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RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1

June 3, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1

RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Exercise 6.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 6
Subject Maths
Chapter Chapter 6
Chapter Name Decimal Numbers
Exercise Ex 6.1
Number of Questions 10
Category RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1

Question 1.
Write the numbers for the following (RBSESolutions.com) in the table given below :
(i) 1 tens 2 unit 3 one-tenths
(ii) 1 hundred 3 tens 7 one-tenths
(iii) 2 hundred 5 tens 1 unit 2 one-tenths
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 1
Solution.
On writting numbers in the table :
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 2

RBSE Solutions

Question 2.
Write the place value of following (RBSESolutions.com) decimal numbers in a table.
(i) 19.4
(ii) 0.5
(iii) 10.9
(iv) 205.9
Solution.
On writing the place value of decimal numbers in a table :
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 3

What is 11/16 as a decimal you ask? Converting the fraction 11/16 into a decimal is very easy.

Question 3.
Write each of the following (RBSESolutions.com) in the form of decimal :
(i) 7 one-tenths
(ii) 2 tens 4 one-tenths
(iii) Fourteen decimal nine
(iv) Six hundred point three
Solution.
On writing each in decimal form :
(i) 7 one-tenths = \(\frac { 7 }{ 10 } \) = 0.7
(ii) 2 tens 4 one-tenths 2 tens = 2 × 10 = 20
4 one-tenths = \(\frac { 4 }{ 10 } \) = 0.4
∴ 2 tens 4 one-tenths = 20.4
(iii) Fourteen point Nine = 14.9
(iv) Six hundred point three = 600.3

Question 4.
Represent the following in (RBSESolutions.com) form of decimal fractions :
(i) \(\frac { 3 }{ 10 } \)
(ii) 4 + \(\frac { 8 }{ 10 } \)
(iii) 300 + 50 + 8 + \(\frac { 1 }{ 10 } \)
(iv) 90 + \(\frac { 3 }{ 10 } \)
(v) \(\frac { 3 }{ 2 } \)
(vi) \(\frac { 2 }{ 5 } \)
(vii) 4 \(\frac { 1 }{ 2 } \)
(viii) 3 \(\frac { 3 }{ 5 } \)
Solution.
On representing each in form (RBSESolutions.com) of decimal fractions :
(i) \(\frac { 3 }{ 10 } \) = 0.3
(ii) 4 + \(\frac { 8 }{ 10 } \) = 4 + 0.8 = 4.8
(iii) 300 + 50 + 8 + \(\frac { 1 }{ 10 } \) = 358 + 0.1 = 358.1
(iv) 90 + \(\frac { 3 }{ 10 } \) = 90 + 0.3 = 90.3
(v) \(\frac { 3 }{ 2 } \) for making its denominator 10, multiply its numerator and denominator by 5 :
\(\frac { 3 }{ 2 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 15 }{ 10 } \) = 1.5
(vi) \(\frac { 2 }{ 5 } \) for making its denominator 10, multiply its numerator and denominator by 2 :
\(\frac { 2 }{ 5 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 4 }{ 10 } \) = 0.4
(vii) 4 \(\frac { 1 }{ 2 } \) = \(\frac { 9 }{ 2 } \)
for making its denominator 10, multiply its numerator and denominator by 5 :
\(\frac { 9 }{ 2 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 45 }{ 10 } \) = 4.5
(viii) 3 \(\frac { 3 }{ 5 } \) = \(\frac { 18 }{ 5 } \)
for making its denominator 10, multiply its numerator and denominator by 2 :
\(\frac { 18 }{ 5 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 36 }{ 10 } \) = 3.6

Question 5.
Write fractions for the following decimal (RBSESolutions.com) numbers and convert in the simplest form.
(i) 0.6
(ii) 2.5
(iii) 2.8
(iv) 13.7
(v) 21.2
(vi) 1.0
(vii) 6.4
Solution.
On writing decimal numbers as fractions and (RBSESolutions.com) converting them in simplest form :
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 4

RBSE Solutions

Question 6.
Using centimeters convert the (RBSESolutions.com) following into decimal form :
(i) 2 mm
(ii) 30 mm
(iii) 116 mm
(iv) 5 cm 2 mm
(v) 95 mm
(vi) 19 cm 1 mm
Solution.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 5

Question 7.
On the number line between which two whole (RBSESolutions.com) numbers, the following numbers are marked? Which whole number of these is closer to the decimal number?
(i) 0.5
(ii) 5.3
(iii) 9.0
(iv) 4.9
(v) 3.8
Solution.
On checking given each decimal number on number line :
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 6
∵ 0.5 is equally near from 0 and 1, but we let it closer to 1, because (RBSESolutions.com) when last point of number is 5 or more than 5, then it will be closer to next number.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 7

Questions 8.
Show the following (RBSESolutions.com) on number line.
(i) 0.3
(ii) 1.7
(iii) 3.4
(iv) 2.5
Solution.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 image 8

RBSE Solutions

Question 9.
The length of Tulsi’s hand grip is 95 m.m. Write (RBSESolutions.com) it in cm form.
Solution.
The length of Tulsi’s hand grip = 95 mm
∵ 10 mm = 1 cm
∴ 95 mm = \(\frac { 1 }{ 10 } \) × 95 cm = \(\frac { 95 }{ 10 } \) = 9.5 cm
Thus, length of Tulsi’s hand grip is 9.5 cm

Question 10.
Deepu has a 6 cm. scale. It has been broken at 4.4 cm. What is the length of the left piece of scale?
Solution.
Total length of scale = 6 cm
Length of broken scale = 4.4 cm Thus, length (RBSESolutions.com) of remaining scale = (6 – 4.4) cm = (6.0 – 4.4) cm = 1.6 cm

We hope the RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers Ex 6.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers Exercise 6.1, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise

June 3, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 6
Subject Maths
Chapter Chapter 6
Chapter Name Decimal Numbers
Exercise In Text Exercise
Number of Questions 11
Category RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise

Page No. 75

Question 1.
You too measure pencil, rubber and other things (RBSESolutions.com) from your bag by scale and fill in the table.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 1
Solution.
Fill the table as below –
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 2
Note : Students measure their own objects.

(Page No. 76)

RBSE Solutions

Question 2.
Write the place value of digits (RBSESolutions.com) in the following number.
(i) 123.4
(ii) 111
Solution.
(i) Place value of 1 = 1 × 100 = 100
Place value of 2 = 2 × 10 = 20
Place value of 3 = 3 × 1 = 3
Place value of 4 = 4 × \(\frac { 1 }{ 10 } \) = 0.4

(ii) Place value of 1 = 1 × 100 = 100
Place value of 1 = 1 × 10 = 10
Place value of 1 = 1 × 1 = 1

ROUND returns n rounded to integer places to the right of the decimal point. … The following example rounds a number to one decimal point.

Page No. 76

Question 1.
Show the decimal (RBSESolutions.com) numbers 0.6, 1.3 and 2.5 on number line.
Solution.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 3

Page No. 81

Question 1
Which number is greater in the following?
(i) 3.07 and 3.89
(ii) 0.57 and 0.05
(iii) 147.8 and 147.08
(iv) 9.5 and 5.92
Solution.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 4
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 5
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 6

Page No. 82

Question 1.
Add the (RBSESolutions.com) following.
(i) 1.54 + 1.80
(ii) 2.75 + 0.08
Solution.
(i) 1.54 + 1.80
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 7
(ii) 2.75 + 0.08
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 8

RBSE Solutions

Here we will write the mixed fraction 1 1/2 as a decimal.

Question 2.
(i) Subtract (RBSESolutions.com) 1.67 from 5.47.
(ii) Subtract 4.07 from 8.90.
Solution.
(i) 5.47 – 1.65
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 9
(ii) 8.90 – 4.07
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 10

Page No. 74

Question 1.
Say how much is length (RBSESolutions.com) of the Ram’s pencil?
Solution.
Length of pencil in figure is more than 6 cm and less than 7 cm. Now, on making 10 equal parts of 1 cm, we find that length of pencil is 1 part more them 6 cm. Thus, length of pencil is 6.1 cm.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 11

Question 2.
How much is the length of Rehman’s compass?
Solution.
Length of compass in figure is more than 5 cm and less than 6 cm. Now, on making 10 equal parts of 1 cm, we find that length of compass is 4 part more than 5 cm. Thus, length of compass is 5.4 cm.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 12

Page No. 75

Question 1.
Find the place value of (RBSESolutions.com) digits of number 523.
Place value of 5 = …………………………….
Place value of 2 = …………………………….
Place value of 3 = …………………………….
Solution.
Following are the place values of digits of number 523.
Place value of 5 = 5 × 100 = 500
Place value of 2 = 2 × 10 = 20
Place value of 3 = 3 × 1 = 3

Question 2.
Fill the following (RBSESolutions.com) table.
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 13
Solution.
Completing the table :
RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise image 14

RBSE Solutions

Page No. 79

Question 1.
Write the following (RBSESolutions.com) numbers in words :
1. 45.36 cm =
2. ₹ 325.25 =
Solution.
On writing the given decimal number in words :
1. 45.36 cm – Forty five decimal three six c.m.
2. ₹ 325.25 – Three hundred twenty five decimal two five

We hope the RBSE Solutions for Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 6 Decimal Numbers In Text Exercise, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.1

June 2, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 1 Numbers Exercise 1.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 5
Subject Maths
Chapter Chapter 1
Chapter Name Numbers
Exercise Ex 1.1
Number of Questions 7
Category RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Chapter 1 Numbers Ex 1.1

1. Write the following numbers in wrods-
(i) 24056
(ii) 40009
(iii) 99999
(iv) 80511
(v) 67725
Solution.
(i) 24056 Twenty four thousand fifty six
(ii) 40009 Forty thousand nine
(iii) 99999 Ninety nine(RBSESolutions.com)thousand nine hundred ninety nine
(iv) 80511 Eighty thousand five hundred eleven
(v) 67725 Sixty seven thousand seven hundred twenty five

Question 2.
Write the expanded form of following numbers –
(i) 12372
(ii) 23434
(iii) 45302
(iv) 75004
(v) 68877
Solution.
(i) 12372 = 10000 + 2000 + 300 + 70 + 2
(ii) 23434 = 20000 + 3000 + 400 + 30 + 4
(iii) 45302 = 40000 + 5000 + 300 + 00 + 2
(iv) 75004 = 70000 + 5000 + 000 + 00 + 4
(v) 68877 = 60000 + 8000 + 800 + 70 + 7

RBSE Solutions

Question 3.
Write the equivalent numbers of following expanded forms –
(i) 40000 + 5000 + 700 + 70 + 2
(ii) 60000 + 0000 + 000 + 20 + 6
(iii) 30000 + 9000 + 900 + 00 + 8
(iv) 50000 + 2000 + 800 + 10 + 1
(v) 80000 + 0000 + 000 + 00 + 8
Solution.
(i) 40000 + 5000 + 700 + 70 + 2 = 45772
(ii) 60000 + 0000 + 000 + 20 + 6 = 60026
(iii) 30000 + 9000 + 900 + 00 + 8 = 39908
(iv) 50000 + 2000 + 800 + 10 + 1 = 52811
(v) 80000 + 0000 + 000 + 00 + 8 = 80008

RBSE Solutions

For larger numbers, it is easier to use exponents for the place values. Example B: … The 4 is in the thousandths place, so multiplying by 10-3 (1/1000).

Question 4.
Find out the place(RBSESolutions.com)value of 6 and 2 in the following numbers –
(i) 28506
(ii) 36265
(iii) 52266
(iv) 69242
(v) 82563
Solution.
(i) 28506 in
Place value of 6 = 6
Place value of 2 = 20000

(ii) 36265 in
Place value of 6 = 6000
Again Place value of 6 = 60
Place value of 2 = 200

(iii) 52266 in
Place value of 6 = 60
Again Place value of 6 = 6
Place value of2 = 2000
Again Place value of = 200

RBSE Solutions

(iv) 69242 in
Place value of 6 = 60000
Place value of 2 = 200
AgainPlance value of 2 = 2

(v) 82563 in
Place value of 6 = 60
Place value of 2 = 2000

Question 5.
Mark the right symbol (<, >, =) between the given numbers
(i) 2979 ………….. 2932
(ii) 5423 ………….. 5432
(iii) 8952 ………….. 8952
(iv) 6850 ………….. 6852
(v) 3675 ………….. 3675
(vi) 9821 ………….. 9799
Solution.
(i) 2979 > 2932
(ii) 5423 < 5432
(iii) 8952 = 8952
(iv) 6850 < 6852
(v) 3675 = 3675
(vi) 9821 > 9799

RBSE Solutions

Question 6.
Write the following(RBSESolutions.com)numbers in ascending order –
(i) 26886, 37725, 30840, 25975, 40021
(ii) 59307, 53907, 59703, 57039, 57903
(iii) 74443, 74434, 74344, 77444, 77555
Solution.
(i) 25975, 26886, 30840, 37725, 40021
(ii) 53907, 57039, 57903, 59307, 59703
(iii) 74344, 74434, 74443, 77444, 77555

Question 7.
Write the following numbers in descending order-
(i) 41525, 51425, 34152, 42325, 50925
(ii) 86067, 81316, 85032, 82511, 81154
(iii) 76543, 73456, 74356, 76435, 74653
Solution.
(i) 51425, 50925, 42325, 41525, 34152
(ii) 86067, 85032, 82511, 81316, 81154
(iii) 76543, 76435, 74653, 74356, 73456

RBSE Solutions

We hope the RBSE Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 1 Numbers Exercise 1.1, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3

June 2, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Exercise 1.3.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 6
Subject Maths
Chapter Chapter 1
Chapter Name Know the Numbers
Exercise Ex 1.3
Number of Questions 5
Category RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Ex 1.3

Question 1.
Replace each number to the (RBSESolutions.com) nearest hundred of the following and calculate the answer again in the nearest hundred.
(i) 247 + 691
(ii) 4316 + 1567
(iii) 7122 – 3565
(iv) 4543 – 2036
Solution.
(i) 247 + 691
Tens place digit in 247 = 4 < 5 Rounding off 247 to nearest hundred = 200
Tens place digit in number 691 = 9 > 5
Digit of hundred =6 + 1 = 7
Roudning off 691 to nearest = 700
Thus, 200 + 700 = 900

RBSE Solutions

(ii) 4316 + 1567
Tens place digit in 4316 = 1 < 5 Rounding off 4316 to (RBSESolutions.com) nearest hundred = 4300
Tens place digit in 1567 = 6 > 5
Digit of hundred =5 + 1=6
Rounding off 1567 to nearest hundred = 1600
Thus, 4300 + 1600 = 5900

(iii) 7122 – 3565
Tens digit in 7122 = 2 < 5 Rounding off 7122 to nearest hundred = 7100
Tens place digit in 3565 = 6 > 5
Digit of hundred =5 + 1 = 6 Rounding off 3565 to nearest hundred = 3600
Thus, 7100 – 3600 = 3500

(iv) 4543 – 2036
Tens place digit in 4543 = 4 < 5 Rounding off 4543 to nearest (RBSESolutions.com) hundred = 4500
Rounding off 2036 to nearest hundred = 3 < 5
Rounding off 2036 to nearest hundred = 2000
Thus, 4500 – 2000 = 2500

Question 2.
Multiply the nearest tens numbers of the following :
(i) 34 × 57
(ii) 294 × 72
(iii) 869 × 675
Solution.
(i) 34 × 57
Rounding off 34 to (RBSESolutions.com) nearest tens = 30
Rounding off 57 to nearest tens = 60
Thus, 30 × 60 = 1,800

(ii) 294 x 72
Rounding off 294 to nearest tens = 290
Rounding off 72 to nearest tens = 70
Thus, 290 × 70 = 20,300

(iii) 869 × 675
Rouding off 869 to nearest tens = 870
Rounding off 675 to nearest tens = 680
Thus, 870 × 680 = 5,91,600

Rounding to the Nearest Hundredth … The hundredth place is the second number after the decimal.

Question 3.
In the school library, there are 2541 books of stories, 1017 subject books (RBSESolutions.com) and other books are 857. Find out the approximate number of books in the school. (Rounding the number to 100).
Solution.
Number of story books = 2541
Round off 2541 = 2500
Number of subject books = 1017
Round off 1017 = 1000
Other books = 857
Round off 857 to nearest hundred = 900
Thus, total books = 2500 + 1000 + 900 = 4400

Question 4.
8596 cows and 7015 buffaloes are there (RBSESolutions.com) in a village. Find out which cattle is more than the other and how much ? (Rounding the number to 100).
Solution.
Number of cows = 8596
Round off 8596 to nearest hundred = 8600
Number of buffaloes = 7015
Round off 7015 to nearest hundred = 7000
Difference = 8600 – 7000 = 1600
Thus, cows are more than others, approximately 1600.

Question 5.
A car runs 15 kilometer with 1 litre petrol. How (RBSESolutions.com) much petrol does it need to go 100 kms ? (Find out the value rounding the number to 10).
Solution.
Petrol need to ran 15 litre = 1 litre
Petrol need to run 1 km = \(\frac { 1 }{ 15 } \) litre
Petrol need to run 100 km
\(=\frac { 1\times 100 }{ 15 } =6.67=7\) litre (approx)

RBSE Solutions

We hope the RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Exercise 1.3, drop a comment below and we will get back to you at the earliest.

RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise

June 2, 2022 by Fazal Leave a Comment

RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 5
Subject Maths
Chapter Chapter 2
Chapter Name Addition and Subtraction
Exercise In Text Exercise
Number of Questions 14
Category RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise

Page No. 7

Solve :
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 1

Question 6.
580 + 27 + 306 = …………
Solution.
9133

RBSE Solutions

1/32 to Decimals are a set of numbers lying between integers on a number line.

Question 7.
473 – 296 = …………
Solution.
177

Question 8.
364+67 – 199 = 431 – 199 = …………
Solution.
232

Question 9.
37 – 15 + 10 = 47 – 15 = …………
Solution.
32

RBSE Solutions

Question 10.
185 boys and 162 girls are studying in Government(RBSESolutions.com)Higher Secondary School, Udliyas. What is the total number of students studying ¡n this school?
Solution.
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 2

Question 11.
In a garden 255 roses, 156 marigold, 178 Jasmine(RBSESolutions.com)plants are there. What is the total number of flowering plants ?
Solution.
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 3

RBSE Solutions

Question 12.
Gita’s father is at the mart to sell pots. This(RBSESolutions.com)time her father built 523 pots, of which 484 were sold out. Then how many pots are left unsold ?
Solution.
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 4

Question 13.
Do addition and(RBSESolutions.com)subtraction with Indian numbers.
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 5
Solution:
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 6

RBSE Solutions

Page No. 8

Practice
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 7
Solution.
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 8
RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise image 9

RBSE Solutions

We hope the RBSE Solutions for Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 2 Addition and Subtraction In Text Exercise , drop a comment below and we will get back to you at the earliest.

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