RBSE Solutions for Class 8 Maths Chapter 16 Data Handling Ex 16.3 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 16 Data Handling Exercise 16.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 16 |

Chapter Name |
Data Handling |

Exercise |
Exercise 16.3 |

Number of Questions |
5 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 8 Maths Chapter 16 Data Handling Ex 16.3

Question 1.

What is the probability of getting head on throwing a coin?

Solution

Probability of getting head

Question 2.

There are 6 white, 11 red and 7 yellow balls in a bag. What is the probability of getting a white ball from the bag?

Solution

Total balls = 6 + 11 + 7 = 24

No. of white balls = 6

∴Probability of getting white ball from, the bag

Question 3.

What is the probability of getting a queen from a pack of well- shuffled cards?

Solution

Total No. of cards = 52

Total No. of queens = 4

∴Probability of getting queen

Question 4.

Find the probability of each below mentioned event when a dice is thrown

(i) A prime number

(ii) No prime number

(iii) number(RBSESolutions.com)more than 3

(iv) Number not more than 5

(v) An odd number.

Solution:

Total number of outcomes when a dice is thrown

= 6 (1, 2, 3, 4, 5, 6)

(i) Total number of favorable outcomes

= 3 (2, 3, 5)

∴Required Probability [latex]=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } [/latex]

(ii) Total number of favorable outcomes

= 3 (1, 4, 6)

∴Required Probability [latex]=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } [/latex]

(iii) Total number(RBSESolutions.com)of favorable outcomes

= 3 (4, 5, 6)

∴Required Probability [latex]=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } [/latex]

(iv) Total number of favorable outcomes

= 5 (1, 2, 3, 4, 5)

∴Required Probability = [latex]\frac { 5 }{ 6 }[/latex]

(v) Total number of favorable outcomes

= 3 (1, 3, 5)

∴Required Probability [latex]=\frac { 3 }{ 6 } =\frac { 1 }{ 2 } [/latex]

Question 5.

Number from 1 to 15 is written on 15 different slips (one number on each slip). They are mixed keeping in box. A slip is taken out without looking into box. What is the probability of following?

(i) Obtaining number 5.

(ii) Obtaining(RBSESolutions.com)a number having two digits.

(iii) Obtaining a number having one digit.

Solution

Total no. of slips = 15

∴Total number of outcomes = 15

(i) Total number of favorable events = 1 (5)

∴Required Probability = [latex]\frac { 1 }{ 15 }[/latex]

(ii) Total number of favorable events = 6 (10, 11, 12, 13, 14, 15)

∴Required Probability [latex]=\frac { 6 }{ 15 } =\frac { 2 }{ 5 } [/latex]

(iii) Total(RBSESolutions.com)number of favorable events = 9 (1, 2, 3, 4, 5, 6, 7, 8, 9

∴Required Probability [latex]=\frac { 9 }{ 15 } =\frac { 3 }{ 5 } [/latex]

We hope the given RBSE Solutions for Class 8 Maths Chapter 16 Data Handling Ex 16.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 16 Data Handling Exercise 16.3, drop a comment below and we will get back to you at the earliest.

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