RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Exercise 1.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 1 |

Chapter Name |
Know the Numbers |

Exercise |
Ex 1.3 |

Number of Questions |
5 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Ex 1.3

Question 1.

Replace each number to the (RBSESolutions.com) nearest hundred of the following and calculate the answer again in the nearest hundred.

(i) 247 + 691

(ii) 4316 + 1567

(iii) 7122 – 3565

(iv) 4543 – 2036

Solution.

(i) 247 + 691

Tens place digit in 247 = 4 < 5 Rounding off 247 to nearest hundred = 200

Tens place digit in number 691 = 9 > 5

Digit of hundred =6 + 1 = 7

Roudning off 691 to nearest = 700

Thus, 200 + 700 = 900

(ii) 4316 + 1567

Tens place digit in 4316 = 1 < 5 Rounding off 4316 to (RBSESolutions.com) nearest hundred = 4300

Tens place digit in 1567 = 6 > 5

Digit of hundred =5 + 1=6

Rounding off 1567 to nearest hundred = 1600

Thus, 4300 + 1600 = 5900

(iii) 7122 – 3565

Tens digit in 7122 = 2 < 5 Rounding off 7122 to nearest hundred = 7100

Tens place digit in 3565 = 6 > 5

Digit of hundred =5 + 1 = 6 Rounding off 3565 to nearest hundred = 3600

Thus, 7100 – 3600 = 3500

(iv) 4543 – 2036

Tens place digit in 4543 = 4 < 5 Rounding off 4543 to nearest (RBSESolutions.com) hundred = 4500

Rounding off 2036 to nearest hundred = 3 < 5

Rounding off 2036 to nearest hundred = 2000

Thus, 4500 – 2000 = 2500

Question 2.

Multiply the nearest tens numbers of the following :

(i) 34 × 57

(ii) 294 × 72

(iii) 869 × 675

Solution.

(i) 34 × 57

Rounding off 34 to (RBSESolutions.com) nearest tens = 30

Rounding off 57 to nearest tens = 60

Thus, 30 × 60 = 1,800

(ii) 294 x 72

Rounding off 294 to nearest tens = 290

Rounding off 72 to nearest tens = 70

Thus, 290 × 70 = 20,300

(iii) 869 × 675

Rouding off 869 to nearest tens = 870

Rounding off 675 to nearest tens = 680

Thus, 870 × 680 = 5,91,600

Rounding to the Nearest Hundredth … The hundredth place is the second number after the decimal.

Question 3.

In the school library, there are 2541 books of stories, 1017 subject books (RBSESolutions.com) and other books are 857. Find out the approximate number of books in the school. (Rounding the number to 100).

Solution.

Number of story books = 2541

Round off 2541 = 2500

Number of subject books = 1017

Round off 1017 = 1000

Other books = 857

Round off 857 to nearest hundred = 900

Thus, total books = 2500 + 1000 + 900 = 4400

Question 4.

8596 cows and 7015 buffaloes are there (RBSESolutions.com) in a village. Find out which cattle is more than the other and how much ? (Rounding the number to 100).

Solution.

Number of cows = 8596

Round off 8596 to nearest hundred = 8600

Number of buffaloes = 7015

Round off 7015 to nearest hundred = 7000

Difference = 8600 – 7000 = 1600

Thus, cows are more than others, approximately 1600.

Question 5.

A car runs 15 kilometer with 1 litre petrol. How (RBSESolutions.com) much petrol does it need to go 100 kms ? (Find out the value rounding the number to 10).

Solution.

Petrol need to ran 15 litre = 1 litre

Petrol need to run 1 km = \(\frac { 1 }{ 15 } \) litre

Petrol need to run 100 km

\(=\frac { 1\times 100 }{ 15 } =6.67=7\) litre (approx)

We hope the RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Exercise 1.3, drop a comment below and we will get back to you at the earliest.