cm.? If they are stocked one after one, then how much surface area will be decreased?
Solution:
Total surface area of 5 cubes each of 3 side = 270 cm² (See the solution of question 1)
If 5 cubes are joined one(RBSESolutions.com)after one, then it becomes a cuboid whose length (l)
= 3 cm. + 3 cm. + 3 cm. + 3 cm. + 3 cm.
= 15 cm.
Breadth (b) = 3 cm.
Height (h) = 3 cm.
∴ Surface Area= 2 (lb + bh + hl).
= 2 (15 x 3 + 3 x 3 + 3 x 15)
= 2 (45 + 9 + 45)
= 198 cm²
∴ Hence, surface area will be reduced and the difference = 270 cm.² – 198 cm.²
= 72 cm.²
Question 4.
Find out lateral surface area of the given cuboid.
Solution:
Here, l = 10 cm.
b = 4 cm.
h = 4 cm.
∴Lateral surface area of cuboid
= 2 (l + b) h
= 2 (10 + 4) 4
= 112 cm.²
Page No: 182
Question 5.
Determine total surface area(RBSESolutions.com)of following cylinders
Solution:
(i) Here, r = [latex]\frac { 7 }{ 2 }[/latex]
h = 10 cm
∴ Total surface are of cylinder
= 2πr (h + r)
Page No: 186
Question 6.
By arranging cubes of unit length And volume of cuboid so obtained
Solution:
Page No: 187
Question 7.
Find volume of cuboid(RBSESolutions.com)on basis of given measures –
Solution:
(i) Here, l = 8 cm.
b = 3 cm.
h = 2 cm.
∴ Volume of cuboid
= l x b x h
= 8 x 3 x 2
= 48 cm.³
(ii) Here, l = 1 cm.
b = 1 cm.
h = 7 cm.
∴ Volume of cuboid
= l x b x h
= 1 x 1 x 7
= 7 cm³
Page No: 187
Question 8.
Solution
Page No: 188
Question 9.
Determine volume(RBSESolutions.com)of the cube having side
(i) 1.5 cm
(ii) 4 m
Solution:
(i) 1.5 cm
Here, a = 1.5 cm
∴ Volume of cube = a³
= (1.5)³
= 1.5 x 1.5 x 1.5
= 3.375 cm³
(ii) 4 cm
Here, a = 4 cm
∴ Volume of cube = a³
= (4)³
= 4 x 4 x 4
= 64 cm³
We hope the given RBSE Solutions for Class 8 Maths Chapter 15 Surface Area and Volume In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 15 Surface Area and Volume In Text Exercise, drop a comment below and we will get back to you at the earliest.
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