RBSE Solutions for Class 8 Maths Chapter 16 Data Handling Ex 16.3

RBSE Solutions for Class 8 Maths Chapter 16 Data Handling Ex 16.3 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 16 Data Handling Exercise 16.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 16
Chapter Name	Data Handling
Exercise	Exercise 16.3
Number of Questions	5
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 16 Data Handling Ex 16.3

Question 1.
What is the probability of getting head on throwing a coin?
Solution
Probability of getting head

Question 2.
There are 6 white, 11 red and 7 yellow balls in a bag. What is the probability of getting a white ball from the bag?
Solution
Total balls = 6 + 11 + 7 = 24
No. of white balls = 6
∴Probability of getting white ball from, the bag

Question 3.
What is the probability of getting a queen from a pack of well- shuffled cards?
Solution
Total No. of cards = 52
Total No. of queens = 4
∴Probability of getting queen

Question 4.
Find the probability of each below mentioned event when a dice is thrown
(i) A prime number
(ii) No prime number
(iii) number(RBSESolutions.com)more than 3
(iv) Number not more than 5
(v) An odd number.
Solution:
Total number of outcomes when a dice is thrown
= 6 (1, 2, 3, 4, 5, 6)
(i) Total number of favorable outcomes
= 3 (2, 3, 5)
∴Required Probability \(=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \)
(ii) Total number of favorable outcomes
= 3 (1, 4, 6)
∴Required Probability \(=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \)
(iii) Total number(RBSESolutions.com)of favorable outcomes
= 3 (4, 5, 6)
∴Required Probability \(=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \)
(iv) Total number of favorable outcomes
= 5 (1, 2, 3, 4, 5)
∴Required Probability = \(\frac { 5 }{ 6 }\)
(v) Total number of favorable outcomes
= 3 (1, 3, 5)
∴Required Probability \(=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \)

Question 5.
Number from 1 to 15 is written on 15 different slips (one number on each slip). They are mixed keeping in box. A slip is taken out without looking into box. What is the probability of following?
(i) Obtaining number 5.
(ii) Obtaining(RBSESolutions.com)a number having two digits.
(iii) Obtaining a number having one digit.
Solution
Total no. of slips = 15
∴Total number of outcomes = 15
(i) Total number of favorable events = 1 (5)
∴Required Probability = \(\frac { 1 }{ 15 }\)
(ii) Total number of favorable events = 6 (10, 11, 12, 13, 14, 15)
∴Required Probability \(=\frac { 6 }{ 15 } =\frac { 2 }{ 5 } \)
(iii) Total(RBSESolutions.com)number of favorable events = 9 (1, 2, 3, 4, 5, 6, 7, 8, 9
∴Required Probability \(=\frac { 9 }{ 15 } =\frac { 3 }{ 5 } \)

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